Find and Replace String in a Column

Hi,
In the table data got stored with " " (Double Quotes) I need to remove these double quotes Please suggest me how to remove
Select address from TECH_SOURCING_EMPLOYEE_DETAILS
"No 12/32" ---> data been saved in this format in the table. I need to remove the double quotes
Thanks
Sudhir

Hi,
Use UPDATE to change existing rows in a table
Use REPLACE to remove a given sub-qtring from a string.
UPDATE     tech_sourcing_employee_details
SET     address     = REPLACE (address, '"')
WHERE     INSTR (address, '"')         > 0          -- Maybe
;This will remove all double-quotes from address.
If you want to remove double-quotes only from the very beginning and end of the string, then use TRIM instead of REPLACE:
UPDATE     tech_sourcing_employee_details
SET     address     = TRIM ('"' FROM address)
WHERE     INSTR (address, '"')         > 0          -- Maybe
;The WHERE clause is only for efficiency.
If, whenever the column contains double-quotes, one of the double-quote is always the first character in the string, then you can change the WHERE clause to:
WHERE     address LIKE '"%'
{code}

Similar Messages

Find and replace string in file

hi,
i need to find and replace text (string) data in about 100+ files, i've decided to write a small java program to do it but i'm stuck on how to replace.
here is what i'm heading towards:
class ReplaceString {
BufferedReader in;
BufferedReader os;
public static void main(String args[]) {
    ReplaceString obj = new ReplaceString();
    obj.replace();
   void replace() {
     try {
       in = new BufferedReader(new FileReader("a.txt");
       os = new BufferdWriter(new FileWriter("a.txt");
       // read until end of file
       String currentLine = new String();
       while((currenLine=is.readLine()) != null) {
         // if matching text then replace????
         if(currentLine.equals("Version 001") {
            // how to now replace the Version 001 with Version 002???
     }catch(IOException e) {
        System.out.println(e);
        in.close();
        os.close();
     in.close();
     os.close();
}the above code i just typed so there might be errors, but looks ok to me, is there any way once i find the string i want to replace, to replace the string with another string. basically i want to replace all occurrences of the text "Version 001" with "Version 002"
Thank you.

Is it always true, as in your example, that the replacement is the same length as the existing string? If so, this one's easy.
Is it also true that you don't need to worry about 16-bit chars? (Again, as in your example.) If you're using just ASCII characters, this gets easier still.
1) Segregate the file I/O from the search/replace process.
2) Main becomes:
readFile();
replace( "this", "that" );
writeFile();Use a byte array buffer, defined in your main class. Fill it via the readFile() code. Use a RandomAccessFile, check its length() to allocate your byte array, then do a single read() to fill the buffer.
A brute force search will certainly work: scan for the first search character, then check the rest for a match, replace if you've got a match and continue scanning. Alternative if your file's aren't too big: create a String from the byte array:
// buffer is a byte array
String s = new String( buffer );And use the String.replaceAll() to do the search/replace. Recover the buffer with:
buffer = string.getBytes();A single write() and close() should handle the remaining work.

Search and replace string inside a column

Hi,
in my table there is Column A with Type NVARCHAR.
i need to search inside all the rows in that column to find the string "_TH" and remove it wherever it exist.
how can i do it?

you can follow below solution .
Step 1: Create a temporary table to load all the records which are having column with '-TH'
Step 2 : Use update statement and join it with temporary table to update the qualified records
Benefits: This is a set based solution which is optimal and high perfroming
Script:
create table test1(col1 nvarchar(20))
insert into test1 values('one_th'),('two_th'),('Gauri')
--Create Temporary table
select *
into #tmp2
from Test1
where col1 like '%_TH%'
--update all such rows which are having column with '_TH'
Note: I am replacing all columns with '_TH' with space . you can replace with other characters based upon your requirement.
update t
set col1 = replace(t.col1,'_TH','')
from test1 t
inner join #tmp2 t2
on t.col1 = t2.col1
Please comment If this solution helps you.

