Generating xml from oracle table

Question

Hi,
I want to generate xml form an oracle table and using sql developer, oracle express 10g, xdk forler is also unzipped under oracle express folder, still getting following error: code used
var g_clob clob;
declare
     l_ctx  dbms_xmlquery.ctxHandle;
     l_clob clob;
    begin
      l_ctx := dbms_xmlquery.newContext('select * from scott.emp');
      dbms_lob.createtemporary(:g_clob,true,dbms_lob.session);
      :g_clob := dbms_xmlquery.getXml(l_ctx);
    end;
    /ORA-06550: line 2, column 14:
PLS-00201: identifier 'DBMS_XMLQUERY.CTXHANDLE' must be declared
Thanks in advance

Answer 1

Hi,
DBMS_XMLQUERY is a wrapper for methods from the Java class "oracle.xml.sql.query.OracleXMLStaticQuery".
The problem is that Oracle 10g XE doesn't have a JVM, so you can't use this package.
Use DBMS_XMLGEN instead, it provides similar functionalities and is more efficient (C-based) :
SQL> var g_clob clob
SQL> DECLARE
  2    l_ctx    dbms_xmlgen.ctxHandle;
  3  BEGIN
  4    l_ctx := dbms_xmlgen.newContext('select * from scott.emp');
  5    :g_clob := dbms_xmlgen.getXML(l_ctx);
  6    dbms_xmlgen.closeContext(l_ctx);
  7  END;
  8  /
PL/SQL procedure successfully completed.
SQL> set long 5000
SQL> set pages 1000
SQL> print g_clob
G_CLOB
<?xml version="1.0"?>
<ROWSET>
<ROW>
  <EMPNO>7369</EMPNO>
  <ENAME>SMITH</ENAME>
  <JOB>CLERK</JOB>
  <MGR>7902</MGR>
  <HIREDATE>17/12/80</HIREDATE>
  <SAL>800</SAL>
  <DEPTNO>20</DEPTNO>
</ROW>
<ROW>
  <EMPNO>7499</EMPNO>
  <ENAME>ALLEN</ENAME>
  <JOB>SALESMAN</JOB>
  <MGR>7698</MGR>
  <HIREDATE>20/02/81</HIREDATE>
  <SAL>1600</SAL>
  <COMM>300</COMM>
  <DEPTNO>30</DEPTNO>
</ROW>
<ROW>
  <EMPNO>7521</EMPNO>
  <ENAME>WARD</ENAME>
  <JOB>SALESMAN</JOB>
  <MGR>7698</MGR>
  <HIREDATE>22/02/81</HIREDATE>
  <SAL>1250</SAL>
  <COMM>500</COMM>
  <DEPTNO>30</DEPTNO>
</ROW>
<ROW>
  <EMPNO>7566</EMPNO>
  <ENAME>JONES</ENAME>
  <JOB>MANAGER</JOB>
  <MGR>7839</MGR>
  <HIREDATE>02/04/81</HIREDATE>
  <SAL>2975</SAL>
  <DEPTNO>20</DEPTNO>
</ROW>
<ROW>
  <EMPNO>7654</EMPNO>
  <ENAME>MARTIN</ENAME>
  <JOB>SALESMAN</JOB>
  <MGR>7698</MGR>
  <HIREDATE>28/09/81</HIREDATE>
  <SAL>1250</SAL>
  <COMM>1400</COMM>
  <DEPTNO>30</DEPTNO>
</ROW>
<ROW>
  <EMPNO>7698</EMPNO>
  <ENAME>BLAKE</ENAME>
  <JOB>MANAGER</JOB>
  <MGR>7839</MGR>
  <HIREDATE>01/05/81</HIREDATE>
  <SAL>2850</SAL>
  <DEPTNO>30</DEPTNO>
</ROW>
<ROW>
  <EMPNO>7782</EMPNO>
  <ENAME>CLARK</ENAME>
  <JOB>MANAGER</JOB>
  <MGR>7839</MGR>
  <HIREDATE>09/06/81</HIREDATE>
  <SAL>2450</SAL>
  <DEPTNO>10</DEPTNO>
</ROW>
<ROW>
  <EMPNO>7839</EMPNO>
  <ENAME>KING</ENAME>
  <JOB>PRESIDENT</JOB>
  <HIREDATE>17/11/81</HIREDATE>
  <SAL>5000</SAL>
  <DEPTNO>10</DEPTNO>
</ROW>
<ROW>
  <EMPNO>7844</EMPNO>
  <ENAME>TURNER</ENAME>
  <JOB>SALESMAN</JOB>
  <MGR>7698</MGR>
  <HIREDATE>08/09/81</HIREDATE>
  <SAL>1500</SAL>
  <COMM>0</COMM>
  <DEPTNO>30</DEPTNO>
</ROW>
<ROW>
  <EMPNO>7900</EMPNO>
  <ENAME>JAMES</ENAME>
  <JOB>CLERK</JOB>
  <MGR>7698</MGR>
  <HIREDATE>03/12/81</HIREDATE>
  <SAL>950</SAL>
  <DEPTNO>30</DEPTNO>
</ROW>
<ROW>
  <EMPNO>7902</EMPNO>
  <ENAME>FORD</ENAME>
  <JOB>ANALYST</JOB>
  <MGR>7566</MGR>
  <HIREDATE>03/12/81</HIREDATE>
  <SAL>3000</SAL>
  <DEPTNO>20</DEPTNO>
</ROW>
<ROW>
  <EMPNO>7934</EMPNO>
  <ENAME>MILLER</ENAME>
  <JOB>CLERK</JOB>
  <MGR>7782</MGR>
  <HIREDATE>23/01/82</HIREDATE>
  <SAL>1300</SAL>
  <DEPTNO>10</DEPTNO>
</ROW>
</ROWSET>Or, using SQL/XML functions :
SELECT XMLElement("ROWSET",
         XMLAgg(
           XMLElement("ROW",
             XMLForest(empno, ename, job, mgr, hiredate, sal, comm, deptno)
       ).getClobVal()
FROM scott.emp
;