How do I join two letters using the shape builder tool?
I am making a sign for my logo. The 'i' in my script face is long and overlaps the following letter which the sign maker's router will not read. So I would like to be able to use the shape builder tool to join the 3 instances where the letter 'i' appears each to the following letter. No luck so far. I have turned the type into points. I have highlighted the first instance, 'i' and 'c'. but the shape builder tool shows a circle with a line through it... not working.
Anyone have an idea?
It may take a combination of some of the Pathfinder tools, such as: Intersect, Merge, and Unite. And, it may be a matter of manually going in and deleting some anchor points in the outlines. Do some experimenting on copies of the instances. Might be a process of elimination.
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Hi,
I have a query that joins two tables in the same database, the result needs to be loaded in a destination DB table. How do I do this in SSIS package?
thank you !
Thank You Warmest Fanny PiedPlease take a look at these links related to your query.
http://stackoverflow.com/questions/5145637/querying-data-by-joining-two-tables-in-two-database-on-different-servers
http://stackoverflow.com/questions/7037228/joining-two-tables-together-in-one-database -
How to Join two tables using the Inner Join
Hi All,
I have two tables i.e table1 and table2 as i have created two otds and my present requirement is to join this two tables and get the results and using this i need to do some logic and update another table3.
can some one help me out how to go for the above req.
Thanks in Advance
SrikanthThe best efficient way to use inner join is create two input otds,use there otd's in create a collaboration usinf etl.
after selecting two input otd's create a inner join statement and map it to out put otd.
while using the etl the performance of the over all integration is increased 20 time of the normal integration.
Hopes this will helps,,
Thanks,
Papa Rao. -
How can i make two ipods use the same apple id
How can I make two ipod touchs have the same apple id
If you haven't already set up your two iPods either make and apple I'd on one and on the setup on the other type on your apple ID by setup I mean when you first get it it asked you questions so when your done answering the questions your iPod is ready to be used
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Mapping Split using the Graphical Mapping Tool
Hello,
I am a little confused right now... so I turn to you for help!
I found this excellent blog:
/people/claus.wallacher/blog/2006/06/29/message-splitting-using-the-graphical-mapping-tool
It details how to do a message split using the Graphical Mapping Tool. WHich is exactly what I want!
But then I found this on help.sap.com:
http://help.sap.com/saphelp_nw04/helpdata/en/42/ed364cf8593eebe10000000a1553f7/frameset.htm
Which states that:
Messages cannot be sent by using different Adapter Engines in a mapping-based message split. This affects configuration thus: All receiver agreements that have a receiver interface from the mapping entered in the key must only be assigned communication channels with the following adapter types:
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- CIDX Adapter
I have a simple mappling split where I want to take a file containing multiple materials and send them one by one to a PROXY into SRM. To send to proxy I want to use the HTTP adapter which is not listed above. BUT if I read it correctly it will work, as long as I dont try to do the interface determination based on the mapping.
Is this correct, that it will work I mean? I think so but not sure about the wording in the sentence above, and wanted to check before I go destroy my mapping.
Thanks!
NamHi,
If your scenario is simple and straight fwd like from one source to one target then you can split message without BPM. As Priyanka said in the message mapping go to Message Tab and set the target message occurance to unbounded. Then in the Interface Mapping in the target interface section you will find the occurance in the last column, change occurance to unbounded.
While doing configuration you have to go for Enhanced Interface Determination thats it.
Provided you are above sp14, incase of any lowere SP'a you will not even able to activate your mapping program as it will expect ABSTRACT interface to do multimapping.
Thanks,
Prakash
Thanks,
Prakash -
Use "shape builder tool" on "boated polygon" FAILED!
http://design.tutsplus.com/tutorials/create-a-traditional-russian-khokhloma-ornament-in-il lustrator--vector-24052
i am trying this tut, but i can't do part 2 step9.
First i can't do "shape builder tool" while select both the under shape and the cap.
Second if i create another shape then do the "shape builder tool", the left cap is another "boated polygon" as the picture i attached. I guess the boat effect applied to the new polygon shape again.
How can i avoid this automatical-shape-change thing?
ALSO, i tried on other shapes too. I use effects on one shape, then i cut or delete part of it, i can't get the rest shape as i wished. Coz the rest part got the effect again and became a new one. For example i can't get a half flower when i use boat effect on a polygon shape, coz the rest half just became a new strange flower.
Is there anything i did wrong????
need your helps!!! PLEASE!!!!The problem is not what you did wrong, but that the instructions are incomplete, a common problem with online tutorials.
After applying the Bloat effect, go to Object > Expand appearance. Then you can select the two shapes and delete the unwanted part with the Shape Builder Tool. Select the new cap shape, duplicate, recolor, scale, move. Select both cap shapes, create blend as I think you did earlier in the tutorial.