Find and replace string in a file using batch script

I am writing a batch script to replace " ", with " ". The below code works but it prefixes each line with the line number and :.
It is the last part of the line that I am trying to replace.
E.g.
" ","BALANCE_SHEET ","ASSETS ","03","LEVEL_2 ",Asset Accounts," ",
To be replaced as
" ","BALANCE_SHEET ","ASSETS ","03","LEVEL_2 ",Asset Accounts," "
Code:
@echo off &setlocal
set "search=" ","
set "replace=" ""
set "textfile=Build_Accounts_Plan_Source.txt"
set "newfile=Build_Accounts_Plan_Source_new.txt"
(for /f "delims=" %%i in ('findstr /n "^" "%textfile%"') do (
set "line=%%i"
setlocal enabledelayedexpansion
set "line=!line:%search%=%replace%!"
echo(!line!
endlocal
))>"%newfile%"
type "%newfile%"
Output:
3:" ","BALANCE_SHEET ","ASSETS ","03","LEVEL_2 ",Asset Accounts," "
Regards,
Ragav.

Did you retype the code or did you use copy/paste? Retyping is not a good idea.
You can do this to find the cause of the problem:
Run the modified code below.
Use notepad.exe to open the file TempVBS.vbs in your %temp% folder.
Mark & copy the code, then paste it into your reply.
@echo off
set "textfile=Build_Accounts_Plan_Source.txt"
set "newfile=Build_Accounts_Plan_Source_new.txt"
set Scr="%temp%\TempVBS.vbs"
( echo Set oFSO = CreateObject("Scripting.FileSystemObject"^)
echo Set oInput = oFSO.OpenTextFile(WScript.Arguments(0^), 1^)
echo sData = Replace(oInput.ReadAll, "," ^& VbCrLf, VbCrLf^)
echo Set oOutput = oFSO.CreateTextFile(WScript.Arguments(1^), True^)
echo oOutput.Write sData
echo oInput.Close
echo oOutput.Close) > %Scr%
cscript //nologo %Scr% %textfile% %newfile%

How to find and replace the table name/column name

We have just upgraded the application to R12. Have many reports developed in Oracle Reports Builder. There are many changes in R12 table and column names when compare with 11i. Please suggest a solution to change the table name or column name in multiple reports queries instead of doing manually.

A Google search may turn up a downloadable service manual for the Laserjet 4600.
You might also ask in the HP Enterprise Business Community Forum here.
Bob Headrick, HP Expert
I am not an employee of HP, I am a volunteer posting here on my own time.
If your problem is solved please click the "Accept as Solution" button ------------V
If my answer was helpful please click the "Thumbs Up" to say "Thank You"--V

VBA Word Find and Replace characters but excluding certain characters

I am trying to write VBA code in Word that I will eventually run from a VBA Excel module. The aim of the project is to find specific strings in the open Word document that have length of either one or two characters and are of a certain format, and replace
them with other strings in the same format. This is to do with transposing (i.e. changing the musical key) of chord symbols in a songsheet in Word. The Find and Replace strings are contained in ranges in an Excel workbook, which is why I want to eventually
run the code from Excel. I'm much more experienced in writing VBA code in Excel than in Word, and I'm fairly confident with transferring the 'Word VBA' code into an Excel module.
At the moment I'm trying out code entirely in Word, and I've come across a stumbling block. For example, I want it to Find "A" and replace with "B",
BUT only if the "A" is NOT followed by "#" (sharp) or "b" (flat).
Here is the code I've got in Word VBA, which I obtained by editing code produced by the recorder:
Sub F_R()
'Find text must have specific font
With Selection.Find.Font
.Bold = True
.Underline = wdUnderlineWords
.Superscript = False
.Subscript = False
End With
'Replacement text must have specific font
With Selection.Find.Replacement.Font
.Bold = True
.Underline = wdUnderlineWords
.Superscript = False
.Subscript = False
End With
'Find & Replace strings
With Selection.Find
.Text = "A" 'hard-coded here for testing, but this will
'eventually be referenced to a cell in Excel
.Replacement.Text = "B" 'hard-coded here for testing, but this will
'eventually be referenced to a cell in Excel
.Forward = True
.Wrap = wdFindContinue
.Format = True
.MatchCase = True
.MatchWholeWord = False
End With
Selection.Find.Execute Replace:=wdReplaceAll
End Sub
For the Find & Replace section I want to do something like:
With Selection.Find
.Text = "A"
.Text <> "A#"
.Text <> "Ab"
.Replacement.Text = "B"
End With
- but this produces a syntax error, presumably because you can have only one .Text line (or it won't accept <>?)
I tried adopting the way of excluding chars when using the Like operator, and while it compiles, it will not replace
any "A":
With Selection.Find
.Text = "A[!b#]"
.Replacement.Text = "B"
End With
I suspect that I'm going to have to change tack completely in the way I'm doing this. Do you have any suggestions, please?
The chord names/symbols are preceded/succeeded by either spaces or paragraph returns and can look like these, for example (all Font Bold and Underlined words only):
C7
Dm7
Eb-5
Bb+11
F#m7
i.e. [ABCDEFG][b # | optional][m |optional][- + | superscript, optional][2 3
5 6 7 9 11 13 | superscript, optional]
The crux of my problem is that the note A should be treated as entirely distinct from Ab or A# (and similar for other flattened/sharpened notes).
Sorry for long post.

