Get the application after launch

Question

Hi all. I'm using OSGI to launch a JavaFX application. You can see the code below (it's in scala but it is very simple).
import org.osgi.framework.{BundleContext, BundleActivator}
class BrowserBundleActivator extends BundleActivator {
  def start(context:BundleContext) {
    new Thread(new Runnable {
      def run() {
        javafx.application.Application.launch(classOf[BrowserStageManager], context.getProperty("test.instanceName"))
    }, "Browser Bundle Activator starter").start()
  def stop(context:BundleContext) {}
}The JavaFX application needs to respond to events that are coming through the BundleContext. So I need a way to call methods on the BrowserStageManager class that is created. Obviously, the Application.launch method doesn't return the BrowserStageManager so is there anyway to get it? Failing this, is there anyway to pass a class into the BrowserStageManager (rather than just strings)?
Thanks, Nick.

Answer 1

I see you are using a PPC Mac with OSX 10.5.8.
Either you can use the last release from Mozilla worked on PPC which is 3.6.*.
The current 3.6.22 is at http://www.mozilla.org/en-US/firefox/all-older.html
Or use a third-party build from http://tenfourfox.blogspot.com/2011/08/601-now-available.html
As of Firefox 4.0 and newer a '''Intel''' Mac and OSX 10.5+ is required.