Get file name of running file
I simply want to know what is the filename of the running file
i.e.String findFileName(){
//return this program's file name somehow
}If you are wondering why do I want to know this, then here you are:
I'm making a feature for downloading the latest version of the application and then replacing the old version with the new one.
Any help?
MariusGav wrote:
I'm making a feature for downloading the latest version of the application and then replacing the old version with the new one.Do you mean just like java web start? Perhaps you should look at how this works and either use it or learn from it.
I simply want to know what is the filename of the running fileIs that the class file, the jar file or the source file? Files don't run. Threads run code in class methods.
If you are wondering why do I want to know this, then here you are:You can try
URL urlForThisClass = getClass().getProtectionDomain().getCodeSource().getLocation();
Similar Messages
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can not transfer date from one hard drive to another, I keep getting an error because I have two of the same file names and one file name is in caps and I cant change the file name. My original external has an error and needs to be reformatted but I dont want to lose this informations its my entire Itunes library.
Sounds like the source drive is formatted as case sensitive and the destination drive is not. The preferred format for OS X is case insensitive unless there is a compelling reason to go case sensitive.
Why can't you change the filename? Is it because the source drive is having problems? If so is this happening with only one or two or a few files? If so the best thing would be to copy those over individually and then rename them on the destination drive.
If it is more then you can do manually and you can't change the name on the source you will have to reformat the destination as case sensitive.
Btw this group is for discussion of the Support Communities itself, you;d do better posting to Lion group. I'll see if a host will move it. -
I have the code to read from a file but my problem is how to prompt the user for the file name at run time.
import java.io.File;
import java.io.FileNotFoundException;
import java.util.InputMismatchException;
import java.util.Scanner;
public class FileRead {
public static void main(String args[]) {
Scanner scan = null;
File file = new File("Results.txt");
String number;
try {
scan = new Scanner(file);
while (scan.hasNext()){
number = scan.next();
System.out.println(number);}
catch (FileNotFoundException ex1){
System.out.println("No such file");
catch (IllegalStateException ex2){
System.out.println("Did you close the read by mistake");
catch (InputMismatchException ex){
System.out.println("File structure incorrect");
finally{
scan.close();}
}Any hints would be greatly appreciated. Thank you in advanceI have read through some of the tutorials that you have directed me too and they are very useful, thank you. however there are still a few things that i am not clear about. I am using net beans 5.0 I have placed a text file named Results.txt into the project at the root so the program can view it.
When I use the code that you provided me with, does it matter where the file is, or will it look through everywhere on the hard drive to find a match?
This code compiles but at run time it comes up with this error
run-single:
java.lang.NoClassDefFoundError: NamedFile
Exception in thread "main"
Java Result: 1
BUILD SUCCESSFUL (total time: 3 seconds)
import java.util.Scanner;
import java.io.*;
class NamedFileInput
public static void main (String[] args) throws IOException
int num, square;
// this Scanner is used to read what the user enters
Scanner user = new Scanner( System.in );
String fileName;
System.out.print("File Name: ");
fileName = user.nextLine().trim();
File file = new File( fileName ); // create a File object
// this Scanner is used to read from the file
Scanner scan = new Scanner( file );
while( scan.hasNextInt() ) // is there more data to process?
num = scan.nextInt();
square = num * num ;
System.out.println("The square of " + num + " is " + square);
}his is the code that i used. It is the same as the code you posted for me (on chapter 23 I/O using Scanner and PrintStream) Sorry im just really stuck on this!! -
Need of a Webservice to get the name of the file in a Folder
Hi All,
I am in need of a Web service which should get the name of the file in a folder.
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Can we get the name of fmx file at runtime
Hi all,
can we get the name of fmx file which is doing some DML operation on a specific table Can we back track which fmx module has done DML on a specific table. The reason I need this because I've 7 different fmx files which are doing some DML operation on a specific table and these fmx files were used by different users. Not necessarily 1:1 For eg. one user can do DML through 3 different fmx files. So in such case if I want to want to know from which fmx file this DML has take place .How can I achieve that. I know I can get the oracle username through v$session but it will not suffice my needs. I need the name of fmx file also.
