Hibernate 2 SQL query question

Question

thanks, I use hibernate 2.1
Now I want to do the same thing, but using SQL
THE_QUERY_STRING="UPDATE CUSTOMER_SOMETHING customerSomething set customerSomething.customer = (select customer.objectId FROM CUSTOMER customer where customer.customerId customerSomething.customerId) where customerSomething.userTask = 15608"
With current THE_QUERY_STRING
two parameters are missing...
session.createSQLQuery(UPDATE_CUSTOMER_SQL, , );
What should I put here?

Answer 1

Hi,
Use LAST to find the location_code related to the latest start_date, like this:
SELECT       employee_id
,       MAX (start_date)     AS max_start_date
FROM       position
GROUP BY  employee_id
HAVING       MIN (location_code) KEEP (DENSE_RANK LAST ORDER BY start_date)     = 25
;MIN (location_code) specifies what to do in case of a tie. In your case, ties are impossible, since (employee_id, start_date) is the primary key, so it doesn't matter if you say MIN or MAX (or, if you want to be cute, AVG or SUM) in the HAVING clause: you'll get the same location_code either way.
I hope this answers your question.
If not, post a little sample data (INSERT statements to go with the CREATE TABLE statement you've already posted), and also post the results you want from that data.
Explain, using specific examples, how you get those results from that data.
Always say which version of Oracle you're using.
See the forum FAQ {message:id=9360002}