Getting lenght of String array
Hi,
How can i find the lenght of a string array, i have used length method to calculate length of single string value,e.g
String value = "test"
int length = value.length()
Now i want to calculate length of a string array.e.g
String csv_values = "test,by,random"
String[] str = csv_values.split(",")
int lenght = str.length()
As you can see i want to calculate total number of entries in an array after i split it dynamically.
Currently it is giving me exception, "Unable to parse exception; Undefined method: length for class: [Ljava.lang.String]"
Thanks
This is a tricky one. An Array has a length property, unlike a String which has a length method.
So...
int length = str.length
Anthony Holloway
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I have table in MS Access databse called Login with two coulmn (User, Password),
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(LIKE USER = {"AA","BB","CC",........"zz"};
i made somthing like this
public class User_Name
final String driver = Login_Dialog.T_driver.getSelectedItem().toString();
final String url = Login_Dialog.T_URL.getSelectedItem().toString();
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import java.awt.*;
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Get String array from Resultset
In Tomcat 6.0.20 I am attempting to create an Oracle 9i resultset that outputs as a String array and need help creating the method.
The CityData getCityList() method will be called in the CityServlet:
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I started my below attempt but not sure how to handle the List/array part:
CityData class: public ArrayList<String> getCityList() { try { ..... List<String> citys = new ArrayList<String>(); while(rs.next()) { citys.add(rs.getString("city")); } } return citys; }Hi!
Try this:
public City[] getCitys() throws Exception
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catch (Exception e) { throw e; }
finally
try
if (stmt != null) stmt.close();
catch (Exception e) { throw e; }
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Store data in a String array getting from access table
Hai all,
i an new to java.
i have a problem regarding database connectivity, in my bean class i have written code to retrieving data from a access table. It is successfully retrieving data as System.out.println(rs.getString(rows)) is working fine but i want to store the data in String array
My code is like follows
String[ ] listTitle;
rs.next();
for(int i;i<8;i++)
rows="F"+i;
System.out.println(rs.getString(rows));
listTitle=rs.getString(rows);
when control coming to
listTitle[i]=rs.getString(rows);
it is giving some error like :::: No data found.
how to solve this any one??Hi,
U r trying to get the value two times. To avoid this store the value in variable, then manipulate.
Try this,
String[ ] listTitle;
String temp;
rs.next();
for(int i;i<8;i++)
rows="F"+i;
temp = rs.getString(rows);
System.out.println(temp);
listTitle =temp;
Regards,
Ram. -
Previous task was:
Write a class "QuestionAnalyser" which has a method "turnAnswerToScore". This method takes a String parameter and returns an int. The int returned depends upon the parameter:
parameter score
"A" 1
"B" 2
"C" 3
other 0
Alright, here's the recent task:
Write another method "turnAnswersToScore". This method takes an array of Strings as a parameter, works out the numerical score for each array entry, and adds the scores up, returning the total.
That's my code:
class QuestionAnalyser{
public static int Score;
public String[] Answer;
public static void main(String[] args) {}
public int turnAnswerToScore(String[] Answer)
for (int i = 0; i < Answer.length;i++) {
if (Answer.equals("A")) {
Score = Score + 1; }
else if (Answer[i].equals("B")) {
Score = Score + 2;}
else if (Answer[i].equals("C")) {
Score = Score + 3;}
else {
Score = Score + 0;}
return Score;
this is the error message I get:
The results of trying to compile your submission and run it against a set of test data was as follows:
----------Compilation output--------------------------------------
javac QATest2.java
QATest2.java:15: cannot resolve symbol
symbol : method turnAnswersToScore (java.lang.String[])
location: class QuestionAnalyser
if(qa.turnAnswersToScore(task)!=total){
^
What went wrong?
Suggestions would be greatly appreciated!If I declare int score in the method i get this message
The results of trying to compile your submission and run it against a set of test data was as follows:
----------Compilation output--------------------------------------
javac QATest2.java
./QuestionAnalyser.java:20: variable score might not have been initialized
score++; }
^
./QuestionAnalyser.java:23: variable score might not have been initialized
score++;
^
./QuestionAnalyser.java:27: variable score might not have been initialized
score++;
^
./QuestionAnalyser.java:34: variable score might not have been initialized
return score;
^
4 errors
----------Sorry expected answer was-------------------------------
The method turnAnswersToScore is working OK - well done!