I'm using:
Forms [32 Bit] Version 10.1.2.0.2 (Production)
Oracle Database 10g Release 10.2.0.1.0 - Production
PL/SQL Release 10.2.0.1.0 - Production
CORE 10.2.0.1.0 Production
TNS for 32-bit Windows: Version 10.2.0.1.0 - Production
NLSRTL Version 10.2.0.1.0 - Production
Any help?
Warm Regards
PercyPercy,
For that you can set the Module Field in the V$session in each form by,
DBMS_APPLICATION_INFO.SET_MODULE(MODULE_NAME => :SYSTEM.CURRENT_FORM, ACTION_NAME => USER);Write this in each form, and then you will get the form name in the V$SESSION's module field with form name.
Hope this helps.
Regards,
Manu. -
How do U to get the names of all files in a directory?
Is there a simple way to get all names of the files in a directory and put them in an array of Strings? Sounds simple, but I don't have a clue how to do this. Thanks.
Hi Kindoo,
Create a instance of File object using the path of the Directory
File fileDir = new File(directoryPath);
To get the List of all the files in the directory use
String[] strFiles = fileDir.list();
This will solve your problem,
Cheers
Nagaraj -
How to get _pageLabel name in jpf file?
hi,
i need to get _pageLabel name in .jpf file
if any one knows, please reply
jphi,
already this isse solved.
please donot reply
jp -
When downloading, previously Firefox would show a number at the end of the file name (renaming the file by adding a number) showing that I had already downloaded a file at least once. Now that isn't happening. How do I get that feature back?
When downloading, previously Firefox would show a number at the end of the file name (renaming the file by adding a number) showing that I had already downloaded a file at least once. Now that isn't happening. How do I get that feature back?
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Get Logical file name from Physical file name
Hi everybody,
Please how can i get Logical file name from Physical file name ?
Thanks & Regards
HassanHi,
What i want is to get Logical file name from Physical file name, and not the opposite (get Physical file name from Logical file name).
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Hassan -
File name conflict in File Download filter in Policy Studio
Hi,
I am trying to use File Download filter to download the file from sftp server and saving it on local machine using Save to File filter. File format is ABC_MMDDYYYY,zip
i need to get the name of the file at run time. what would be Attribute Selector i should use in File Download filter for File name. I tried ABC_${date}
but its not able to understand that format. i tried lot nothing seems to be working.
Please help.i am Getting Auth Fail error in trace logs when creating Policy for SFTP File Download and Saving it.
Problem Description
Getting Auth Fail error in trace logs when creating Policy for SFTP File Download and Saving it on server.
Steps to Reproduce
1. Create a policy with Add HTTP Header and FileDownload filter with SFTP server details (need to specify fingerprint)
2.Add Save to File filter with correct path and file name.
3.Add scheduler that runs after every 20 sec
4.Verify file at Save location and check trace logs. -
How to put the file name in notepad file
dear frank,
how to put the file name in notepad file via power shell. I mean i want to put the file name in that notepad file
for example,
my file name is ABL and in this file data is
02/06/2015,180.00,182.00,176.01,180.50,1575500
02/06/2015,4.20,4.20,4.20,4.20,500
02/06/2015,113.50,113.70,112.91,113.09,157800
02/06/2015,682.01,695.90,682.00,683.19,4250
02/06/2015,213.98,215.00,213.00,214.87,326200
02/06/2015,21.52,21.65,21.52,21.60,4000
02/06/2015,111.00,111.25,108.25,108.91,17100
02/06/2015,52.00,52.00,52.00,52.00,500
and i want to data in this form
ABL,02/06/2015,180.00,182.00,176.01,180.50,1575500
ABL,02/06/2015,4.20,4.20,4.20,4.20,500
ABL,02/06/2015,113.50,113.70,112.91,113.09,157800
ABL,02/06/2015,682.01,695.90,682.00,683.19,4250
ABL,02/06/2015,213.98,215.00,213.00,214.87,326200
ABL,02/06/2015,21.52,21.65,21.52,21.60,4000
ABL,02/06/2015,111.00,111.25,108.25,108.91,17100
ABL,02/06/2015,52.00,52.00,52.00,52.00,500
There are many file like this that i want to be edit
plese tell me how can i do it, i think it is possible via windows power shell.
thanks in advance.Hi
Just for completeness, what version of VB.NET are you using?