Peter -
Can't use Shape Builder Tool - getting circle with line through it.
I can't find any setting or anything I can change to make the Shape Builder Tool work. Using latest version.
Without more info, it can only be a guess, but be aware that the tool only works on selected objects. PRE-selected, that is.
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I am using a PC and installed the latest update of all the CC programs I use (AI, PS, AE, etc.) and within Illustrator I've noticed the Shape Builder Tool doesn't behave exactly as it did in the past. (And not in a good way.)
Previous versions allowed me to edit/add/remove shapes from one another without issue (leaving all shape paths as they were before the editing while making the desired alterations), but the newest behavior seems to alter existing paths once shapes are merged/deleted making the tool almost non-usable.
Not sure if there's a check box I'm missing or what, but have done some brief research on the problem and haven't found anything helpful. If anyone has run into this issue and/or knows a way to correct it, I would greatly appreciate it
Thanks!Please show a screenshot before and after.
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If you abandon one of the Apple IDs you will also basically be abandoning any content that you have acquired with that Apple ID. Content can only be updated and re-downloaded with the Apple ID that was used to buy it. Apple will not combine the content of Apple IDs and Apple will not transfer the content from one Apple ID to another Apple ID.
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Would it be worth learning about the relevant Darwin API (supposing there is one) and writing a small command-line program for the job? I am an experienced developer of software using Standard C.
Comments appreciated.
Davei wonder if there is a key that is stuck cause whenever i try to turn it on again after the 60 minute lockout, it says that the password was incorrect and i am locked out for another 60 minutes
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iTunes Store: Associating a device or computer to your Apple ID
http://support.apple.com/kb/ht4627
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How to fix the "Two computers using the same IP address" issue on the airport express
I just bought an airport express and got dsl at my apartment, and I haven't been able to set up the wireless connection. My DSL works just fine but whenever I hook up the AX I get an error message saying that there are two computers using the same IP address on the network, but I only have one computer.
I know this is probably a simple fix, but I've never had this issue when I set up the Extreme at my parents house and I haven't been able to find a thread on this.
As of right now I have it set to Factory settings.
Help please!This modem was designed to connect directly to a computer and you are trying to connect it to a router.
Unfortunately, this is not a simple fix as both the modem and your AirPort Express will need to be configured differently to work together correctly.
Connect the modem directly to your computer.
Open up your browser and type the default IP address for the modem into the address bar. Check your documentation on the modem but it is likely 192.168.1.254
That will bring up the configuration page for the modem.
You may need to enter the modem access code which is on a label on the back or bottom of the device
Look for an Advanced tab, then look for a tab labeled something like PPP Location
Right now, you will see that "PPP is on the modem"
Chance that to "PPP is on the computer or router"
Click to save your new settings and the modem will restart
If you ever need to get the modem back to its original settings, you will need to hold in the reset button on the back of the modem for 5-6 seconds and then enter in the default IP address to be able to access the settings on the modem
Connect the modem to the AirPort Express with an Ethernet cable
Open AirPort Utility on your Mac and click Continue to follow the guided setup to "Create a wireless network"
You may be asked to "switch" networks when you do this. You want to switch
Select the "Connect Using PPPoe" option when it appears
Enter your user name and password with your provider. Leave the Service Name area blank. You want to always stay connected if you see that option
Continue to follow the guided setup and Update to save settings
Pull the power cord from the modem, wait a moment, then restart the modem
Log on to the wireless network that you created during the setup and you should have an Internet connection -
LEFT OUTER JOIN multiple tables - using the 9i syntax
I've always written my queries using the (+) operator for outer joins. I want to start using the new ANSI standard available in 9i. I can do it when I'm joining two tables in a simple query, but how does it work when I am joining multiple tables?
Here is an example of some SQL that works with the (+) outer join syntax. How can I convert this to use the LEFT OUTER JOIN syntax?
SELECT *
FROM audit_entry aue,
audit_table aut,
audit_statement aus,
audit_row aur,
audit_row_pkey aup1,
audit_row_pkey aup2
WHERE aue.audit_entry_id = aus.audit_entry_id
AND aut.table_name = 'TEST_AUDITING'
AND aut.table_owner = 'CLA_JOURNAL'
AND aus.audit_table_id = aut.audit_table_id
AND aur.audit_statement_id (+) = aus.audit_statement_id
AND aup1.audit_row_id (+) = aur.audit_row_id
AND aup1.pk_column_name (+) = 'TEST_AUDTING_PK_1'
AND aup2.audit_row_id (+) = aur.audit_row_id
AND aup2.pk_column_name (+) = 'TEST_AUDITING_PK_2'
I can join audit_statement to audit_entry easy enough, but then I want to join audit_table to audit_statement, how do I do that, do I start nesting the join statements?
