How can I kepp all songs on the same album?

Some of my albums that have duets on them will show up as multiple albums when they were ripped from the same CD. Is there a way to make them all under the same album cover. I also have some artists that under an artist search will show up with multiple different headings of the same artist. I'm using the Ipod on a Kenwood car head unit.

I add it to the title as I've described, i.e. *Title \[Feat. Guest\]*. This means that all the information is still visible when playing the track in iTunes or on the iPod and can also be used when searching.
To fix things I set my library up in List view with the browser turned on and the columns arranged so that I could see both Artist & Album Artist. I then selected the first album in Album section of the browser to show it's tracks. Pressing the down arrow on the keyboard shows the next album. A brief glance will reveal if some tracks of the album have different artist values, in which case these can be fixed before moving on to the next album. It should take less than a second per album to confirm that it is properly formatted as your eyes will rapidly notice any inconsistency in the artist column. The process is only time consuming when you actually need to make some changes.
If two different artists have albums with the same album title, e.g. Greatest Hits, this also shows up when working methodically through this list. I've chosen to rename the albums in the form *Album - Artist* as this separates the albums, makes it clear in the browser which album is which and puts them in artist order. Another approach is adding different numbers of trailing spaces for each different album.
tt2

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    When importing songs of a same album but different artist iTunes will separate the artists. How can I bring all together in the same album?