Here is a complete project to copy all the files with the added "ABL," at the start of each line. You need to start a new Project with a BLANK default Form1, and replace all of Form1 code with the code below. When you run this project, you
need to use the 2 buttons to set up the ORIGINAL file folder and a folder to place the copies. You need to check if the file EXTENSION is correct (I assumed txt), and check the text to add to each line is correct. Once all is set up you should have a
big red button to start the operation.
NOTE: it is important that you try this out on a copy of some of the files to verify accuracy BEFORE trying on original files. Make sure you have a good back up of the original files before doing anything else.
' new project with default BLANK Form1
' replace all Form1 code with this code
' WARNING: make sure you have a backup of
' any files you use this application to
' operate on.
Option Strict On
Option Infer Off
Option Explicit On
Public Class Form1
Dim OrigFileFolderPath As String = Nothing
Dim CopyToFolderPath As String = Nothing
Dim lab1, lab2, lab3 As New Label
Dim tb1, tb2, tb3 As New TextBox
Dim b1, b2, b3, b4 As New Button
Dim fb As New FolderBrowserDialog
Dim bgw As New System.ComponentModel.BackgroundWorker
Private Sub Form1_Load(sender As Object, e As EventArgs) Handles Me.Load
Me.Size = New Size(731, 300)
With lab1
.Text = "Original Files Folder Path"
.Location = New Point(15, 5)
End With
With tb1
.Width = 560
.Location = New Point(10, 30)
.BackColor = Color.Khaki
.ForeColor = Color.Maroon
.Font = New Font(Me.Font.FontFamily, 12)
.BorderStyle = BorderStyle.FixedSingle
.Anchor = AnchorStyles.Top Or AnchorStyles.Left Or AnchorStyles.Right
End With
With lab2
.Text = "Copy Files to Folder Path"
.Location = New Point(15, 125)
End With
With tb2
.Width = 665
.Location = New Point(10, 150)
.BackColor = Color.Khaki
.ForeColor = Color.Maroon
.Font = New Font(Me.Font.FontFamily, 12)
.BorderStyle = BorderStyle.FixedSingle
.Anchor = AnchorStyles.Top Or AnchorStyles.Left Or AnchorStyles.Right
End With
With lab3
.Text = "File Ext"
.Location = New Point(600, 5)
.Anchor = AnchorStyles.Top Or AnchorStyles.Right
End With
With tb3
.Text = ".txt"
.Width = 80
.Location = New Point(590, 30)
.BackColor = Color.Khaki
.ForeColor = Color.Maroon
.TextAlign = HorizontalAlignment.Center
.Font = New Font(Me.Font.FontFamily, 12)
.BorderStyle = BorderStyle.FixedSingle
.Anchor = AnchorStyles.Top Or AnchorStyles.Right
End With
With b1
.Text = "Choose Original Files Folder Path"
.AutoSize = True
.Location = New Point(10, 65)
End With
With b2
.Text = "Choose Copy Files to Folder Path"
.AutoSize = True
.Location = New Point(10, 185)
End With
With b3
.Text = "DO THE COPY"
.AutoSize = False
.Size = New Size(240, 50)
.BackColor = Color.Red
.ForeColor = Color.White
.Font = New Font(Me.Font.FontFamily, 20, FontStyle.Bold)
.Location = New Point(420, 80)
.Anchor = AnchorStyles.Top Or AnchorStyles.Right
.Visible = False
End With
With b4
.Text = "CANCEL JOB"
.AutoSize = False
.Size = New Size(240, 50)
.BackColor = Color.Red
.ForeColor = Color.White
.Font = New Font(Me.Font.FontFamily, 20, FontStyle.Bold)
.Location = New Point(420, 80)
.Anchor = AnchorStyles.Top Or AnchorStyles.Right
.Visible = False
End With
Me.Controls.AddRange({lab1, lab2, lab3, tb1, tb2, tb3, b1, b2, b3, b4})
