Generate Random Password by policy

Hey guys,
I'm trying to put together some code to randomly generate a password for new users that would match up with the user's associated password policy. I have this code mapped as a entity adapter on the pre-insert. The problem i am having is trying to retrieve the password policy that is associated with the new user.....the tcPasswordOperationsIntf utility class has a method called getUserPasswordPolicy which takes the usr_key as an argument.....but since the user hasn't been created yet the method fails with an usr_key not found error.
anyone know how i can get the password policy for a new user? has anyone done anything like this before?
Thanks in advance!

Well if you are trying to set the password for the Users created in OIM then the password policy must be attached to Xellerate Users resource object. So you have an option of fetching the password policy using another API getObjectPasswordPolicyDescription of the same interface. You need to pass the Object Key in this case. This must return the ResultSet for the same thing you are expecting.
The you can validate the password accordingly.
Thanks
Sunny

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How to generate random password as per password policy by knowing the resou

Hi,
Any body tell me, how to generate random password as per password policy by knowing the resource object in OIM11g
Regards,
Nishith Nayan

Hi Nayan,
You can try below code snippet:
UserRepository ur = new DBUserRepository();
UserInfo user = ur.getUserInfo(userKey);
               ResourceRepository rrepo = new ResourceDBRepository();
               Resource resource = rrepo.findResource(resourceName);
               PasswordPolicyAssignmentsRepository par = new PasswordPolicyAssignmentsDBRepository();
               PasswordPolicyRepository ppr = new DBPasswordPolicyRepository();
               List passwordPolicyAssignments = par.getPasswordPolicyAssigments(resource);
               PasswordPolicy passwordPolicy;
                                        PasswordPolicyAssignment passwordPolicyAssignment = (PasswordPolicyAssignment) passwordPolicyAssignments.get(0);
                         if (isApplicable(passwordPolicyAssignment, getMappedAttributes(userInfo.getAttributes()))) {
                              passwordPolicy = ppr.find(passwordPolicyAssignment.getPasswordPolicyID());
                                             RandomPasswordGeneratorImpl rpg = new RandomPasswordGeneratorImpl();
                         password = rpg.generatePassword(userInfo, passwordPolicy);
regards,
gyan

How to create a javabean that generate random password?

May i know how to create a javabean that can generate random password?
that include character and string
and length of 10.

i created a class file for my java bean
package autogenerate;
import java.util.*;
public class GeneratePwId
private int MemId;
private String Passwd;
public GeneratePwId(){}
public String getPasswd()
return this.Passwd;
public void setPasswd()
char[] letters = { 'A', 'B', 'C', 'D', 'E', 'F', 'G', 'H',
'J', 'K', 'L', 'M', 'N', 'P', 'R', 'T',
'U', 'V', 'W', 'X', 'Y', 'Z', 'a', 'b', 'c',
'd', 'e', 'f', 'g', 'h', 'i', 'j', 'k',
'm', 'n', 'p', 'q', 'r', 's', 't', 'u',
'v', 'w', 'x', 'y', 'z', '0', '1', '2',
'3', '4', '5', '6', '7', '8', '9' } ;
String pwd = "" ;
while( pwd.length() < 10 )
pwd += letters[ (int)( Math.random() * letters.length ) ] ;
this.Passwd = pwd;
i successfully compile my java file. and try to test it by writing a jsp file.
here is my jsp code
<html>
<head>
<title>
Try retrieving password
</title>
</head>
<body>
<jsp:useBean class"autogenerate.GeneratePwId" id="bean0" scope="page"/>
<%=bean0.getPasswd()%>
</body>
</html>
but i encounter this error
org.apache.jasper.compiler.ParseException: /jsp/GetPasswd.jsp(7,18) Attribute class has no value
anyone can teach me how to solve this problem?
thanks a alot!

