How do I open a text file to sort using bubble sort?

Question

Hi,
I have a text file, which is a list of #'s.. ex)
0.001121
0.313313
0.001334
how do you open a text file and read a list? I have the bubble sort code which sorts.. thanks

Answer 1

I wrote this, but am getting a couple errors:
import java.util.*;
import java.io.*;
public class sort
     public static void main(String[] args)
          String fileName = "numsRandom1024.txt";
          Scanner fromFile = null;
          int index = 0;
          double[] a = new double[1024];Don't use double. You should use something that implements Comparable, like java.lang.Double.
          try
               fromFile = new Scanner(new File(fileName));
          catch (FileNotFoundException e)
System.out.println("Error opening the file " +
" + fileName);
               System.exit(0);
          while (fromFile.hasNextLine())
               String line = fromFile.nextLine();
               a[index] = Double.parseDouble(line);Don't parse to a double, create a java.lang.Double instead.
               System.out.println(a[index]);
               index++;
          fromFile.close();
          bubbleSort( a, 0, a.length-1 );No. Don't use a.length-1: from index to a.length-1 all values will be null (if you use Double's). Call it like this:bubbleSort(a, 0, index);
public static <T extends Comparable<? super T>> void
d bubbleSort( T[] a, int first, int last )
          for(int counter = 0 ; counter < 1024 ; counter++)
for(int counter2 = 1 ; counter2 < (1024-counter) ;
) ; counter2++)Don't let those counter loop to 1024. The max should be last .
                    if(a[counter2-1] > a[counter2])No. Use the compareTo(...) method:if(a[counter2-1].compareTo(a[counter2]) > 0) {
                         double temp = a[counter2];No, your array contains Comparable's of type T, use that type then:T temp = a[counter2];
// ...Good luck.