With bgw
.WorkerReportsProgress = True
.WorkerSupportsCancellation = True
End With
AddHandler bgw.DoWork, AddressOf bgw_DoWork
AddHandler bgw.RunWorkerCompleted, AddressOf bgw_Completed
AddHandler b1.Click, AddressOf b1_Click
AddHandler b2.Click, AddressOf b2_Click
AddHandler b3.Click, AddressOf b3_Click
AddHandler b4.Click, AddressOf b4_Click
End Sub
Private Sub b1_Click(sender As Object, e As EventArgs)
fb.SelectedPath = My.Computer.FileSystem.SpecialDirectories.MyDocuments
fb.ShowNewFolderButton = False
Dim r As DialogResult = fb.ShowDialog
If r = Windows.Forms.DialogResult.OK Then
tb1.Text = fb.SelectedPath
If IO.Directory.Exists(tb1.Text) AndAlso IO.Directory.Exists(tb2.Text) AndAlso Not (tb1.Text = tb2.Text) Then
If tb3.Text = Nothing Then
redo: tb3.Text = InputBox("Enter the file extension that you want to copy/change", "FILE EXTENSION")
If tb3.Text = Nothing Then GoTo redo
End If
b3.Visible = True
Else
b3.Visible = False
End If
End If
End Sub
Private Sub b2_Click(sender As Object, e As EventArgs)
fb.SelectedPath = My.Computer.FileSystem.SpecialDirectories.MyDocuments
fb.ShowNewFolderButton = True
Dim r As DialogResult = fb.ShowDialog
If r = Windows.Forms.DialogResult.OK Then
tb2.Text = fb.SelectedPath
If IO.Directory.Exists(tb1.Text) AndAlso IO.Directory.Exists(tb2.Text) AndAlso Not (tb1.Text = tb2.Text) Then
If tb3.Text = Nothing Then
redo: tb3.Text = InputBox("Enter the file extension that you want to copy/change", "FILE EXTENSION")
If tb3.Text = Nothing Then GoTo redo
End If
b3.Visible = True
Else
b3.Visible = False
End If
End If
End Sub
Private Sub b3_Click(sender As Object, e As EventArgs)
b3.Visible = False
b4.Visible = True
If Not tb3.Text.StartsWith(".") Then tb3.Text = "." & tb3.Text
bgw.RunWorkerAsync()
End Sub
Private Sub b4_Click(sender As Object, e As EventArgs)
bgw.CancelAsync()
End Sub
Private Sub ReadPWFile(fn As String)
Dim filename As String = My.Computer.FileSystem.GetName(fn)
Dim barename As String = IO.Path.GetFileNameWithoutExtension(fn)
Dim copyto As String = tb2.Text & "\" & filename
Dim line As String = Nothing
Dim lines As New List(Of String)
Using sr As IO.StreamReader = New IO.StreamReader(fn)
Do
line = sr.ReadLine()
If Not line = Nothing Then
lines.Add(barename & "," & line)
End If
Loop Until line = Nothing
End Using
Using sw As IO.StreamWriter = New IO.StreamWriter(copyto)
For Each s As String In lines
sw.WriteLine(s)
Next
End Using
End Sub
Private Sub bgw_DoWork(sender As Object, e As System.ComponentModel.DoWorkEventArgs)
Dim ftc As Collections.ObjectModel.ReadOnlyCollection(Of String) = My.Computer.FileSystem.GetFiles(tb1.Text)
For Each f As String In ftc
If bgw.CancellationPending Then
e.Cancel = True
Exit For
End If
Dim ex As String = My.Computer.FileSystem.GetFileInfo(f).Extension.ToLower
If My.Computer.FileSystem.GetFileInfo(f).Extension.ToLower = tb3.Text.ToLower Then
ReadPWFile(f)
End If
Next
End Sub
Public Sub bgw_Completed(sender As Object, e As System.ComponentModel.RunWorkerCompletedEventArgs)
tb1.Text = Nothing
tb2.Text = Nothing
b3.Visible = False
b4.Visible = False
MessageBox.Show("Finished copying files", "Job Completed")
End Sub
End Class
Regards Les, Livingston, Scotland -
Change File Name In The "File Download" Dialog Box For Web Reports
Hi All ,
I followed the below note to change the "File Download" name.