    Generally setting a common Album Artist will fix things. For deeper problems see Grouping tracks into albums.
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    I know this is gonna be too demanding, but can someone please tell me why my Consumer's run() method never reaches the System.out.println( "ALL CONSUMING DONE") line
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    using semaphores. Your program should be able to check for prime numbers in a range specified
    by the user and with a variable number of threads. Example:
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    import java.util.concurrent.Semaphore;
    import java.io.*;
    public class Assign1 {
    static int fromThisNumber;
    static int toThisNumber;
    static int numberOfThreads;
    static int buffer[];
    static Semaphore ready;          /*This semaphore is used by the Producer to signal
                                         an "OK" to the consumers*/
    static Semaphore critical;  /*This is a Mutex semaphore. It allows only 1 consumer
                                         to enter his critical section.
    static Semaphore counter;     /*This semaphore acts as a counter.
                                        Instead of having a global variable
                                         incremented each time, we just release()
                                         this semephore when we find a prime number
                                         Because remember that release() increments permits
    static Producer prod;
    static Consumer cons[];
    static int in=0;
    static int out=0;
    static PrintWriter outFile;
         public static void main (String args[]){
              try{
                   outFile=new PrintWriter(new FileWriter("primes.txt"));
                   }catch(Exception e){}
              numberOfThreads=Integer.parseInt(args[0]);
              fromThisNumber=Integer.parseInt(args[1]);
              toThisNumber=Integer.parseInt(args[2]);
              buffer=new int[Integer.parseInt(args[2])-Integer.parseInt(args[1])+1];
              ready=new Semaphore(0,false); /*We initialise it to 0 because we wait
                                                      for the Producer to produce atleast a
                                                      item. Suppose ready was 1 and if
                                                      Consumer ran first he would be in an
                                                      empty buffer */
              critical=new Semaphore (1,false);/*We initialise it to 1 because when
                                                         the first Consumer thread tries
                                                         to enter its critical section, it
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                                                         Subsequent threads will have to
                                                         wait since only 1 thread can
                                                         access its critical section at a time*/
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              for(int i=0;i<cons.length;i++)
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                   {     System.out.println("producing");     
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                        fromThisNumber++;
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              catch (Exception e){e.printStackTrace();}
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         public void run(){try{
              System.out.println("before while"+this.getId());
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                   System.out.println("before ready"+this.getId()+" "+ready.availablePermits()+" "+in);
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                   System.out.println("before critical.acquire"+this.getId());
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                   tempout=out;
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                        {System.out.println(buffer[tempout]+" by "+this.getId());buffer[tempout]=0;}
                   else {counter.release();System.out.println("prime added: "+buffer[tempout]+" by "+this.getId());}
                   critical.acquire();
                   tempout=out;
                   System.out.println("tempout:"+tempout+" of "+this.getId());
                   critical.release();
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         public boolean isPrime(int n){
              for(int i=2;i<=(n/2);i++)
                   if(n%i==0)
                        return false;
              return true;
    ======================
    import java.util.concurrent.Semaphore;
    import java.io.*;
    /* 3 questions to ask Barlas
    * Why error if I start the Consumer threads before Producer
    * Why does the counter semaphore always give a +1 result at the end
    * Is there a way I can verify that all the work is not being done by only 1 consumer thread? In other words, the workload is being shared properly
    * if I put ready.acquire() outside or inside the while loop, its not making any difference, why?
    * Strangely, its not making any difference if I playing with the release() and aquire() of the semaphores, WHY?!?!
    public class Assign1 {
    static int fromThisNumber;
    static int toThisNumber;
    static int numberOfThreads;
    static int buffer[];
    static Semaphore ready;          /*This semaphore is used by the Producer to signal
                                       an "OK" to the consumers*/
    static Semaphore critical; /*This is a Mutex semaphore. It allows only 1 consumer
                                       to enter his critical section.
    static Semaphore counter;     /*This semaphore acts as a counter.
                                  Instead of having a global variable
                                       incremented each time, we just release()
                                       this semephore when we find a prime number
                                       Because remember that release() increments permits
    static Producer prod;
    static Consumer cons[];
    static int in=0;
    static int out=0;
    static PrintWriter outFile;
         public static void main (String args[]){
              try{
                   outFile=new PrintWriter(new FileWriter("primes.txt"));
                   }catch(Exception e){}
              numberOfThreads=Integer.parseInt(args[0]);
              fromThisNumber=Integer.parseInt(args[1]);
              toThisNumber=Integer.parseInt(args[2]);
              buffer=new int[Integer.parseInt(args[2])-Integer.parseInt(args[1])+1];
              ready=new Semaphore(0,false); /*We initialise it to 0 because we wait
                                                      for the Producer to produce atleast a
                                                      item. Suppose ready was 1 and if
                                                      Consumer ran first he would be in an
                                                      empty buffer */
              critical=new Semaphore (1,false);/*We initialise it to 1 because when
                                                      the first Consumer thread tries
                                                      to enter its critical section, it
                                                      should be allowed to;
                                                      Subsequent threads will have to
                                                      wait since only 1 thread can
                                                      access its critical section at a time*/
              counter=new Semaphore(0,false); // duh!
              cons=new Consumer[numberOfThreads-1]; /*numberOfThreads-1 because 1 thread
                                                                is taken by the Producer*/
              //Creating Producer object
              prod=new Producer();
              //Creating the Consumer object and start the thread.
              for(int i=0;i<cons.length;i++)
                        cons[i]=new Consumer();
                        cons[i].start();
              prod.start();          
              //Printing to screen and file
    /*          for(int i=0;i<buffer.length;i++)
                   if(buffer[i]!=0)
                             System.out.println(buffer[i]);
                             outFile.println(buffer[i]);
              System.out.println("Total primes found between "+args[1]+" and "+toThisNumber+": "+counter.availablePermits()+"\n primes.txt written");
              outFile.println("Total primes found between "+args[1]+" and "+toThisNumber+": "+counter.availablePermits());
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    static class Producer extends Thread {
         public void run(){try{
              while(in<buffer.length)     /*'in' should always be more than 'out'.Oherwise the consumer will try to access an empty index*/
                   {     System.out.println("producing");     
                        buffer[in]=fromThisNumber;
                        in++;
                        fromThisNumber++;
                        ready.release();
              catch (Exception e){e.printStackTrace();}
              System.out.println("ALL PRODUCING DONE");
    static class Consumer extends Thread {
         int tempout=0;
         public void run(){try{
              System.out.println("before while"+this.getId());
              while(tempout<=in)
                   System.out.println("before ready"+this.getId()+" "+ready.availablePermits()+" "+in);
                   ready.acquire();
                   System.out.println("before critical.acquire"+this.getId());
                   critical.acquire();
                   tempout=out;
                   out++;
                   critical.release();               
                   if(!isPrime(buffer[tempout]))
                        {System.out.println(buffer[tempout]+" by "+this.getId());buffer[tempout]=0;}
                   else {counter.release();System.out.println("prime added: "+buffer[tempout]+" by "+this.getId());}
                   critical.acquire();
                   tempout=out;
                   System.out.println("tempout:"+tempout+" of "+this.getId());
                   critical.release();
              System.out.println("ALL CONSUMING DONE"+this.getId());
         catch(Exception e){e.printStackTrace();}
         //Prime number-checking method     
         public boolean isPrime(int n){
              for(int i=2;i<=(n/2);i++)
                   if(n%i==0)
                        return false;
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    ===========================
    BTW, when I tried to change extends Thread to implements Runnable I got some kinda of error.
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