Hi Ian,
It is not easy to find Microsoft forums. However this forum is for the Visual Studio Net version.
Try this forum for VBA.
https://social.msdn.microsoft.com/Forums/en-US/home?forum=isvvba
Success
Cor

Reformatting files in Dreamweaver: Batch series of .dwr files (find and replace) consecutively

I have to do complicated reformatting of an entire site. It's been simplified to a series of find and replace tasks for each file. Each find and replace string has been saved as a .dwr file. Currently I have to load and execute each .dwr file.
How do you batch process or automate this task in Dreamweaver? In other words, queue up a series of .dwr files to be executed consecutively?

OK here we go.
This example, a simple Dreamweaver Command Extension, will execute two Find and Replace commands in one go. (It can be any number of Find and Replace commands.)
The first command replaces "the" and "this" with "phe" and "phis". The second command replaces <ul> ... </ul> with <ol> ... </ol>. (These of course can be any Find and Replace.)
You need two files: a HTML file (for the UI) and a Javascript file (for actions). I named them "Find and Replace Test.html" and "Find and Replace Test.js". (They can be any name.)
Find and Replace Test.html
<!DOCTYPE HTML SYSTEM "-//Adobe//DWExtension layout-engine 10.0//dialog">
<HTML>
<HEAD>
<Title>Find and Replace Test</Title>
<script src="Find and Replace Test.js"></script>
</HEAD>
<BODY>
<form>
 Are you sure?
</form>
</BODY>
</HTML>
Find and Replace Test.js
function canAcceptCommand() {
 return true;
function commandButtons() {
 return new Array("Go!", "doIt()", "Cancel", "window.close()");
function doIt() {
 dreamweaver.setUpFindReplace({
 searchString: "th(e|is)",
 replaceString: "ph$1",
 searchWhat: "document",
 searchSource: true,
 useRegularExpressions: true
 dreamweaver.replaceAll();
 dreamweaver.setUpFindReplace({
 searchString: "<(/?)ul>",
 replaceString: "<$1ol>",
 searchWhat: "document",
 searchSource: true,
 useRegularExpressions: true
 dreamweaver.replaceAll();
 window.close();
Basically you can call any number of this pair of functions in the script:
dreamweaver.setUpFindReplace(findAndReplaceObject);
dreamweaver.replaceAll();
Place these HTML and JS files in this directory:
Dreamweaver App Directory/Configuration/Commands/
Then in Dreamweaver, open "Insert" window. (You need to have a HTML file open in order to make the Insert window active.) At the top of the Insert window there's a category dropdown menu ("Common" etc.). Do alt + click (ctrl + click) - then you'll see an item "Reload Extenesions" at the bottom of the dropdown. This will load this extension to DW. (Alternatively you can restart DW to load the extension.)
Now it's ready to run the Extension. Open a HTML document you want to modify. Go to "Commands" on the menu bar. At the bottom of the dropdown there should be an item "Find and Replace Test". Select and enjoy
Notes
This example is set to perform the Find and Replace on the current document. You can change the scope to the entire site, or the selected files, etc, just like in the Find and Replace dialogue box. The API doc is here: http://help.adobe.com/en_US/dreamweaver/cs/apiref/WS5b3ccc516d4fbf351e63e3d117f9e09bcf-7ed a.html
You can use dreamweaver.setUpComplexFindReplace(xmlQueryString) command instead. xmlQueryString is basically <dwquery> ... </dwquery> in your .dwr files, you can copy from your .dwr files. However xmlQueryString needs to be one continuous string (no line breaks), which can be a pain The doc: http://help.adobe.com/en_US/dreamweaver/cs/apiref/WS5b3ccc516d4fbf351e63e3d117f9e09bcf-7ed 9.html
Command Extension general example in the doc: http://help.adobe.com/en_US/dreamweaver/cs/extend/WS5b3ccc516d4fbf351e63e3d117f53d6ec3-7fe 6.html
I hope all of these make sense...
Kenneth Kawamoto
http://www.materiaprima.co.uk/

