Goup by in oracle vs group function in coldfusion
Hello
what is the difference between goup by in oracle vs group
function in coldfusion?
It's easier to list the similarities:
Both use the word "group".
Other than that: they're different things.
Both are well documented in their respective documentation
sources (which
are avaialble online). Suggest you read up.
Adam
Similar Messages
-
Hello does anyone know how to use the group function in
coldfusion
my tables that out-puts to a html
is outputing multiple CEENO
for example CEENO
11111
11111
11111
11111
someone here said to use the group function in coldfusion
do you know where i can put it?
<table border="2" cellpadding="2" cellspacing="0">
<tr>
<th>Record Number</th>
<TH>PEA_id</TH>
<th width="120">CEENO</th>
<TH>Address</TH>
<TH>ZipCode</TH>
<th>AdvisoryDate</th>
</tr>
<cfloop query="getthecases">
<tr bgcolor="<cfif currentrow mod
2>GHOSTWHITE<cfelse>WHITE</cfif>">
<td>#CurrentRow#</td>
<td>#PEA_id</td>
<Td>#CEENO#</td>
<td>#ST_NO# #ST_initial# #st_dir#</td>
<td>#ZipCode#</td>
<td>#dateformat(ADVISORY_DATE,"mm/dd/yyyy")#</td>
</tr>
</cfloop>
</table>What they are referencing is the group attribute of the
CFOUTPUT tag:
<cfoutput query="qryName" group="groupName">
#dbgroupvar#
<cfoutput>
#otherdbdata#
</cfoutput>
</cfoutput>
However, you have to write the correct SQL to get this to
work and that includes using the ORDER BY clause in your SQL
Statement to specify what column on which to group the output.
For example, the following query would get all employees from
the database and order them by the department for which they work:
<cfquery name="qTest" datasource="dsn">
SELECT name, title, department
FROM employee
ORDER BY department
</cfquery>
We can use the group attribute of cfoutput to show all
employees for each department:
<cfoutput query="qTest" group="department">
<h1>#department#</h1>
<table>
<cfoutput>
<tr>
<td>#name#</td>
<td>#title#</td>
</tr>
</cfoutput>
</table>
Hope this helps.
Cheers,
Craig -
Grouping error in Oracle's analytic function PERCENTILE_CONT()
Hi,
I have a question regarding the usage of Oracle's analytic function PERCENTILE_CONT(). The underlying time data in the table is of hourly granularity and I want to fetch average, peak values for the day along with 80th percentile for that day. For the sake of clarification I am only posting relevant portion of the query.
Any idea how to rewrite the query and achieve the same objective?
SELECT TRUNC (sdd.ts) AS ts,
max(sdd.maxvalue) AS max_value, avg(sdd.avgvalue) AS avg_value,
PERCENTILE_CONT(0.80) WITHIN GROUP (ORDER BY sdd.avgvalue ASC) OVER (PARTITION BY pm.sysid,trunc(sdd.ts)) as Percentile_Cont_AVG
FROM XYZ
WHERE
XYZ
GROUP BY TRUNC (sdd.ts)
ORDER BY TRUNC (sdd.ts)
Oracle Error:
ERROR at line 5:
ORA-00979: not a GROUP BY expressionYou probably mixed up the aggregate and analytical versin of PERCENTILE_CONT.
The below should work, but i dont know if it produces the desireed results.
SELECT TRUNC (sdd.ts) AS ts,
max(sdd.maxvalue) AS max_value, avg(sdd.avgvalue) AS avg_value,
PERCENTILE_CONT(0.80) WITHIN GROUP (ORDER BY sdd.avgvalue ASC) as Percentile_Cont_AVG
FROM XYZ
sorry, what is this where clause for??
