Find n replace pricing in paragraphs-

Question

OK, I have a rather large catalogue that used to be a QuarkXPress Job recently converted by plug-in and cleaned up. I now have the need to run thru this and make some changes. (Please bare in mind Im using CS2 so my find and change may NOT be up to this?) Here is an example of the contents of the price listed text frames…
What I need to do is replace the last 2 prices with just the one e.g. '£00.00' in the black. I will then be moving the tab stop positions. Now the example above is NOT the best as my prices can be of varying length '£1.23', '£12.34' or '£123.45' so is there a way I can use find n change in the GUI or would script be better suited to this? I think I could do multi f&r to something unique then replace that but its going to be too time consuming. Is it possible to use any digit {n} times? In Quark I could have it include '£' and '.' in the definition of word then just remove the last word. I hope thats fairly clear if NOT let me know. Thanks in advance…

Answer 1

Well, I had a little time to dig some further and this is almost there even if a little ugly…
#target indesign
function removePrices() {
     if (app.documents.length == 0) {
          alert('Please have an "InDesign" document open before running this script.');
          return;
     var docRef = app.activeDocument;
     // Just using a selected box to test
     with (docRef.selection[0]) {
          // Missout first n last paras
          for (var i = 1; i < paragraphs.length-1; i++) {
               var a = paragraphs[i].contents.indexOf('£') + 1;
               var b = paragraphs[i].contents.length-2;               
               paragraphs[i].characters.itemByRange(a,b).remove()
               paragraphs[i].words.lastItem().contents = '£00.00';               
          // No return at end of this one
          var a = paragraphs[i].contents.indexOf('£') + 1;
          var b = paragraphs[i].contents.length-1;          
          paragraphs[i].characters.itemByRange(a,b).remove();
          paragraphs[i].words.lastItem().contents = '£00.00';
          // Remove my last tab
          paragraphs.everyItem().tabStops.lastItem().remove();
          // Move my tabs and respace content
          paragraphs.everyItem().tabStops.lastItem().position = 77;
          This did NOT work but I was hardly surprised!!!
          paragraphs.everyItem().tabStops.lastItem().previousItem().position = 67;
          var c = paragraphs[1].tabStops.length-2;
          paragraphs.everyItem().tabStops.item(c).position = 67;
removePrices();