Find and replace value in Delimited String

Hi All,
I have a requirement, where i need to find and replace values in delimited string.
For example, the string is "GL~1001~157747~FEB-13~CREDIT~A~N~USD~NULL~". The 4th column gives month and year. I need to replace it with previous month name. For example: "GL~1001~157747~JAN-13~CREDIT~A~N~USD~NULL~". I need to do same for last 12 months.
I thought of first devide the values and store it in variable and then after replacing it with required value, join it back.
I just wanted to know if there is any better way to do it?

for example (Assumption: the abbreviated month is the first occurance of 3 consecutive alphabetic charachters)
with testdata as (
select 'GL~1001~157747~FEB-13~CREDIT~A~N~USD~NULL~' str from dual
select
str
,regexp_substr(str, '[[:alpha:]]{3}') part
,to_date('01'||regexp_substr(str, '[[:alpha:]]{3}')||'2013', 'DDMONYYYY') part_date
,replace (str
         ,regexp_substr(str, '[[:alpha:]]{3}')
         ,to_char(add_months(to_date('01'||regexp_substr(str, '[[:alpha:]]{3}')||'2013', 'DDMONYYYY'),-1),'MON')
) res
from testdata
STR
PART
PART_DATE
RES
GL~1001~157747~FEB-13~CREDIT~A~N~USD~NULL~
FEB
02/01/2013
GL~1001~157747~JAN-13~CREDIT~A~N~USD~NULL~
with year included
with testdata as (
select 'GL~1001~157747~JAN-13~CREDIT~A~N~USD~NULL~' str from dual
select
str
,regexp_substr(str, '[[:alpha:]]{3}-\d{2}') part
,to_date(regexp_substr(str, '[[:alpha:]]{3}-\d{2}'), 'MON-YY') part_date
,replace (str
         ,regexp_substr(str, '[[:alpha:]]{3}-\d{2}')
         ,to_char(add_months(to_date(regexp_substr(str, '[[:alpha:]]{3}-\d{2}'), 'MON-YY'),-1),'MON-YY')
) res
from testdata
STR
PART
PART_DATE
RES
GL~1001~157747~JAN-13~CREDIT~A~N~USD~NULL~
JAN-13
01/01/2013
GL~1001~157747~DEC-12~CREDIT~A~N~USD~NULL~
Message was edited by: chris227 year included

Find and replace an item in one column only

I have tried and tried and I cannot work out how to find and replace an item in one column only.
For example one column has a letter followed by a number which varies in length.
I want to find and repace the letters with nothing leaving the numbers only.
But when I try to do this all the letters in the spreadheet are replaced, not just in the column I have selected.
Help please....

Hi 8'
Use a formula.
Insert a (temporary) auxiliary column to the right of the one for which you want to male the changes.
Assuming you description is accurate—every entry in the column consists of a letter followed immediately by a number of one or more digits—the problen could also be stated as "How do I strip the first character from a string?"
Here's a sample. Letter followed by number in column B; number part without leading letter i column C:
Formula:
C2, and filled down to end of column: =RIGHT(B,LEN(B)-1)
When the formula has done its work:
Select all of column C (except the ehader row cell), and Copy.
Select cell B2, and go Edit > Paste Values.
Select column C again and go Table (menu) > Delete column.
Regards,
Barry

[Forum FAQ] How to find and replace text strings in the shapes in Excel using Windows PowerShell

