File open in java

Question

I have created a small application to upload any file and save it in a temporary directory.
Then display all the file names which are in that directory.here's my code ....
MultipartRequest mr = null;
               try {
                    mr = new MultipartRequest(req, ".");                              
                    BufferedReader br = new BufferedReader(new FileReader(fileName = (String)mr.getFilesystemName("importFile")));
               } catch(Exception e) { System.out.println("Error uploading from file '"+fileName+"': "+e); e.printStackTrace();
               } finally { new File(fileName).delete(); }
               String dir = "C:\\asta-timesheet\\temp\\";
               Vector fileVector = new Vector();
               boolean result = false;
               DataInputStream dis;
               FileInputStream fin;
               try {               
                    String fileContent = "";
                    Enumeration files = mr.getFileNames();
                    String name = (String)files.nextElement();
                    String filename = mr.getFilesystemName(name);
                    String type = mr.getContentType(name);
                    File f = mr.getFile(name);
                    FileReader fs = new FileReader(f);
                    BufferedReader in = new BufferedReader(fs);
                    String s, s2 = new String();
                    while((s = in.readLine())!= null) {
                    s2 += s + "\n";
                    fileContent = s2;     
                    in.close();                                                                 
               File file = new File(dir, fileName);           
     // Create file if it does not exist
     boolean success = file.createNewFile();
     if (success) {              
                         InputStream inn = new FileInputStream(f);
               OutputStream out = new FileOutputStream(file);
               // Transfer bytes from in to out
                    byte[] buf = new byte[1024];
                    int len;
               while ((len = inn.read(buf)) > 0) {
               out.write(buf, 0, len);
               inn.close();
               out.close();
     } else {
     // File already exists     
     req.setAttribute("fileStatus", "exists");
          } catch(Exception e) { System.out.println("Error uploading from file '"+fileName+"': "+e); e.printStackTrace();}
               File dirr = new File(dir);
          String[] children = dirr.list();
          if (children == null) {
          } else {
          for (int i=0; i<children.length; i++) {                    
          String filename = children;
          // The list of files can also be retrieved as File objects
          File[] files = dirr.listFiles();
          for (int i = 0; i < files.length; i++) {
                    File f = files[i];                                                                           
               req.setAttribute("fileVector", files);                    
          return returnPage;
I need help with opening up the listed files.i.e if its a word doc.i need it to be open on ms word.I have file types like excel,jpg,txt....Can someone pls explain or provide code for this.
thx in advance.

Answer 1

All you could use to detect the correct type would be the extension which might or might not be accurate. We'll assume for a moment that the extensions will be accurate. What you need to look into running native code. Follow the bouncing link.
http://www.google.com/search?hl=en&q=Java+%2B+native+code&btnG=Google+Search
Hope this helps,
PS.
One more thing, please use code tags when you're posting code, it makes it much easier to read.
Message was edited by:
puckstopper31