How can I generate random password

Hello...
I use oracle 10g for windows,,,I have an employee table , there are a lot of colunms , their names are employee_name , employee_id ,employee_pass .....
employee_pass colunm is empty
I want to generate random password for employee_pass colunm
How can I generate random password for employee_pass colunm
thanks
omer faruk akyuzlu
in Turkey

SQL> exec dbms_random.seed(to_char(sysdate, 'sssss'))
PL/SQL procedure successfully completed.
SQL> select dbms_random.string('X', 8) from dual
2 /
DBMS_RANDOM.STRING('X',8)
4YT1H150
SQL> select dbms_random.string('X', 8) from dual
2 /
DBMS_RANDOM.STRING('X',8)
WIA3QCIP
SQL> Please be aware that storing the actual passwords in a the EMPLOYEES table is a very bad idea. Oracle has a pretty good password implementation. It's not perfect but it's a darn site better than hand-rolling our own.
Cheers, APC

How to generate random password

Hi Experts,
i using some cmdlets to generate random password.
$ascii=$NULL;
For ($a=97;($a –le 122);$a++) {$ascii+=,[char][byte]$a }
$No_of_password = 6
$length_of_password = 10
$TempPassword=$NULL     # To store single password
$Morepassword=@() # Variable to 'X' no. of passwords
for ($lp=0; $lp -le $count; $lp++ )
For ($loop=1; $loop –le $length; $loop++)
    $TempPassword+=($ascii | GET-RANDOM)   # this generate the random password
$morepassword[$lp]= $TempPassword
$morepassword    # This should give the all random password
Output is like ---
=zM;HFuElY
=zM;HFuElYp88<kqTOVM
=zM;HFuElYp88<kqTOVMfS1xR01VzY
=zM;HFuElYp88<kqTOVMfS1xR01VzY4<$wG%Z>ft
=zM;HFuElYp88<kqTOVMfS1xR01VzY4<$wG%Z>ft=a&ME7>&3T
=zM;HFuElYp88<kqTOVMfS1xR01VzY4<$wG%Z>ft=a&ME7>&3T$98v$b>jSU
This is not required output. It should give the output like
=zM;HFuElY
p88<kqTOVM
fS1xR01VzY
4<$wG%Z>ft
=a&ME7>&3T
$98v$b>jSU
Total 6 passwords with a length of 10
How do create a array like this ?

I agree with Fred but here i shwo to manage two loops with PowerShell.
$pwdchars=33..122|%{[char]$_}
1..6|
ForEach-Object{
$pwd=''
1..10 |
ForEach-Object{
$pwd+=$pwdchars | GET-RANDOM
$pwd
It is usually always better to write less code and to use the code correctly. YOu have guessed at mmost of the code but have not used consistent variables. My guess is that you have tried to modify somecode you found. Look at this code
to see how easy it is to build loops in PowerShell
¯\_(ツ)_/¯

Sun idm 8.0.0.3: generate random password according to policy

Hi all,
probably a stupid question: using sun idm 8 I have an active-sync-source, containing employees but no passwords. So I should generate a new password in my active-sync-form and search for a way to export the password so new employees can be sent a letter "welcome at company, here is your password". Something like that.
However, I fail to generate a password in the first place. I think I read about a PasswordGenerator once, but can't find it.
So, what's the preferred way to generate a new password, if possible according to a selected password-policy?
CU,
Patrick.

OK, OK if the policy is set to generate my troubles go away.... I thought that was gone with metaview?
Anyway, what if I'd like to choose a special Policy for creation that differs from normal operations?
CU,
Patrick.

Parameterized Active Sync Form generating random password

Hi im looking for an sample of an Parameterized Active Sync Form which generates a random password.
Thanks!
Michael

--I think password from AD not put in to activeSync.
--Why?
You cannot change the user's password from the activeSync RA. The password is encrypted in Active Directory and you can't decrypt it.
You can read the Idm Resources Reference - Active Directory. There's a table with all the supported fields; the userPassword field is write-only.
If you want to take the AD password and send it to IDM, you want to use Password Sync.
Good luck

Random password

dear friends,
please tell me how to generate random password using empno from emp table both from frontend forms and through plsql.

