Find Previous row

Hi All,
Pls tell me how to find previous row data according to specific condition as follows,
my table structure like this
ID NAME SAL
7 pp 500
1 aa 100
2 bb 200
3 cc 300
4 dd 400
1 gg 400
2 pp 500
5 qq 700
1 ql 900
8 ql 900
9 al 900
1 al 700
I want to select only previous row which is before id 1.
I want result like this .
ID NAME SAL
7 pp 500
4 dd 400
5 qq 700
9 al 900
Pls help me.
Thanks & Regards,

Hi,
SQL> SELECT * FROM t;
        ID NAME                        SAL
         7 pp                          500
         1 aa                          100
         2 bb                          200
         3 cc                          300
         4 dd                          400
         1 gg                          400
         2 pp                          500
         5 qq                          700
         1 ql                          900
         8 ql                          900
         9 al                          900
        ID NAME                        SAL
         1 al                          700
12 rows selected.
SQL> SELECT * FROM t
2 WHERE (id) IN (
3 SELECT id_1 FROM (
4 SELECT id,lag(id,1) over (order by 1) id_1 FROM t
5 ) WHERE id = 1
6 )
7 /
        ID NAME                        SAL
         4 dd                          400
         5 qq                          700
         7 pp                          500
         9 al                          900
SQL>Regards

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Hi All,
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EXAMPLE:
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Hi, please find the detail description of the problom.
DDL (table scripts)
ITEM
CREATE TABLE ITEM
ITEM VARCHAR2(50 CHAR) NOT NULL,
DESCR VARCHAR2(50 CHAR) DEFAULT ' ' NOT NULL,
UOM VARCHAR2(50 CHAR)
SKU
CREATE TABLE SKU
ITEM VARCHAR2(50 CHAR) NOT NULL,
LOC VARCHAR2(50 CHAR) NOT NULL,
OH float
SKUPROJSTATIC
CREATE TABLE SKUPROJSTATIC
ITEM VARCHAR2(50 CHAR) NOT NULL,
LOC VARCHAR2(50 CHAR) NOT NULL,
STARTDATE DATE
VehicleLoad
CREATE TABLE VEHICLELOAD
LOADID VARCHAR2(50 CHAR) NOT NULL,
DESCR VARCHAR2(50 CHAR) DEFAULT ' ' NOT NULL,
SHIPDATE DATE DEFAULT TO_DATE('01/01/1970','MM/DD/YYYY') NOT NULL,
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VEHICLELOADLINE
CREATE TABLE VEHICLELOADLINE
LOADID VARCHAR2(50 CHAR) NOT NULL,
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DML scripts
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select
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vl.shipdate,
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I have a SSRS report which uses a matrix for a crosstab effect.
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All,
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Hi All,
I am having a problem with the query. Can some of please help me?
I need to get difference between current row and previous row in a table. I have a table, which have data like bellow.
TABLEX
================
Name Date Items
AAA 01-SEP-09 100
BBB 02-SEP-09 101
CCC 03-SEP-09 200
DDD 04-SEP-09 200
EEE 05-SEP-09 400
Now I need to get output like bellow...
Name Date Items Diff-Items
AAA 01-SEP-09 100 0
BBB 02-SEP-09 101 1
CCC 03-SEP-09 200 99
DDD 04-SEP-09 200 0
EEE 05-SEP-09 400 200
Can some one help me to write a query to get above results?
Please let me know if you need more information.
Thanks a lot in advance.
We are using Oracle10G(10.2.0.1.0).
Thanks
Asif