WHERE
XYZ
GROUP BY TRUNC (sdd.ts)
ORDER BY TRUNC (sdd.ts) Edited by: chris227 on 26.03.2013 05:45 -
Error while using group function
Oracle forms6i
Hai
While i am compile my coding it compile successfully, but when i tried to executes i shows error in group function
my coding is
if (cnt<>0 ) then
select BARCODE,INTIME,OUTTIME into today_bar,today_in,today_out from dail_att where BARCODE= :Barcode
and ATTEND_DATE = :bardate;
update dail_att set outtime = max(:bartime) where barcode= :barcode
and ATTEND_DATE = :bardate;
else
if (cnt2<>0 ) then
select INTIME,OUTTIME into yest_in,yest_out from dail_att where BARCODE= :Barcode
and ATTEND_DATE = :bardate-1;
if(yest_in is not null and yest_out is null) then
update dail_att set outtime =max(:bartime) where barcode= :barcode
and ATTEND_DATE = :bardate-1;
else
insert into dail_att(barcode,intime,attend_date)
values(:barcode,min(:bartime),:bardate);
end if;
else
if :bartime between 0100 and 0630 then
insert into dail_att(barcode,intime,attend_date)
values(:barcode,min(:bartime),:bardate-1);
update dail_att set outtime = max(:bartime) where barcode= :barcode
and ATTEND_DATE = :bardate-1;
else
insert into dail_att(barcode,intime,attend_date)
values(:barcode,:min(bartime),:bardate);
end if;
end if;
end if;
while i am trying to this groupfunction it throws error while i use having tell me how to use group function and where
to use
Regadrs
Srikkanth.MHai sir
I had a table that contain fields
EMPCODE NUMBER
EMPNAME VARCHAR2(25)
BARCODE VARCHAR2(25)
INTIME VARCHAR2(25)
OUTTIME VARCHAR2(25)
INTRTIMEIN VARCHAR2(25)
INTROUTTIME VARCHAR2(25)
PERTIMEIN VARCHAR2(25);
PERTIMEOUT VARCHAR2(25);
ATTEND_DATE DATE ;
Consider that a table with 6 fields ie timein,intrtimein,pertimein,pertimeout,intrtimeout,timeout
I have generating a attendance table and a table contain 6 various times for an employees and we need to arrange it in order
0815,0816,1230,1250,1645,1646
If 0815 is the starting time then timein ie mintime
0816 stored to be in intrtime
then1250 then it stored in pertimein
then 1230 then it stored in pertimeout
then 1645 stored in intrtimeout
then 1646 stored in timeout
I tried with max and min function but its not working properly pls tell me some solutions
Thanks & Regards
Srikkanth.M -
PL/SQL equivalent of T-SQL - "group function is not allowed here"
Hi all, hope someone can give me a hand as I'm pretty stuck! I have been trying to convert some MS SQL Server T-SQL statements into Oracle PL/SQL and am stuck on the below one:
SELECT
CA.AssessmentID,
(SELECT ProductName + ISNULL(' - ' + PrincipalBenefit,'')
FROM rptPolicySnapshot WHERE PolicyID = MAX(CA.PolicyID)
AND SnapshotID = 1),
MAX(CA.PolicyID)
FROM rptClaimInvoiceLineSnapshot CIL
INNER JOIN rptClaimAssessmentSnapshot CA
ON CIL.AssessmentID = CA.AssessmentID
AND CIL.SnapshotID = CA.SnapshotID
WHERE CIL.SnapshotID = 1
GROUP BY CA.AssessmentID
This works fine in MSSQL but returns the below error in Oracle:
'ORA-00934: group function is not allowed here'
If I take out the subquery the query works fine.
Any ideas as to the syntax? I am new to Oracle so not sure as to how I should go about writing this.
Thanks in advance!
LeoWITH x AS (SELECT ca.assessmentid,
MAX (ca.policyid) policy_id
FROM rptclaiminvoicelinesnapshot cil
INNER JOIN rptclaimassessmentsnapshot ca
ON cil.assessmentid = ca.assessmentid
AND cil.snapshotid = ca.snapshotid
WHERE cil.snapshotid = 1
GROUP BY ca.assessmentid
SELECT x.assessment_id,
x.policy_id,
productname + decode(principalbenefit,null,null,' - ' || principalbenefit ) prodname
FROM rptpolicysnapshot, x
WHERE policyid = x.policy_id
AND snapshotid = 1I think that's in the neighbourhood. -
How to create a user_defined grouping function?
I need to create a user_defined function and use it in my sql statement.
I know the user_defined function can be used anywhere the build-in function can be used.In oracle,there are grouping functions.
How can I create a user_defined grouping function and I can use it in my sql statement.Hi, can you explain exactly what you are trying to achieve:
SQL> create or replace function my_func return number as
2 begin
3 return 5;
4 end;
5 /
Function created.
SQL> select deptno,my_func(),max(sal)
2 from emp
3 group by deptno,my_func()
4 /
DEPTNO MY_FUNC() MAX(SAL)
10 5 5000
20 5 3000
30 5 2850 -
ORA-00978 without group function
I've experienced a strange problem with oracle 11g.
I've retrieved the oracle exception ORA-00978 even if there was no group function in my query.
I supposed was a problem in the optimizer so I rebuild the tables statistics, after that the query was execute successfully.
Does anyone has an idea what the problem is?
Is possible that a bug exists in the 11g optimizer?
