Getting an ABAP error while using innerjoins.

Question

Hi,
Please find out the error in the following script.
I have two tables VBAK and VBAP and i am considering these fields.
VBAK -- ERDAT,HANDLE.
VBAP -- ERDAT.
Since ERDAT is been compared from 2 tables i.e.VBAK and VBAP, and if the dates are same then print the values of 'HANDLE' field
I have written the following program using innerjoin between 2 tables and i am geting an error saying that
""ITEM_TABLE-HANDLE" cannot be converted to a character-type field."
Please correct my program.and tell me the error.
and one more thing HANDLE field is there nly in VBAK not in VBAP.
REPORT  Z_TEST4                                 .
TYPES: BEGIN of STRUCT,
       ERDAT TYPE VBAP,
      VBAP,
      ERDAT TYPE VBAP,
       HANDLE TYPE VBAK,
END OF STRUCT.
DATA: item_table TYPE STANDARD TABLE OF STRUCT WITH HEADER LINE.
SELECT AERDAT BERDAT B~HANDLE INTO TABLE ITEM_TABLE FROM VBAP AS A
INNER JOIN VBAK AS B ON AERDAT = BERDAT.
*WHERE AERDAT = BERDAT.
IF SY-SUBRC NE 0.
WRITE: /'No Entries Found'.
ENDIF.
LOOP AT ITEM_TABLE.
       WRITE: / ITEM_TABLE-HANDLE.
       ENDLOOP.

Answer 1

Hi
Kindly check the following code:
DATA: BEGIN OF item_table OCCURS 0,
        erdat LIKE vbak-erdat,
        handle LIKE vbak-handle,
      END OF item_table.
SELECT a~erdat a~handle INTO TABLE item_table
FROM vbak AS a INNER JOIN vbap AS b
ON  b~vbeln = a~vbeln
AND b~erdat = a~erdat.
IF sy-subrc NE 0.
  WRITE: /'No Entries Found'.
ENDIF.
LOOP AT item_table.
  WRITE: / item_table-handle.
ENDLOOP.
<b>Declaration</b>
You can do the declaration of the internal table this way too...
In your declaration of the structure, you have given the whole table as a single field.
<b>Query</b>
Try the above inner join query...
Hope this helps!
best regards,
Thangesh