Getting attributes from a XML File, stored in Oracle

Hello,
my problem is the following
I have a xml file that looks like that:
<?xml version="1.0" encoding="ISO-8859-1" standalone="yes"?>
<root path="H:\musik">
<directory name="Bj�rk - Homogenic" path="H:\musik\Bj�rk - Homogenic">
<file album="Homogenic" artist="Bjoerk" comment=""
completename="Bjoerk - Hunter" genre="Techno"
name="01 - Hunter.mp3"
path="H:\musik\Bj�rk - Homogenic\01 - Hunter.mp3"
title="Hunter" year="1997"/>
<file album="Homogenic" artist="Bjoerk" comment=""
completename="Bjoerk - Joga" genre="" name="02 - Joga.mp3"
path="H:\musik\Bj�rk - Homogenic\02 - Joga.mp3" title="Joga" year="1994"/>
</directory>
<directory name="Blank & Jones - In Da Mix" path="H:\musik\Blank & Jones - In Da Mix">
<file album="In da Mix" artist="Blank & Jones" comment=""
completename="Blank & Jones - On a journey (Intro)"
genre="Dance" name="01 - On a journey (Intro).mp3"
path="H:\musik\Blank & Jones - In Da Mix\01 - On a journey (Intro).mp3"
title="On a journey (Intro)" year="1999"/>
<file album="In da Mix" artist="Blank & Jones" comment=""
completename="Blank & Jones - Cream" genre="Dance"
name="02 - Cream.mp3"
path="H:\musik\Blank & Jones - In Da Mix\02 - Cream.mp3"
title="Cream" year="1999"/>
</directory>
</root>
This file I have stored in Oracle as table of XML Type.
Now I have build a little Java Programm, that displays the XML File like the File structure in the Windows Explorer.
I want, when I choose a file in the File structure, that the ID3 Informations like album artist a.s.o. can be displayed. My problem is, I couldn't get these informations e.g. in an array from the database. Any suggestions how I could realize this in Java?
Thx for any comments
Max

Try this:
select extract(xmltypefieldname, '//xpath/field@attribute').getStringVal() from yourtable where yourwhereclause
You can also select elements that match certain attributes by using a predicate such as field[@attr = myval][@attr2 = myval2]...
Hope this helps.

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