----------Your answer however was---------------------------------
Exception in thread "main" java.lang.NoClassDefFoundError: QuestionAnalyser
at QATest2.main(QATest2.java:4)
This is the message I get from the submission page, but trying to compile it I get the same messages.
The code looks like this, then
class QuestionAnalyser{
String[] answer;
public static void main(String[] args) {}
public int turnAnswersToScore(String[] answer)
int score;
for (int i = 0; i < answer.length; i++) {
if (answer.equals("A")) {
score++; }
else if (answer[i].equals("B")) {
score++;
score++; }
else if (answer[i].equals("C")) {
score++;
score++;
score++; }
else {}
return score;
When I leave 'public int score;' where it was before (right after the class declaration below the declaration of the string array) I get this but it compiles normally.
The results of trying to compile your submission and run it against a set of test data was as follows:
----------Compilation output--------------------------------------
javac QATest2.java
----------Sorry expected answer was-------------------------------
The method turnAnswersToScore is working OK - well done!
----------Your answer however was---------------------------------
wrong answer in turnAnswersToScore for
BDCAADDCA
Alright, even university students need to sleep :-)
Good night. -
Getting null values from array
I have set up an array which is supposed to take the values of a recordset. Only problem is when I display them on the page, I get a list of 'null' instead of the data.
I'm trying to list first and last name (fname_ul & lname_ul in DB)
Here's my code:
<% // Here I'm getting the amt of rows returned
int count=1;
while(rs.next()) {
count++;
%>
<%
int k = count;
int i = 0;
String[] fname = new String[k]; // here i'm trying to initialize the string arrays;
String[] lname = new String[k];
while (rs.next()) {
fname[i] = rs.getString("fname_ul"); // here i'm trying to put data into the array;
lname[i] = rs.getString("lname_ul");
i++;
%>
<table>
<% for (i=0; i < k; i++) { %> // and finally here i'm trying to display the array;
<tr>
<td><%=fname%></td>
<td><%=lname[i]%></td>
<td><%=i%></td> // just something to make sure the rows are counting.
</tr>
<% } %>
</table>
my result is like this:
null null 0
null null 1
null null 18 // this is correct in that there are 19 rows in the resultset.
So, why isn't the data from the recordset going into the array??? Thanks for any help out there. Oh, those comments up there, they're not in the actual code, just to explain here.I have set up an array which is supposed to take the
values of a recordset. Only problem is when I display
them on the page, I get a list of 'null' instead of
the data.
I'm trying to list first and last name (fname_ul &
lname_ul in DB)
Here's my code:
<% // Here I'm getting the amt of rows returned
int count=1;
while(rs.next()) {
count++;
%>
<%
int k = count;
int i = 0;
String[] fname = new String[k]; // here i'm trying
to initialize the string arrays;
String[] lname = new String[k];
while (rs.next()) {
fname[i] = rs.getString("fname_ul"); // here i'm
trying to put data into the array;
lname[i] = rs.getString("lname_ul");
i++;
%>Well, in the first while-loop, you already loop through all the result set, so in the second while-loop, all you get is a null value.
Also, the way you put the data into the array is not right. I didn't see any array indices. Instead of using arrays, you can consider using Vector, so you don't need to know the number of rows in advance. -
Exporting a String Array to an HTML file
Hey everyone..I'm currently making lots of progress in my project...but right now I've been trying to make a button that exports my search results to an html file...basically what I've made is a search engine to search webcrawler files...
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Trying to compare string array using equals not working
Hi,
im prolly being really dumb here, but i am trying to compare 2 string arrays using the following code:
if(array.equals(copymearray))
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String array into formula node
Hello,
I am taking data from SQL, I am getting multiple rows of data for many different devices. I would like to wire the data into a formula node so I can sepearate and sort via script. However, I am getting an error for "Polymorphic terminal cannot accept this data type". Is there a work around? Can I not wire in a string array to a formula node.