Windows PowerShell is a powerful command tool and we can use it for management and operations. In this article we introduce the detailed steps to use Windows PowerShell to find and replace test string in the
shapes in Excel Object.
Since the Excel.Application
is available for representing the entire Microsoft Excel application, we can invoke the relevant Properties and Methods to help us to
interact with Excel document.
The figure below is an excel file:
Figure 1.
You can use the PowerShell script below to list the text in the shapes and replace the text string to “text”:
$text = “text1”,”text2”,”text3”,”text3”
$Excel
= New-Object -ComObject Excel.Application
$Excel.visible = $true
$Workbook
= $Excel.workbooks.open("d:\shape.xlsx")
#Open the excel file
$Worksheet
= $Workbook.Worksheets.Item("shapes")
#Open the worksheet named "shapes"
$shape = $Worksheet.Shapes
# Get all the shapes
$i=0
# This number is used to replace the text in sequence as the variable “$text”
Foreach ($sh in $shape){
$sh.TextFrame.Characters().text
# Get the textbox in the shape
$sh.TextFrame.Characters().text =
$text[$i++]
#Change the value of the textbox in the shape one by one
$WorkBook.Save()
#Save workbook in excel
$WorkBook.Close()
#Close workbook in excel
[void]$excel.quit()
#Quit Excel
Before invoking the methods and properties, we can use the cmdlet “Get-Member” to list the available methods.
Besides, we can also find the documents about these methods and properties in MSDN:
Workbook.Worksheets Property (Excel):
http://msdn.microsoft.com/en-us/library/office/ff835542(v=office.15).aspx
Worksheet.Shapes Property:
http://msdn.microsoft.com/en-us/library/office/ff821817(v=office.15).aspx
Shape.TextFrame Property:
http://msdn.microsoft.com/en-us/library/office/ff839162(v=office.15).aspx
TextFrame.Characters Method (Excel):
http://msdn.microsoft.com/en-us/library/office/ff195027(v=office.15).aspx
Characters.Text Property (Excel):
http://msdn.microsoft.com/en-us/library/office/ff838596(v=office.15).aspx
After running the script above, we can see the changes in the figure below:
Figure 2.
Please click to vote if the post helps you. This can be beneficial to other community members reading the thread.

Thank you for the information, but does this thread really need to be stuck to the top of the forum?
If there must be a sticky, I'd rather see a link to a page on the wiki that has links to all of these ForumFAQ posts.
EDIT: I see this is no longer stuck to the top of the forum, thank you.
Don't retire TechNet! -
(Don't give up yet - 13,085+ strong and growing)

Find and Replace text string in HTML

Opps... I hope this forum is not just for Outlook. My Html files reside on my hard-drive. I am looking for VBA code to open specified file names ####File.html and then find and replace text strings within the html for example "####Name" replaced
with "YYYYY"
I drive the "####File.html" names and the find and replace text strings from an Excel sheet. I am an artist and this Sub would give me time to paint instead of find and replace text. Thank you!
[email protected]

Hello Phil,
The current forum is for developers and Outlook related programming questions. That's why I'd suggest hiring anybody for developing the code for you. You may find freelancers, for example. Try googling for any freelance-related web sites and asking such
questions there.
If you decide to develop an Outlook macro on your own, the
Getting Started with VBA in Outlook 2010 article is a good place to start from.

How to find and replace any string between " "

Hi everyone,
Here my sample
String szTest;
szTest = "Yellow banana";
szTest = "Blue monkey";
szTest = "Red mango";
szTest is only needed when it's in testing progress. Now I want to put all of that in the /*comment*/ so the released program won't run those code any more (but still keep szTest so I can use it for future develop testing).
So Here what I want after using the Find and Replace Box:
//String szTest; //Manual
/*szTest = "Yellow banana";*/ //use find and replace
/*szTest = "Blue monkey";*/ //use find and replace
/*szTest = "Red mango";*/ //use find and replace
I think I can do this with Regular expressions or Wildcards. But I don't know how to find and replace any string between " and ".
Find: szTest = " ??Any string?? ";
Replace with: /*szTest = " ??Any string?? ";*/
Thanks for reading.

Hi Nathan.j.Smith,
Based on your issue, I suggest you can try the Joel's suggestion check your issue again. In addition, I find a MSDN document about how to use the Regex.Replace Method to match a regular expression pattern with a specified replacement string,
maybe you will get some useful message.
https://msdn.microsoft.com/en-us/library/xwewhkd1(v=vs.110).aspx
If the above suggestion still could not provide you, could you please tell me what language you use to create the program for finding and replace any string using regular expression so that we will find the correct programming develop forum to support this
issue?
Best Regards,
We are trying to better understand customer views on social support experience, so your participation in this interview project would be greatly appreciated if you have time. Thanks for helping make community forums a great place.
Click
HERE to participate the survey.