Look at this.. I wrote this to generate password for one of the jobs that we run every 90 days..
CREATE OR REPLACE procedure GENERATE_RANDOM
IS
cursor c1 is
select username
from password_age where FLAG='Y';
V_Random_number binary_integer;
V_Prefix varchar2(4);
V_Password varchar2(9);
begin
FOR crec IN c1
LOOP
V_Random_number := dbms_random.random;
V_Password := substr(to_char(abs(V_Random_number)),1,5);
V_Prefix := substr(to_char(sysdate,'DAY'),2,1)||to_char(add_months(sysdate,substr(V_Random_number,2,3)),'MON');
Update password_age set passwd = V_Prefix||V_Password where username = crec.username;
commit;
END LOOP;
end;
/

Random Password Generator

Hi everyone, I made this Password Generator that does what I want, but I'd like to extend its functionality. Right now it creates a random password from an array of letters and numbers.
import java.io.*;
import javax.swing.*;
import java.util.*;
*Version 0.1:
*creates several random passwords using numbers,
*uppercase and lowercase letters
*Version 0.2:
*add a save feature
public class PasswordGeneratorV02
    public static void main(String[] args)
         * Define all variables and create all objects here
        // create the Number and Letter arrays
        Integer[] numberList = new Integer[10];
        String[] letterList = new String[12];
        //Variable to continue the while loop
        Boolean cont = true;
        //Scanner used to continue or not
        Scanner input = new Scanner(System.in);
        //Stores the user input
        String answer;
         * End variables
        //fill the letterList array
        //need to find a more efficient way to do this
        //and add all the letters of the alphabet
        letterList[0] = "a";
        letterList[1] = "F";
        letterList[2] = "c";
        letterList[3] = "R";
        letterList[4] = "y";
        letterList[5] = "O";
        letterList[6] = "p";
        letterList[7] = "W";
        letterList[8] = "q";
        letterList[9] = "n";
        letterList[10]= "E";
        letterList[11]= "w";
        // fill it with numbers 0-9
        for (int i=0; i < numberList.length; i++)
            numberList= i;
// make both arrays lists so we can shuffle them
List list = Arrays.asList(numberList);
List list2 = Arrays.asList(letterList);
//Start the output to user
System.out.println("Welcome to the random password generator!");
System.out.println("This program will create a random 20 character alphanumeric password.");
System.out.println();
//Shuffles the array contents then prints it out.
while(cont == true)
// shuffle the list
Collections.shuffle(Arrays.asList(numberList));
Collections.shuffle(Arrays.asList(letterList));
// print out the shuffled array contents
for (int i : numberList)
System.out.print(i + letterList[i]);
System.out.println();
System.out.println("Press Enter for a new password. Q to quit.");
answer = input.nextLine();
//check to see if user wants to quit
if(answer.equalsIgnoreCase("q"))
cont = false;
System.out.println("Goodbye...");
}I would like to change/add two things.
1st, I want to change the array of letters to include the full alphabet(lower and uppercase), with out having to type it in.
2nd, I would like to add a save feature where the user types in "S" at the prompt and it will allow them to save the password as a text file.
Thanks in advance.

