Find the installation Path of the current running VM on Windows

Question

Hello,
I have a java class started by webstart.
In this class I would like to find the absolute path of the current running vm? This is important to me because I need to start an exe file (using ProcessBuilder) and hand it the path of the java VM,
For example I could try something like this:
private static File findJDK() throws Exception {
String s = System.getProperty("java.home");
File myJRE = new File(s);
if (new File(myJRE, "bin/javac.exe").isFile()) {
return myJRE;
File parent = myJRE.getParentFile();
if (new File(parent, "bin/javac.exe").isFile()) {
return parent;
for (String pathel : System.getenv("PATH").split(File.pathSeparator)) {
File bindir = new File(pathel);
if (new File(bindir, "javac.exe").isFile()) {
return bindir.getParentFile();
return myJRE;
But I would like the above code to be more fool proof!
For example the "java.home" could be wrongly set.
Since java is allready running I would have hopped that I could query the Runtime. But there seems to be no method providing the running java VM path?
I also tried looking at the jnlp services API but no luck.
I would be also interested find the lastest java VM on the client Windows machine....
Many greetings
john

Answer 1

http://docs.oracle.com/javase/7/docs/api/java/lang/System.html#getProperties()
bye
TPD