How To Change The File Name In The "File Download" Dialog Box For Web Reports? Doc ID: Note:418366.1
However its not working. Has anyone tried this and works fine ?
Basically I wanted to change the name "rwservlet" when a report is run in an
excel format.
Rajesh Alex
Rajesh AlexHello,
Have you checked if a HTTP header "Content-disposition" is returned ?
You can use ieHTTPHEaders for IE
http://www.blunck.se/iehttpheaders/iehttpheaders.html
and
Live HTTP Headers for FireFox
https://addons.mozilla.org/en-US/firefox/addon/3829
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Hi All,
I have a requirement to send the two file from the third party system(GXS) to SAP ECC via SAP PI(version - 7.4). We are using AS2 adapter at the sender side to pick the file and using File Adapter to place the file in ECC.
Its a pass through scenarion(No ESR part is used).
Requirement:
We are going to get 2 files ->Example: one from Axis and another one from ICICI -> each bank file will have a file name ->
We have to post the file at the target system with the same name as source file name, the source file name could come dynamically(with diff time stamp).
Please let me know, Is it possible to achieve the above requirement(we have to retain the file name in target that coming from source system) with Sender AS2 adapter, If yes then please suggest the best approach.
Regards,
Pradeep BawliaHi Guys,
The above requirement is solved now.
Solution - I used java mapping for extracting the same source file name and assignning the same to the target system.
Code:
public class ExtractFileName_ASMA extends AbstractTransformation{
public void transform(TransformationInput in, TransformationOutput out) throws StreamTransformationException
DynamicConfiguration conf=in.getDynamicConfiguration();
DynamicConfigurationKey key_AS2FileNmae = DynamicConfigurationKey.create("http://sap.com/xi/XI/AS2/AS2", "AS2Filename");
DynamicConfigurationKey key_FileNmae = DynamicConfigurationKey.create("http:/"+"/sap.com/xi/XI/System/File", "FileName");
String As2FileName=conf.get(key_AS2FileNmae);
conf.put(key_FileNmae, As2FileName);
try{
byte b[]=new byte[in.getInputPayload().getInputStream().available()];
in.getInputPayload().getInputStream().read(b);
out.getOutputPayload().getOutputStream().write(b);
catch(Exception e)
2. Another solution we can use the graphical mapping and need to use the dynamic config UDF at mapping level to acheive this requirement but here is one drawback - we need to do content conversion is this case.
In case of Java mapping, no need to play with source file.
WITHOUT USING ESR, WE CAN NOT ACHEIVE THIS REQUIREMENT.
Regards,
Pradeep Bawlia -
Logical File name of Transaction File
Hi All,
I am using FILE_NAME_GET function module to get the Physical file name based on logical file name.
But here i am not getting total file name, i maintained Physical File name as ZDM\INTB18\<PARAM_1>.
Transaction File is stored in application server and it's name is ZDM\INTB18\RMCB18_DATETIME.
Could you please anybody suggest how to get total file name.
Thanks,
Rami Reddy.Hi Rami,
Have you utilised the Parameter WITH_FILE_EXTENSION in the function ... e.g.
Example
logical file name: MONTHLY_SALES_FILE
physical file name: VALUES<PARAM_1>
logical path: SALES_DATA_PATH
physical path (Windows): C:\SALES\<FILENAME>
Get file name for WINDOWS platform, with file name extension
CALL FUNCTION 'FILE_GET_NAME'
EXPORTING
LOGICAL_FILENAME = 'MONTHLY_SALES_FILE'
WITH_FILE_EXTENSION = 'X'
IMPORTING
FILE_NAME = FILE
FILE_FORMAT = FORMAT.
Result:
FILE = C:\SALES\VALUES.WK1
FORMAT = WK1
Rgds, Derrick -
Could not save as (file name) because the file could not be found
When i try saving sothing it comes up with could not save as (file name) because the file could not be found and need to save this file. i could save stuff before but not anymore if anyone could help i would be grateful
im using photoshop cs5.1
Thanks keironWe cannot know. These kinds of things are operating system errors with stuff getting blocked due to insufficient permissions, security tools interfering, network errors or whatever. Since you mentioned none of that, it's an "Ask your mom..." thing at this point, but if you provide more details, someone might be able to figure it out.
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