Ok well, I googled around and found something.
The output now displays letters, but it no longer shuffles them around. For example:
6A8B7C4D2E0F5G1H3I9J
Every letter is just the next letter in the alphabet. How would I shuffle an array of chars?
New code:
import java.io.*;
import javax.swing.*;
import java.util.*;
*Version 0.1:
*creates several random passwords using numbers,
*uppercase and lowercase letters
*Version 0.2:
*add a save feature
public class PasswordGeneratorV02
    public static void main(String[] args)
         * Define all variables and create all objects here
        // create the Number and Letter arrays
        Integer[] numberList = new Integer[10];
        char[] letterList = "ABCDEFGHIJKLMNOPQRSTUWVXYZabcdefghijklmnpqrstuvwxyz".toCharArray();
        //Variable to continue the while loop
        Boolean cont = true;
        //Scanner used to continue or not
        Scanner input = new Scanner(System.in);
        //Stores the user input
        String answer;
         * End variables
        // fill it with numbers 0-9
        for (int i=0; i < numberList.length; i++)
            numberList= i;
// make both arrays lists so we can shuffle them
List list = Arrays.asList(numberList);
List list2 = Arrays.asList(letterList);
//Start the output to user
System.out.println("Welcome to the random password generator!");
System.out.println("This program will create a random 20 character alphanumeric password.");
System.out.println();
//Shuffles the array contents then prints it out.
while(cont == true)
// shuffle the list
Collections.shuffle(Arrays.asList(numberList));
Collections.shuffle(Arrays.asList(letterList));
// print out the shuffled array contents
for (int i=0;i<numberList.length;i++)
System.out.print(numberList[i] + String.valueOf(letterList[i]));
System.out.println();
System.out.println("Press Enter for a new password. Q to quit.");
answer = input.nextLine();
//check to see if user wants to quit
if(answer.equalsIgnoreCase("q"))
cont = false;
System.out.println("Goodbye...");

Generating a random password and sending a userid through mail to the user

HI,
I have a field named UserID in the process form,this user id can only be accessed by the GIA PROVISIONING ANALYST for updation of the userid to provision the resource to some related id of the user .I want to send this user ID from the process form in a mail to the target user,moreover i also want to include a password field nd also send a random password to the user.In short i want to obtain the values of user id and password send it in a email to the target user

This is the body of my email template:
Request number: <Request Information.Request ID>
The following access has been granted:
Name: <Request Information.List of user targets being requested for>
ID: <User Profile Information.User Login>
Resource: <Object Information.Object Name>
Updated UserID:<Process Data Information.RSS User Name>
In this case the "Updated UserID " is to be obtained from the Process Form and has to be sent in the mail.
"RSS User Name" is the field label in the process form.when this email is sent iam not able to retrieve the values .The same statement ie."Updated UserID:<Process Data Information.RSS User Name>" is displayed in the email .
I have even tried giving <Process Information.RSS User Name> and <Process Data Information.Process Name.RSS User Name> still the value is not obtained.Plz guide me through this.

Disable random Password generation button on Reset Password popup window.

Hi ALL,
We have a new requirement when user click on reset password tab on "Modify User" page, a pop up window will open with two options :
1) Manually change the Password
2) Auto-generate the Password (Randomly generated)
I want to remove or disable this 2nd option. Can you please guide me what necessary changes required?
Thanks,
Amit

It's easy enough to generate a random password. Use a
constant string containing your alphabet (different
systems have different rules about what characters
are allowed). Then us Random first to generate a
suitable length, then to pick a character from your
alphabet for each slot. If there are further rules
(e.g. "must contain at least one digit") then check
the password you've just generated and if it fails
the test, simply try again.
But this isn't a particularly good system. It allows
anyone to harrass a user by changing their password
if they can guess their user name.
The approach I favour is to send the user a one-time
click-thru URL in an e-mail which allows them to set
their password to anything they chose. That needs a
special table in some data base. You generate a
random token which acts as a one-shot password on a
special "change password" page. As soon as the click
through has been used then the database entry is
deleted so that the token is invalidated. You should
also invalidate the token if they log on in the
normal way.I agree that the 'forgot your password' feature is nasty. I mean, we are normally enjoined from saying "invalid user id" or "invalid password", we have to say "invalid user id / password combination" or something to that effect. But by providing the 'forgot your password' feature, it would be trivial to write a bot to see which sites provide this, determine a good page from a bad (e.g., valid user id) and then have an easier time brute-forcing the password. Sad.
On the other hand, I know personally that many companies are concerned with phishing attacks on their customers. As such, they have a blanket policy prohibiting any URL that hits a secured page in any way.
So, what to do? :^(
- Saish