My oracle version is:
Oracle Database 11g Enterprise Edition 11.1.0.6.0 64bit Production
the query i tried is:
SELECT *
FROM TBCALENDAR Cal,
VWCALENDARACTIVITY CA,
VWSE R,
TBSCHEDULERPARTITION P,
TBREGION REG,
TBRESOURCE RES ,
TBZIPCITY z
WHERE Res.id=Cal.RESOURCE_ID
AND R.RESOURCE_ID=RES.ID
AND Cal.ACTIVITY_ID=CA.ID
AND CA.SCHEDULING=1
AND Cal.SCHEDPARTITION_ID IN
(select item.PARTITION_ID
from tbidcprofile prof,
tbidcpartitem part,
tbschedpartitem item
where prof.USERPROFILE_ID=4
and prof.IDCPARTITION_ID=part.PARTITION_ID
and part.BUSINESSUNIT_ID=item.BUSINESSUNIT_ID
and part.REGION_ID=item.REGION_ID )
AND TRUNC(Cal.START_DT)=trunc(sysdate)
AND P.ID=Cal.SCHEDPARTITION_ID
AND REG.ID(+)=Cal.WORKREGION_ID
AND Z.GEOLOCATION_ID(+)=Cal.HOMEGEOLOC_ID;
VWCALENDARACTIVITY and VWSE are two views, but I can select from them without any problem.
I've also tried to remove one view at a time an the error occurs only when the query uses both view at the same time.
Thanks
Renzouser479513 wrote:
VWCALENDARACTIVITY and VWSE are two views, but I can select from them without any problem.
I've also tried to remove one view at a time an the error occurs only when the query uses both view at the same time.
What are the views definition ?
Nicolas. -
How to create a grouping function
How to create a grouping function ?? For example, can I create a function:myavg and I can use it like :
select col_a, col_b, myavg(col_c)
from table_a
group by col_a, col_b
Thanks in advance !!
nullI don't think that you can create a grouping function in Oracle, but you can create a function and use it in Select statments.
null -
Grouping Function usage in SQL
All,
How does grouping function work, does it also depends on the sequence of columns used in group by rollup
select deptno,job, group_id(), sum(sal), grouping(deptno) , grouping(job)
from emp
group by rollup (deptno, job)
If the query is run by "rollup(job,deptno)" grouping (deptno) returns 1 where as if "rollup(deptno,job)" grouping (deptno) returns 0.
Does the column sequence in group by rollup decides the returning of grouping(deptno) function. I feel to have some misunderstanding of the way its said in ORACLE documentation. We referred to the below link for our understanding.
http://download.oracle.com/docs/cd/E11882_01/server.112/e17118/functions071.htm
Request the PRO's to discuss and clarify on this.Hi,
ramarun wrote:
All,
How does grouping function work, GROUPING (x) returns 1 if the current row represents a superaggregate of x, and 0 otherwise. In other words, if GROUPING (x) is 0, then the row represents a single value of x. If GROUPING (x) is 1, then the row represents a total of all values of x.
For example the query you posted may produce results like this:
` DEPTNO JOB GROUP_ID() SUM(SAL) GROUPING(DEPTNO) GROUPING(JOB)
20 ANALYST 0 6000 0 0
ANALYST 0 6000 1 0
10 CLERK 0 1300 0 0
20 CLERK 0 1900 0 0
30 CLERK 0 950 0 0
CLERK 0 4150 1 0
10 MANAGER 0 2450 0 0
20 MANAGER 0 2975 0 0
30 MANAGER 0 2850 0 0
MANAGER 0 8275 1 0
10 PRESIDENT 0 5000 0 0
PRESIDENT 0 5000 1 0
30 SALESMAN 0 5600 0 0
SALESMAN 0 5600 1 0
0 29025 1 1Look at the last three rows. On this row
` DEPTNO JOB GROUP_ID() SUM(SAL) GROUPING(DEPTNO) GROUPING(JOB)
30 SALESMAN 0 5600 0 0GROUPING (deptno) is 0; so the row represents only deptno=30.
GROUPINT (job) is 0, so the row represents only job='SALESMAN'.
SUM (sal) is 5600, so the total salary of all salesmen in department 30 is 5600.
Now look at this row:
` DEPTNO JOB GROUP_ID() SUM(SAL) GROUPING(DEPTNO) GROUPING(JOB)
SALESMAN 0 5600 1 0GROUPING (deptno) is 1; so the row does not represent any one deptno; it is a superaggregate of all deptnos. Notice that the deptno column is NULL, even though there are no rows in the table where deptno is NULL.
