How can I get file name using JSTL ?

Question

Hi,
I'm now using <c:out value="${pageContext.request.requestURI}"/>
this return servlet path
How can I get just file name
or user path (in location bar) ?
thanks in advance

Answer 1

The original uri (before forwarding) is available in a request scoped attribute.
These attributes are given the values obtained by calling the related method on the original request received by the container.
javax.servlet.forward.request_uri
javax.servlet.forward.context_path
javax.servlet.forward.servlet_path
javax.servlet.forward.path_info
javax.servlet.forward.query_stringSo if those two above don't work for you these might.
<c:out value="${requestScope['javax.servlet.forward.request_uri']}"/>
<c:out value="${requestScope['javax.servlet.forward.servlet_path']}"/>If these values are null, then the value in the request object is the correct one.
You mentioned the value in the address bar being a .html file. Do you perchance use framesets? If so the value in the address bar is always the url used to load the frameset, and doesn't change no matter where you travel within those frames. That won't be available to the server, because it has nothing to do with the current request.
Cheers,
evnafets