Random password generation

Hi All,
We have a link on login page "Forgot Password" ?
As users clicks the link, idea is he goes to page that has emails address and submit button.
As user enters his emails address and clicks submit, the mechanism gemerates a new password and sends it over to his email address.
My question is, "I dont know how to generate that new random password."
Is there a code around, that I can use ?
thanks a lot,
pp

It's easy enough to generate a random password. Use a
constant string containing your alphabet (different
systems have different rules about what characters
are allowed). Then us Random first to generate a
suitable length, then to pick a character from your
alphabet for each slot. If there are further rules
(e.g. "must contain at least one digit") then check
the password you've just generated and if it fails
the test, simply try again.
But this isn't a particularly good system. It allows
anyone to harrass a user by changing their password
if they can guess their user name.
The approach I favour is to send the user a one-time
click-thru URL in an e-mail which allows them to set
their password to anything they chose. That needs a
special table in some data base. You generate a
random token which acts as a one-shot password on a
special "change password" page. As soon as the click
through has been used then the database entry is
deleted so that the token is invalidated. You should
also invalidate the token if they log on in the
normal way.I agree that the 'forgot your password' feature is nasty. I mean, we are normally enjoined from saying "invalid user id" or "invalid password", we have to say "invalid user id / password combination" or something to that effect. But by providing the 'forgot your password' feature, it would be trivial to write a bot to see which sites provide this, determine a good page from a bad (e.g., valid user id) and then have an easier time brute-forcing the password. Sad.
On the other hand, I know personally that many companies are concerned with phishing attacks on their customers. As such, they have a blanket policy prohibiting any URL that hits a secured page in any way.
So, what to do? :^(
- Saish

Random Passwords

Hi all,
I need to change the random password function in portal.
I need to generate passwords with 8 characters but the standard function generates with 14 characters.
I've already changed the password policy to minimum and maximum of 8 characters in password, but the system still generates wrong passwords (14 characters).
I need to generate a password with 8 characters, that ones 5 numbers and 3 lower case letters.
How can I change this? Anyone could help me?
Tks

You need to customize your UME security Policy.
Go the below link and follow the SAP recommendations.
http://help.sap.com/saphelp_nw70/helpdata/EN/0a/065e4278636255e10000000a155106/frameset.htm
Here you can chnge the exiting config of ume.logon.security_policy.password_min_length.

How do I get Keychain to generate a password for me? It does not ask to do so automatically anymore.

Originally, Keychain would automatically offer to create a random password for me. After refusing the offer many times, Keychain no longer offers anymore for any of my regular websites. How do I get it to offer again?

Open Keychain Access.
Select the desired item in the list,
Double click the item or use 'File > Get info'.
Click the checkbox to reveal the current password & enter your keychain password to view it.
Now click the 'key' icon next to the password field.
The 'password assistant' window appears, use that to to generate a password, when you are happy with it click the 'Save changes' button in the 'info' window for that item.

How to lock a user by using random password?

hello,
i need to lock a user from a target system by pushing in random passwords for the accounts. i am successfully able to create an adapter that can generate a random string, but the place where i am stuck is that where to use it as i just need to lock the user and not delete it. if the corresponding manager approves the suspension then the account needs to be deleted else again the account needs to be enabled.
Please help!
Thanks!

ok... sorry...
so what i did is that i have created a resource that has to be provisioned to the user if the user is to be terminated, in which the manager will mention the user to be terminated and the reason.
now OIM has to lock the user till the reason that has been given by the manager is deemed valid by the second level manager.
so for that i have a approval and a process form and processes associsted with them. but the problem is that i need to lock the user using the "Entity Adapter" so i need to do so only in the "Data Object Manager" and thus the problem starts as i dont know where to map the adapter that generates the random password so as to lock the user.
please, if you find anything confusing here, go thru the discussion in the whole of the thread.
Thanks!

Generate Random Password by policy

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