How can I get the position of an element/cell of a ListView?

Hi,
I am working on an interface that requires "Parallel Coordinate" like view. It requires lists with edges between their elements. To do that I need the location (x, y) coordinates of the right and left edges of each cell. Is there a way to find that?
Thanks
Ankit

No, it has to by 'dynamic'. I don't want to transfer it hard, because it should work for any internal table name.
The requirement is: There are many function modules that have an input field TABLENAME. I have to give the tablename in the Form 'IT_TAB'.
But I look for a possibiltity not to write:
tabname = 'IT_TAB'.
For DDIC-Tables its not a problem, but I dont know a way for internal tables.

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Hi!
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Hello,
I'm working with VBscript.
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Best regards,
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Message was edited by: Andreas Jansson

In my opinion, locate a cell according to his content is not so effortable. What happens if contents of more than two cells are equals?
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Invoke node >>> point to Row Column
Ben
Message Edited by Ben on 07-19-2007 03:14 PM
Ben Rayner
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Attachments:
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How can I get the position of an element/cell of a ListView?

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