Thanks
RichardThanks for getting back so quickly, I have tried the suggested SQL with mixed results:
SELECT COUNT(*)
FROM audit_entry aue
JOIN audit_statement aus ON aue.audit_entry_id = aus.audit_entry_id
JOIN audit_table aut ON aus.audit_table_id = aut.audit_table_id
RIGHT OUTER JOIN audit_row aur ON aur.audit_statement_id = aus.audit_statement_id
RIGHT OUTER JOIN audit_row_pkey aup1 ON aup1.audit_row_id = aur.audit_row_id
RIGHT OUTER JOIN audit_row_pkey aup2 ON aup2.audit_row_id = aur.audit_row_id
WHERE aut.table_name = 'TEST_AUDITING_TWO'
AND aut.table_owner = 'CLA_JOURNAL'
AND aup1.pk_column_name = 'TEST_AUDTING_PK_1'
AND aup2.pk_column_name = 'TEST_AUDITING_PK_2'
I had to change the order slightly, between the first two JOINs but otherwise it executed OK. My problem is, it should only return 175 rows but its returning 30625 rows. If I comment out the second reference to audit_row_pkey I get the expected result:
SELECT COUNT(*)
FROM audit_entry aue
JOIN audit_statement aus ON aue.audit_entry_id = aus.audit_entry_id
JOIN audit_table aut ON aus.audit_table_id = aut.audit_table_id
RIGHT OUTER JOIN audit_row aur ON aur.audit_statement_id = aus.audit_statement_id
RIGHT OUTER JOIN audit_row_pkey aup1 ON aup1.audit_row_id = aur.audit_row_id
--RIGHT OUTER JOIN audit_row_pkey aup2 ON aup2.audit_row_id = aur.audit_row_id
WHERE aut.table_name = 'TEST_AUDITING_TWO'
AND aut.table_owner = 'CLA_JOURNAL'
AND aup1.pk_column_name = 'TEST_AUDTING_PK_1'
--AND aup2.pk_column_name = 'TEST_AUDITING_PK_2'
It looks the same condition is being used in each case but why do I suddenly get so many rows - its joining differently somehow. It must be to do with the order, do I need to bracket the query?
Thanks again
Richard -
I am trying to develop a query in MS Access 2010 to join two tables using three joins, one of which is a (between) date range. The tables are contained in Access. The reason
the tables are contained in access because they are imported from different ODBC warehouses and the data is formatted for uniformity. I believe this cannot be developed using MS Visual Query Designer. I think writing a query in SQL would be suiting this project.
ABCPART links to XYZPART. ABCSERIAL links to XYZSERIAL. ABCDATE links to (between) XYZDATE1 and ZYZDATE2.
[ABCTABLE]
ABCORDER
ABCPART
ABCSERIAL
ABCDATE
[ZYXTABLE]
XYZORDER
XYZPART
XYZSERIAL
XYZDATE1
XYZDATE2Thank you for the looking at the post. The actual table names are rather ambiguous. I renamed them so it would make more sense. I will explain more and give the actual names. What I do not have is the actual data in the table. That is something I don't have
on this computer. There are no "Null" fields in either of the tables.
This table has many orders (MSORDER) that need to match one order (GLORDER) in GLORDR. This is based on MSPART joined to GLPART, MSSERIAL joined to GLSERIAL, and MSOPNDATE joined if it falls between GLSTARTDATE and GLENDDATE.
[MSORDR]
MSORDER
MSPART
MSSERIAL
MSOPNDATE
11111111
4444444
55555
2/4/2015
22222222
6666666
11111
1/6/2015
33333333
6666666
11111
3/5/2015
This table has one order for every part number and every serial number.
[GLORDR]
GLORDER
GLPART
GLSERIAL
GLSTARTDATE
GLENDDATE
ABC11111
444444
55555
1/2/2015
4/4/2015
ABC22222
666666
11111
1/5/2015
4/10/2015
AAA11111
555555
22222
3/2/2015
4/10/2015
Post Query table
GLORDER
MSORDER
GLSTARTDATE
GLENDDATE
MSOPNDATE
ABC11111
11111111
1/2/2015
4/4/2015
2/4/2015
ABC22222
22222222
1/5/2015
4/10/2015
1/6/2015
ABC22222
33333333
1/5/2015
4/10/2015
3/5/2015
This is the SQL minus the between date join.
SELECT GLORDR.GLORDER, MSORDR.MSORDER, GLORDR.GLSTARTDATE, GLORDR.GLENDDATE, MSORDR.MSOPNDATE
FROM GLORDR INNER JOIN MSORDR ON (GLORDR.GLSERIAL = MSORDR.MSSERIAL) AND (GLORDR.GLPART = MSORDR.MSPART); -
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