GROUPING (job) is 0, so the row represents only job='SALESMAN'.
SUM (sal) is 5600, so the total salary of all salesmen in any department is 5600. (As it happens, all the salesmen are in department 30, so this sum is the same as on the previous row.)
Now look at the last row:
` DEPTNO JOB GROUP_ID() SUM(SAL) GROUPING(DEPTNO) GROUPING(JOB)
0 29025 1 1GROUPING (deptno) is 1; so the row does not represent any one deptno; it is a superaggregate of all deptnos. Notic that both deptno and job are both NULL on this row of output, even though neither column is ever NULL in the table.
GROUPING (job) is 0, so the row represents only job='SALESMAN'.
SUM (sal) is 5600, so the total salary of people with any job and any department is 29025.
does it also depends on the sequence of columns used in group by rollup Excellent question! Try it an see. Change the order or columns in the GROUP BY clause and see. If you get different results, then the order does matter.
select deptno,job, group_id(), sum(sal), grouping(deptno) , grouping(job)
from emp
group by rollup (deptno, job) If the query is run by "rollup(job,deptno)" grouping (deptno) returns 1 where as if "rollup(deptno,job)" grouping (deptno) returns 0. You get different results; therefore the order does matter.
Does the column sequence in group by rollup decides the returning of grouping(deptno) function...Yes.
"GROUP BY ROLLUP (deptno, job)" means a superaggregate row for each value of job, representing all deptnos, will be formed. That is, you will get one row representing all analysts; another row representing all clerks, another row representing all managers, and so on. This will be similar to the results that you would get if you never mentioned the first expression in the ROLLUP list, that is, deptno. You will not get a superaggregate row representing any one deptno, say, 10.
"GROUP BY ROLLUP (job, deptno)" means a superaggregate row for each value of deptno, representing all jobs, will be formed. That is, you will get one row representing all anlysts; another row representing deprtment 10, another row representing department 20, and so on. This will be similar to the results that you would get if you never mentioned the first expression in the ROLLUP list, that is, job. You will not get a superaggregate row representing any one job, say, 'ANALYST'. -
ORA-00935: group function is nested too deeply - SQL Query is correct...
select s.sname, to_char(sum(t.amount), 'fm$999999.00')
from transactions t, salespeople s
where t.sid = s.sid
group by s.sname, t.year
having (t.year = 1997) and max(sum(t.amount));
I'm trying to print sales person name who had the highest total sell in 1997. I do not see where did i go wrong in the above query...Isn't nested group function allowed?!
What about this?
select s.sname, to_char(sum(t.amount), 'fm$999999.00') as "TOTAL"
from transactions t, salespeople s
where t.sid = s.sid
group by s.sname, t.year
having (t.year = 1997) and sum(t.amount) = (select max(amount) from transactions where year = 1997);
It should return something, but it does not due lack of data in database. I think the above code is correct. I just need to confirm from you...select s.sname, (case when sum(t.amount) > sum(t2.amount)
then sum(t.amount)
else sum(t2.amount)
end) "TOTAL"
from transactions t, salespeople s
where t.sid = s.sid
group by s.sname, t.year
having t.year = 1997
union
select s.sname, sum(t2.amount)
from transactions t2, salespeople s
where t2.sid = s.sid
group by s.sname, t2.year
having t2.year = 1997;
Your code looks good, but it does not work in Oracle Developer...