     , nvl (items - lag (items) over (order by dt), 0)like in
SQL> with test as
2 (
3 select 'AAA' name, to_date('01-SEP-09', 'dd-MON-rr') dt, 100 items from dual union all
4 select 'BBB' name, to_date('02-SEP-09', 'dd-MON-rr') dt, 101 items from dual union all
5 select 'CCC' name, to_date('03-SEP-09', 'dd-MON-rr') dt, 200 items from dual union all
6 select 'DDD' name, to_date('04-SEP-09', 'dd-MON-rr') dt, 200 items from dual union all
7 select 'EEE' name, to_date('05-SEP-09', 'dd-MON-rr') dt, 400 items from dual
8 )
9 select name
10       , dt
11       , items
12       , nvl (items - lag (items) over (order by dt), 0)
13    from test
14 ;
NAM DT             ITEMS NVL(ITEMS-LAG(ITEMS)OVER(ORDERBYDT),0)
AAA 01-SEP-09        100                                      0
BBB 02-SEP-09        101                                      1
CCC 03-SEP-09        200                                     99
DDD 04-SEP-09        200                                      0
EEE 05-SEP-09        400                                    200
SQL>

How to find middle row in a table ?

Hi Friends,
Is it possible to find middle row in a table by SQL Query.
KarTiK.

Solution: sort the rows in order to create an ordered
sequence and then there will be a "middle row".Well, not quite.
If there are an odd number of rows then, yes, there will be a middle row in an ordered sequence, however if there is an even number of rows then the middle is between two rows... or... you could take it as the two rows either side of the middle....
SQL> select * from emp order by empno;
     EMPNO ENAME      JOB              MGR HIREDATE                   SAL       COMM     DEPTNO
      7369 SMITH      CLERK           7902 17/12/1980 00:00:00        800                    20
      7499 ALLEN      SALESMAN        7698 20/02/1981 00:00:00       1600        300         30
      7521 WARD       SALESMAN        7698 22/02/1981 00:00:00       1250        500         30
      7566 JONES      MANAGER         7839 02/04/1981 00:00:00       2975                    20
      7654 MARTIN     SALESMAN        7698 28/09/1981 00:00:00       1250       1400         30
      7698 BLAKE      MANAGER         7839 01/05/1981 00:00:00       2850                    30
      7782 CLARK      MANAGER         7839 09/06/1981 00:00:00       2450                    10
      7788 SCOTT      ANALYST         7566 19/04/1987 00:00:00       3000                    20
      7839 KING       PRESIDENT            17/11/1981 00:00:00       5000                    10
      7844 TURNER     SALESMAN        7698 08/09/1981 00:00:00       1500          0         30
      7876 ADAMS      CLERK           7788 23/05/1987 00:00:00       1100                    20
      7900 JAMES      CLERK           7698 03/12/1981 00:00:00        950                    30
      7902 FORD       ANALYST         7566 03/12/1981 00:00:00       3000                    20
      7934 MILLER     CLERK           7782 23/01/1982 00:00:00       1300                    10
14 rows selected.
SQL> select e.empno, e.ename, e.job, e.mgr, e.hiredate, e.sal, e.comm, e.deptno
2 from (select emp.*, row_number() over (order by empno) as rn from emp) e
3      ,(select round(count(*)/2) as middle, round(((count(*)+1)/2)) as middle2 from emp) m
4 where e.rn in (m.middle, m.middle2)
5 /
     EMPNO ENAME      JOB              MGR HIREDATE                   SAL       COMM     DEPTNO
      7782 CLARK      MANAGER         7839 09/06/1981 00:00:00       2450                    10
      7788 SCOTT      ANALYST         7566 19/04/1987 00:00:00       3000                    20
SQL> insert into emp values (1111, 'WILLIS', 'CLERK', 7902, sysdate, 900, null, 20);
1 row created.
SQL> select * from emp order by empno;
     EMPNO ENAME      JOB              MGR HIREDATE                   SAL       COMM     DEPTNO
      1111 WILLIS     CLERK           7902 18/01/2008 12:18:14        900                    20
      7369 SMITH      CLERK           7902 17/12/1980 00:00:00        800                    20
      7499 ALLEN      SALESMAN        7698 20/02/1981 00:00:00       1600        300         30
      7521 WARD       SALESMAN        7698 22/02/1981 00:00:00       1250        500         30
      7566 JONES      MANAGER         7839 02/04/1981 00:00:00       2975                    20
      7654 MARTIN     SALESMAN        7698 28/09/1981 00:00:00       1250       1400         30
      7698 BLAKE      MANAGER         7839 01/05/1981 00:00:00       2850                    30
      7782 CLARK      MANAGER         7839 09/06/1981 00:00:00       2450                    10
      7788 SCOTT      ANALYST         7566 19/04/1987 00:00:00       3000                    20
      7839 KING       PRESIDENT            17/11/1981 00:00:00       5000                    10
      7844 TURNER     SALESMAN        7698 08/09/1981 00:00:00       1500          0         30
      7876 ADAMS      CLERK           7788 23/05/1987 00:00:00       1100                    20
      7900 JAMES      CLERK           7698 03/12/1981 00:00:00        950                    30
      7902 FORD       ANALYST         7566 03/12/1981 00:00:00       3000                    20
      7934 MILLER     CLERK           7782 23/01/1982 00:00:00       1300                    10
15 rows selected.
SQL> select e.empno, e.ename, e.job, e.mgr, e.hiredate, e.sal, e.comm, e.deptno
2 from (select emp.*, row_number() over (order by empno) as rn from emp) e
3      ,(select round(count(*)/2) as middle, round(((count(*)+1)/2)) as middle2 from emp) m
4 where e.rn in (m.middle, m.middle2)
5 /
     EMPNO ENAME      JOB              MGR HIREDATE                   SAL       COMM     DEPTNO
      7782 CLARK      MANAGER         7839 09/06/1981 00:00:00       2450                    10
SQL>

