Getting the date to be read in an example.

Hi,
Im using the below example for a self project:
http://zone.ni.com/devzone/cda/epd/p/id/3421
and in the example below it says you can read the date as well however I can't get this to work. I've trited a few things but everytime when I add a new point on a different date but same time as a previous point they just overlap.
The reason I am using this example is the device I have hooked up outputs data in this exact format so it works really well.
One thing is my dates are set up as :2007.02.28 not like the example as:2/28/2007
If someone could help me out in getting that graph to read the date too that would be great.
Thanks
-D

Hi Darren,
I changed the main vi of the example to also convert the date string to a number. Read the comments in the code!
I made the changes in LV6.1, with newer LabView-version you will get more possibilities like date/time data type...
Best regards,
GerdW
CLAD, using 2009SP1 + LV2011SP1 + LV2014SP1 on WinXP+Win7+cRIO
Kudos are welcome
Attachments:
Spreadsheet Time Data to Graph.vi ‏114 KB

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data : wa_p0008 like p0008,
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when others.
endcase.
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shanti.

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For this we can write a query like this..
Select empno, ename, job, mgr, sal, hiredate, deptno from emp;
Just to avoid only one column, I mentioned all the remaining ( 7 ) columns of the table in the query..
As the EMP table consists only 8 columns, it doesn't seem much difficult to mention all the columns in the query,
but if a table have 100 columns in the table, then do we have to mention all the columns in the query..?
Is there any other way of writing the query to get the required result..?
Thanks..

Your best best it to just list all the columns. Any other method will just cause more headaches and complicated code.
If you really need to list all the columns for a table because you don't want to type them, just use something like...
SQL> ed
Wrote file afiedt.buf
1 select trim(',' from sys_connect_by_path(column_name,',')) as columns
2 from (select column_name, row_number() over (order by column_id) as column_id
3        from user_tab_cols
4        where column_name not in ('COMM')
5        and   table_name = 'EMP'
6       )
7 where connect_by_isleaf = 1
8 connect by column_id = prior column_id + 1
9* start with column_id = 1
SQL> /
COLUMNS
EMPNO,ENAME,JOB,MGR,HIREDATE,SAL,DEPTNO
SQL>

How to get the Date in a particular format?

Hi,
How to get the Date in the below format? I will be passing the year in my method..
2/10/2003 9:46:52 PM
D/M/YYYY H:M:S A
public Date getDate (String year) {
Here i want to get the Date in this format
2/10/<Passed Year> 9:46:52 PM
Thanks

This is my code
public static Date getCalendar(Calendar calendar,int getYear) {
String formatted_date="";
 int year = getYear;
 int month = calendar.get(Calendar.MONTH+1);
 int day = calendar.get(Calendar.DATE);
 int hour = calendar.get(Calendar.HOUR);
 int min = calendar.get(Calendar.MINUTE);
 int sec = calendar.get(Calendar.SECOND);
 int am_pm =calendar.get(Calendar.AM_PM);
 formatted_date = month+"/"+day+"/"+year+" "+hour+":"+min+":"+sec+" PM";
 System.out.println("formatted_date is "+formatted_date);
 o/p : formatted_date is 1/4/2006 1:44:21 PM
 SimpleDateFormat dateFormat = new SimpleDateFormat("dd/MM/yyyy");
// DateFormat dateFormat =DateFormat.getDateTimeInstance(DateFormat.SHORT, DateFormat.SHORT);
 Date passdate = new Date();
 try {
 passdate = dateFormat.parse(formatted_date);
 } catch (ParseException e) {
 System.out.println("Invalid Date Parser Exception "+e.getLocalizedMessage()+"DateFormat is "+dateFormat);
 System.out.println("The Date inside the function is "+passdate+"and the year passed is "+year);
o/p : The Date inside the function is Sat Apr 01 00:00:00 IST 2006and the year passed is 2006
 return passdate;
Expected O/P is 3/1/2006 1:44:12 PM
 }

Getting the date to be read in an example.

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