The above should work isn't it? The inner query gets executed then the outer one so the result i get in -
JDBC 8.1.6.0.1 Bug with grouping function
Hi,
I found a bug in the JDBC 8.1.6.0.1 driver, concerning the new grouping functionality of Oracle 8.1.6. Look at the following code fragment:
String cSelect = "SELECT DACO_VU_NAME AS DIM1, ' ' AS DIM2, TO_CHAR(DACO_VERKAUFSDATUM,'yyyymm') AS DIM_DATE, GROUPING(DACO_VU_NAME) AS DIM1GROUP, GROUPING(' ') AS DIM2GROUP, GROUPING(TO_CHAR(DACO_VERKAUFSDATUM,'yyyymm')) AS DIM_DATEGROUP, sum(DACO_BRUTTOBETRAG_TX) AS VALUE FROM DATENCONTAINER GROUP BY CUBE (DACO_VU_NAME, '-', TO_CHAR(DACO_VERKAUFSDATUM,'yyyymm') ) ORDER BY 1,2,3";
try {
System.out.println("SELECT: " + cSelect);
Statement stmt = conn.createStatement();
ResultSet rset = stmt.executeQuery(cSelect);
while (rset.next()) {
String cTest1 = rset.getString("DIM1");
String cTest2 = rset.getString("DIM2");
String cTest3 = rset.getString("DIM_DATE");
String cChar1 = rset.getString("DIM1GROUP");
String cChar2 = rset.getString("DIM2GROUP");
String cChar3 = rset.getString("DIM_DATEGROUP");
System.out.println(cTest1 + "\t" + cTest2 + "\t" + cTest3 + "\t" + cChar1 + "\t" + cChar2 + "\t" + cChar3);
}When I compile this with the mentioned JDBC version and run it with java 1.2.2 (JDeveloper 3.1), i get the following output:
Ahrend GmbH & Co. KG 200003 0 0 0
Ahrend GmbH & Co. KG 200003 1 0 0
Ahrend GmbH & Co. KG 200004 0 0 0
Ahrend GmbH & Co. KG 200004 1 0 0
Ahrend GmbH & Co. KG null 0 0 1
Ahrend GmbH & Co. KG null 1 0 1
null 200003 0 1 0
null 200003 1 1 0
null 200004 0 1 0
null 200004 1 1 0
null null 0 1 1
null null 1 1 1As you can see, the grouping columns are mixed up. In this example, everywhere a normal row shows a "null" value, a corresponding grouping row should show a "1", but as you can see, for the last 6 rows, the ones are not in the first, but in the second grouping row.
When I compile the example with the Oracle 8.1.5 JDBC driver, I get the following, correct, output:
Ahrend GmbH & Co. KG 200003 0 0 0
Ahrend GmbH & Co. KG 200004 0 0 0
Ahrend GmbH & Co. KG null 0 0 1
Ahrend GmbH & Co. KG 200003 0 1 0
Ahrend GmbH & Co. KG 200004 0 1 0
Ahrend GmbH & Co. KG null 0 1 1
null 200003 1 0 0
null 200004 1 0 0
null null 1 0 1
null 200003 1 1 0
null 200004 1 1 0
null null 1 1 1The special thing about this example is, that I use a constant row for grouping (row 2). If you use a normal database row, everything works fine with 8.1.6.0.1, but nevertheless, this should be a bug.
Any comments on this are highly appreciated, since I need the JDK 1.2 for the application and I didn't find a working Oracle 1.2 JDBC version.
Thanks,
Thorsten.Patches can be obtained from an Oracle Support Services technical analyst.
null -
Hi,
Is any difference between grouping function in oracle9i and oracle19g?
Thanks,
Michael.There is a book that lists all the new features of 10g
Bye Alessandro
Message was edited by:
Alessandro Rossi
And these too!!
http://download.oracle.com/docs/cd/B14117_01/server.101/b10750/chapter1.htm#sthref581
http://download.oracle.com/docs/cd/B14117_01/server.101/b10750/chapter1.htm#sthref629 -
Hi, I need to list the shortest string along with the number of characters in the string, so far I've come up with:
SELECT eventtitle, MIN(LENGTH(eventtitle))
FROM event
Oracle XE is giving the error "not a single-group group function", but I can't quite see how to get "eventtitle" on it's own, the function "MIN(LENGTH(eventtitle))" does give me the desired result if run by its self. I'm grateful for any assistance!1 with t
2 as
3 (
4 select 'abcd' short_string from dual
5 union all
6 select 'a' short_string from dual
7 union all
8 select 'b' from dual
9 )
10 select short_string, rownum rn from t
11* order by length(short_string)
SQL> /
SHOR RN
a 2
b 3
abcd 1one version using analytics
1 with t
2 as
3 (
4 select 'abcd' short_string from dual
5 union all
6 select 'a' short_string from dual
7 union all
8 select 'b' from dual
9 )
10 select short_string, len from
11 (
12 select short_string, length(short_string) len, min(length(short_string)) over() min_length from t
13* ) where len = min_length
SQL>
SHOR LEN
a 1
b 1Regards
Raj -
GROUP BY without GROUP functions
I red in Oracle university book that you can use the GROUP BY clause without using a group function in the SELECT list, can someone give me an example using the popular table 'employees' OR 'departments'
I cannot think of why or how such a query would be useful except it you selected the same column you grouped on you would be doing the equilivent of a select distinct:
UT1 > select deptno from emp group by deptno;
DEPTNO
10
20
30
HTH -- Mark D Powell -- -
Hello.
How can I use user define group function (Oracle 9i feature) in the same report with system define (sum, max).
I use Discoverer 9i.
Thanks.hi,
Try this in Fx
SUM(Absence_Days by person_id)
Thanks,
Saichand.v
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