Using the Previous Row in a Calculator Formula

Hello. I am using the calculator to create a new channel that is a custom filtered version of an existing channel. Unfortunately, I have not been able to identify the previous row entry in the channel. To make things easier, let's say my filter is a simple averager. Here is simple pseudocode for what I want to do:
New_Channel = (Existing_Channel[n] + Existing_Channel[n-1]) / 2
where n is the current row.
This is the calculator formula I have come up with:
ch("[1]/New_Channel") = (CHD(chnRow - 1, "[1]/Existing_Channel") + ch("[1]/Existing_Channel")) / 2 + CTNV(chnRow > 1)
Unfortunately, I think chnRow only returns 0.
Obviously, I am a beginner. I am open to other approaches to creating a new channel with a custom filter.
Thanks!
Solved!
Go to Solution.

Hi jbuttron,
What you need to do is to copy the channel and delete the first value from the copied channel-- then the Nth row of the original channel will line up with the (N-1)th row of the copied channel. You should also add the last value of the copied channel to the end of that channel as a new value so both channels end up with the same channel length. Now you can reference the channels with Ch("[1]/old") and Ch("[1]/new") in the channel calculator expression, assuming that the channel names are "old" and "new" respectively and that both are in the first group. You don't need a row variable in the expression now, which is good because there's no way to iterate a row variable in a channel calculator expression. The row iteration is implicit in the channel referencing Ch("[1]/new").
Brad Turpin
DIAdem Product Support Engineer
National Instruments

HOW TO FIND PREVIOUS BALANCE OF DOCUMENT NUMBER.

Hello Abapers,
I am doing customer statment report in FI.In this i need to find previous cumulative balance of document number and i need to add present balance.
For eaxmple.
Invoice    payment        Balance    Cumulative balance
8000       4000              600             600
8001       4001              500             (600 + 500 ) = 1100
              4002              800             (600 + 800) = 1400.
8002       4003             900              (1400+900) = 2300.
              4004             1000            (1400+1000) = 2400.
In the above example,I need to find cumulative balnce of 8000(600) and add document(4001,4002) of balance.
This is my case.
How can i achive it.
waiting for u rfavourable replies.
Regards
Maruthi

If I understand you right, the input is restricted to positive integers. (if you allow negative numbers, zero, or fractions, you need to define what results you want).
For positive integers inputs, here's a mathematical solution (but the formatting solutions above are probably simpler).
LabVIEW Champion . Do more with less code and in less time .
Attachments:
CountDigits.png ‏11 KB

Add row based on previous row in table control?