Can't find and replace on one column only

in Excel I could find and replace something that where on one column.
In Numbers I can find and replace on all the document, active sheet or formula, but not on the selected column i.e.
Does anyone know any trick for that?
Cheers
Olivke

Hi Olivke,
Welcome to Apple Discussions and the Numbers '09 forum.
Of the three choices, the one that seems most immediately useful in "on the active sheet."
To use that, you'll have to isolate the column (or it's contents) on a separate sheet, and make that the 'active sheet.'
I would recommend making duplicates of your file to use when trying each of these methods.
Start by inserting a new sheet. Then go back to the 'current sheet', select the column, and Copy.
Click on the new sheet to bring it to the front, click on the top body cell (B2) of the empty table that came with that sheet and Paste.
Do Find/Replace, restricting the action to the Current Sheet.
Select the column, Copy, return to the original, Select the column, Paste.
Second method...
Starts the same way, but this time select and delete the table that comes with the New Sheet.
On the original table, click on any cell to make the table active and show the column and row reference tabs.
Use the mouse to grab the reference tab of the column you want to search, and drag it upward until you see it separate from the rest of the table. Continue to drag it until it is completely separated from the table, then drop it on the sheet. In the sidebar, you'll see a new table icon for this one column table. Drag the icon down to a position below the icon for the new sheet you created above.
When you drop the icon, the new sheet will be come the current sheet, and will come to the front with the one column table selected.
Do Find/Replace, restricting the action to the current sheet.
When finished, drag the one column table back to its original sheet, using the icon in the sidebar.
On the original sheet, click on a cell to make the one column table active. Grab the column reference tab and drag the column back to its original position in the original table.
Done.
Regards,
Barry

String find and replace

Hello,
I am trying to do the equivalent of a find and replace in a String object.
I want to be able to replace text in a String with a java variable so as an example, this is a line of the text file. The text has to be stored in an outside file and read in...
<center>Users name is #username#</center>
I have this String stored in, lets say, outputString and have the username stored in usernameString. I want to do something like:
String usernameString = "bob";
if ( //found the reference #username# in outputString ) {
 //replace #username# with usernameString;
}So I end up with:
<center>Users name is Bob</center>
I have looked at the methods in String and it is possible to do this if I do a lot of complicated coding using Char[] arrays or index counts etc.
Does anyone have any idea how to do this easily?
Many Thanks

Use the StringBuffer class:
String usernameString = "bob";
if(outputString.indexOf("#username#") > -1) {
 outputString = new StringBuffer(outputString).replace(outputString.indexOf("#username#"),
 "#username#".length(),
 usernameString).toString();
}

Find and Replace a Blank in Load Rules

 Does anyone know if it is possible to find and replace a blank cell with a member name within Essbase Load Rules? My source data (a .txt file) has blanks within a single dimension that I need to replace with an Essbase member name so I can load it into the essbase cube. Until I add characters into the 'Find' window within Find and Replace, the option to add it in is greyed out. I am using Essbase 6.5.1 

From the DBag: Replacing an Empty Field with Text You may want to replace empty fields in a column with text. If, for example, empty fields in the column represent default values, you could insert the default values to replace the empty ones or insert #MI to represent missing values. Replacing an empty field with text requires several steps. To replace an empty field with text: Select the column containing the empty fields you want to replace. Choose Field > Create Using Text or click the Create Using Text button, . Enter the text to put in the new field. Enter a dummy string that is not in the selected column, such as "temp." Click OK. Join the new field with the column containing the fields to replace. Select both columns, choose Field > Join, and click OK. The previously blank fields now contain the dummy string you entered in step 3; for example, temp. Select the column containing the dummy string and choose Field > Properties or click the Field Properties button, . Click the Global Properties tab. Enter the text string you want to replace in the Replace text box. This should be the dummy string you entered in step 3; for example, temp. Now enter the text to replace it with in the With text box. This should be the final value you want to put in the fields, for example, default. Select the Match Whole Word. Click Add and then click OK. Now replace the extra dummy strings in the column with nothing. Choose Field > Properties or click the Field Properties button, . Click the Global Properties tab. Enter the dummy string in the Replace text box; for example, temp. Enter nothing in the With text box. Make sure the Match Whole Word option is not checked. Click Add and then click OK.

Find and Replace String in a Column

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