How do I generate XML File Using JDeveloper 9.0.3

Question

Hi All
I want to generate a XML file against the data in one of my Oracle table,,,, This is the first time I am doing this Task, so please let me know whether I am going through the correct path, or if not appreciate if you could put me to the correct system of doing this please���..
OK , Well I am working to a publishing company in Australia and we have Oracle 8i (Release 3 ) database and I have Oracle JDeveloper (9.0.3 -Preview ) version in my personal computer.
I have a Table(ONIXT4) with three Columns( ISBN,Author,Price) in Oracle as follows:
ISBN     Author     Price
2512456321     Peter     14.50
7445854127     Ray      21.75
What I want to generate a XML File using JDeveloper as below with respect to data in above Table.
<ISBN>2512456321</ISBN>
<ProductInfor>
<Author>Peter</Author>
<Price>14.50</Price>
</ProductInfor>
<ISBN>7445854127</ISBN>
<ProductInfor>
<Author> Ray </Author>
<Price>21.75</Price>
</ProductInfor>
I created the database connection within JDeveloper to Oracle those working fine,, my major problem is,, the Tag <ProductInfor>, since this is not a Column Name of the Table I don't know how should I incorporate this with the file.
What I did so far with the JDeveloper:
1.Create the Workspace and the Project
2.File -- New -- XML -- XSQL
3.Then I Selected Query from the Component Palette,, Property Values were NOT changed, and gave 'Select * from ONIXT4'
Whole Untitled3.xsql file look likes below
<?xml version = '1.0' encoding = 'windows-1252'?>
<!--
| Uncomment the following processing instruction and replace
| the stylesheet name to transform output of your XSQL Page using XSLT
<?xml-stylesheet type="text/xsl" href="YourStylesheet.xsl" ?>
-->
<page xmlns:xsql="urn:oracle-xsql" connection="Connection1">
<xsql:query max-rows="-1" null-indicator="no" tag-case="lower">
Select * From OnixT4
</xsql:query>
</page>
Then the Result comes as:
<?xml version="1.0" encoding="windows-1252" ?>
- <!--
| Uncomment the following processing instruction and replace
| the stylesheet name to transform output of your XSQL Page using XSLT
<?xml-stylesheet type="text/xsl" href="YourStylesheet.xsl" ?>
-->
- <page>
- <rowset>
- <row num="1">
<isbn>2512456321</isbn>
<author>Peter</author>
<price>14.5</price>
</row>
- <row num="2">
<isbn>7445854127</isbn>
<author>Ray</author>
<price>21.75</price>
</row>
</rowset>
</page>
How do I format the outcome to obtain the my requirement??
Welcome all comments of donig this ....

Answer 1

To format your XML to the requiered output you'll use a stylesheet and XSLT
As it says in your output:
- <!--
| Uncomment the following processing instruction and replace
| the stylesheet name to transform output of your XSQL Page using XSLT
<?xml-stylesheet type="text/xsl" href="YourStylesheet.xsl" ?>
-->
A nice tutorial on XSLT is available on the XML technology center in OTN:
See Transforming XML with XSLT
http://otn.oracle.com/tech/xml/learner.html