Dear all,
I have a table control with some rows. Every row contains one button. On button click i want to add another row with dirrerent data. I want to add content based on button text or another columns (ex text views text,) based on this text view, I have to add row. One button can click any no of times. On every click i want to add row, but desired position and content should be based on button click. Any help in doing this??
Cheers,
Venkys.

Refer to these old threads referring this table and button problem.
Adding rows to table
How to create different rows in table or in ALV?
and for the current scenario what you can do is ...
in the eventhandler of the button click .
find out the row number by using the code to read index.
then based upon that add the element in the node at the desired position.
finding the row number
data indx type i.
      DATA lo_el TYPE REF TO if_wd_context_element.
      lo_el = wdevent->get_context_element( 'CONTEXT_ELEMENT' ).
indx = lo_el->get_index( ).
and the adding the element at the desired position say n
    DATA lo_nd_zdealer TYPE REF TO if_wd_context_node.
    lo_nd_zdealer = wd_context->get_child_node( name = 'DEALER' ).
data ls_str type wd_this->element_dealer.
   ls_str-id = '00023445'.
   ls_str-name = 'sarbjeet'.
   ls_str-location = 'hosiarpur'.
   ls_str-status = '0001'.
   lo_nd_zdealer->bind_structure( new_item = ls_str
   set_initial_elements = abap_false
   index = n
thanks
sarbjeet singh

When updating my iphone 4s to the new ios 6, it lost all data including photos, contacts etc. itunes now cannot find previous back up. Is there anyway i can get this lost data

when updating my iphone 4s to the new ios 6, it lost all data including photos, contacts etc. itunes now cannot find previous back up. Is there anyway i can get this lost data

rebeccakhwar17 wrote:
Hi
Can anyone help me please. I've recesally had to take my Iphone to be repaired before I. took my phone i backed up my data into Icloud and when i got my new phone I have lost all my contacts and photos.
Restore the iPhone from your backup.
See this -> http://support.apple.com/kb/ht1766
Then make sure you sync everything to your computer so you do not lose it.

How to find duplicate row in sql query?

Hi All,
Please solve my query, find duplicate row and how to count its. your suggestion would be greatly appreciated.

You can use group by and having.
SQL> WITH t
2       AS (SELECT       LEVEL id
3                 FROM   DUAL
4           CONNECT BY   LEVEL <= 5
5           UNION ALL
6           SELECT       LEVEL + 2
7                 FROM   DUAL
8           CONNECT BY   LEVEL <= 3)
9 SELECT   *
10    FROM   t;
        ID
         1
         2
         3
         4
         5
         3
         4
         5
8 rows selected.
SQL> WITH t
2       AS (SELECT       LEVEL id
3                 FROM   DUAL
4           CONNECT BY   LEVEL <= 5
5           UNION ALL
6           SELECT       LEVEL + 2
7                 FROM   DUAL
8           CONNECT BY   LEVEL <= 3)
9 SELECT     id, COUNT (*)
10      FROM   t
11 GROUP BY   id
12    HAVING   COUNT (*) > 1;
        ID   COUNT(*)
         3          2
         4          2
         5          2
SQL>

How to get previous row of result set in select query?

I want to access the previous row of an result set obtained yet, in the same selectquery .
How can I do that?

Use analytical functions.
For example:
create table top_n_test (
   a number,
   b varchar2(10)
insert into top_n_test values (1,   'one');
insert into top_n_test values (2,   'two');
insert into top_n_test values (3, 'three');
insert into top_n_test values (4, 'four');
insert into top_n_test values (5, 'five');
insert into top_n_test values (6,   'six');
insert into top_n_test values (7, 'seven');
insert into top_n_test values (8, 'eight');
insert into top_n_test values (9, 'nine');
commit;
select a, b from (
select
    a,b,
    rank() over (order by b) r
from
    top_n_test
where
r<4;
         A B
         8 eight
         5 five
         4 fourHTH
Ghulam

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