/r
TravoThere are lots of basic string VIs that you can use to parse the string and separate out the individual fields. I would recommend "programming" your application using script nodes. Use the native language. LabVIEW is a fully functional and capable programming language.
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Large string array in 6.1 is extremely slow
Good day all,
While this is in to tech support at NI, I wanted to see if anyone else has encountered it.
I am upgrading from 6.0.2 to 6.1. Several large (2500 rows by 250 columns or larger) string arrays are used as inputs into subvi's. Under 6.0.2, these functions run in tenths of seconds, while under the converted 6.1 vi's they run in 20 seconds or more!
Tracing back using probes, the problem is occurring at the point of the input. It is appears that the array is taking many seconds to copy from the input to the wire on the diagram.
Array controls generated in 6.1 (not converted from 6.0.2) seem to function just fine. Using a save with options... to convert back to 6.0.2, the vi's again function in tenths of
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Thanks!I hear what you're saying about legacy code...
Something you might want to be looking at for the future is migrating to a structure where the data is stored in a 1D array, where each element is a cluster contain the data that's now in a single row. This would be the most straight-forward change, but could make getting at the data tricky, depending on how you need to be able to search it.
Alternately, you could have a cluster containing arrays of each of the row values.In this structure element 0 of all the arrays is the first "row", element 1 of the arrays is the second "row" and so on. This structure at first blush looks more complicated, but it's really not, plus it would allow you to use any value (or combination of
values) to search for a specific row without a lot of parsing.
If the data that is in the example VIs you posted is typical, either of these changes would be advantagous because it looks like there is a lot of reptative data that might be able to be encoded in an enum. Plus storing numbers as numbers often reduces the memory required and produces a predictable memory footprint (an I32 will always take-up 4 bytes per value regardless of how large of small the number is). My sense is that the variability of the string size is what's killing you.
One thing that would make this sort of dramatic change somewhat easier is that because you are changing the basic datatype of the interface, you aren't going to have to worry about finding all the places the change will effect--the wires will be broken.
If you ever decide to take this on, give a hollar.
Mike...
Certified Professional Instructor
Certified LabVIEW Architect
LabVIEW Champion
"... after all, He's not a tame lion..."
Be thinking ahead and mark your dance card for NI Week 2015 now: TS 6139 - Object Oriented First Steps -
Newbie trying to sort 2D string array
Dear all,
After read some book chapters, web sites including this, I still don't get the point.
If I have a file like,
1 aaa 213 0.9
3 cbb 514 0.1
2 abc 219 1.3
9 bbc 417 10.4
8 dee 887 2.1
9 bba 111 7.1
and I load into memory as a String[][]
here comes the problem, I sort by column 1 (aaa,...,bba) using an adaptation of the Quicksort algorithm for 2D arrays
* Sort for a 2D String array
* @param a an String 2D array
* @param column column to be sort
public static void sort(String[][] a, int column) throws Exception {
QuickSort(a, 0, a.length - 1, column);
/** Sort elements using QuickSort algorithm
static void QuickSort(String[][] a, int lo0, int hi0, int column) throws Exception {
int lo = lo0;
int hi = hi0;
int mid;
String mitad;
if ( hi0 > lo0) {
/* Arbitrarily establishing partition element as the midpoint of
* the array.
mid = ( lo0 + hi0 ) / 2 ;
mitad = a[mid][column];
// loop through the array until indices cross
while( lo <= hi ) {
/* find the first element that is greater than or equal to
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while( ( lo < hi0 ) && ( a[lo][column].compareTo(mitad)<0))
++lo;
/* find an element that is smaller than or equal to
* the partition element starting from the right Index.
while( ( hi > lo0 ) && ( a[hi][column].compareTo(mitad)>0))
--hi;
// if the indexes have not crossed, swap
if( lo <= hi )
swap(a, lo, hi);
++lo;
--hi;
/* If the right index has not reached the left side of array
* must now sort the left partition.
if( lo0 < hi )
QuickSort( a, lo0, hi, column );
/* If the left index has not reached the right side of array
* must now sort the right partition.
if( lo < hi0 )
QuickSort( a, lo, hi0, column );
* swap 2D String column
private static void swap(String[][] array, int k1, int k2){
String[] temp = array[k1];
array[k1] = array[k2];
array[k2] = temp;
----- end of the code --------
if I call this from the main module like this
import MyUtil.*;
public class kaka
public static void main(String[] args) throws Exception
String[][]a = MyUtil.fileToArray("array.txt");
MyMatrix.printf(a);
System.out.println("");
MyMatrix.sort(a,1);
MyMatrix.printf(a);
System.out.println("");
MyMatrix.sort(a,3);
MyMatrix.printf(a);
for the first sorting I get
1 aaa 213 0.9
2 abc 219 1.3
9 bba 111 7.1
9 bbc 417 10.4
3 cbb 514 0.1
8 dee 887 2.1
(lexicographic)
but for the second one (column 3) I get
3 cbb 514 0.1
1 aaa 213 0.9
2 abc 219 1.3
9 bbc 417 10.4
8 dee 887 2.1
9 bba 111 7.1
this is not the order I want to apply to this sorting, I would like to create my own one. but or I can't or I don't know how to use a comparator on this case.
I don't know if I am rediscovering the wheel with my (Sort String[][], but I think that has be an easy way to sort arrays of arrays better than this one.
I've been trying to understand the Question of the week 106 (http://developer.java.sun.com/developer/qow/archive/106/) that sounds similar, and perfect for my case. But I don't know how to pass my arrays values to the class Fred().
Any help will be deeply appreciated
Thanks for your help and your attention
Pedropublic class StringArrayComparator implements Comparator {
int sortColumn = 0;
public int setSortColumn(c) { sortColumn = c; }
public int compareTo(Object o1, Object o2) {
if (o1 == null && o2 == null)
return 0;
if (o1 == null)
return -1;
if (o2 == null)
return 1;
String[] s1 = (String[])o1;
String[] s2 = (String[])o2;
// I assume the elements at position sortColumn is
// not null nor out of bounds.
return s1[sortColumn].compareTo(s2[sortColumn]);
// Then you can use this to sort the 2D array:
Comparator comparator = new StringArrayComparator();
comparator.setSortColumn(0); // sort by first column
String[][] array = ...
Arrays.sort(array, comparator);I haven't tested the code, so there might be some compiler errors, or an error in the logic. -
Converting vector to string array
How can I convert values in a vector into a string array?
Vector formsVector = new Vector();
while (rs.next())
{formsVector.add(rs.getString("forms"));}
String forms[] = (String[])formsVector.toArray();
I tried the above line but it did not work. Any input please?
Thanks.... What is the difference between the two as
according to online help, both are same.
String forms[] = (String [])formsVector.toArray();
String forms[] = (String [])formsVector.toArray( new
String[0] );The difference lies in the type of the object returned from toArray. The first form you list, formsVector.toArray(), always returns an Object[]. In your example, you'll get a ClassCastException at runtime when you cast to String[].
The second form will try to use the array you pass in. If it's not big enough, it'll create a new one of the same type as that array. This is what's happening when passing a zero-length array into toArray.
My personal preference is to save an extra instantiation and build the array to the proper size to begin with:String forms[] = (String [])formsVector.toArray( new String[formsVector.size()] ); -
How do I read a formatted excel worksheet as a string array
I am using the report toolkit to read a excel worksheet as a LV string array. This works fine except that it reads the full precision of numeric cells (~10 digits of precision).
In my workbook I have the displayed precision set to 2. Is there any way to read the table as it is displayed instead of how it is internally stored? (BTW, I understand how to do this
manually by parsing the string array and limiting the precision myself but would prefer to use excel itself to determine the precision)
Solved!
Go to Solution.sachsm,
This should allow you to get the actual displayed text from an cell or range of cells. Kind of doing a 'Paste Special' 'Values'.
Attachments:
Read Excel Displayed Text.png 30 KB
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