How do I prevent null being shown in the field

Question

Hi Everyone,
I do have a form I am done with designing using the Adobe LiveCycle 7.0, but is having problem with the backend code. Whenever you delete the value, null gets written in it and it even appears on the printout. Please, can anyone help me out with this code and tell me what I need to do to get rid of this problem.
if (EMPLNAME.rawValue.rawValue == "" || EMPLNAME.rawValue.rawValue == null)
EMPLNAME.rawValue.rawValue == "";
// xfa.host.messageBox(EMPLNAME.rawValue);
EMPNAME.rawValue = String(EMPFNAME.rawValue) + " " + String(EMPMI.rawValue) + "." + " " + String(EMPLNAME.rawValue);
if (EMPFNAME.rawValue != "" || EMPMI.rawValue != "" || EMPLNAME.rawValue != "")
EMPNAME.rawValue = String(EMPFNAME.rawValue) + " " + String(EMPMI.rawValue) + "." + " " + String(EMPLNAME.rawValue);
var s = EMPMI.rawValue;
EMPMI.rawValue = s.toUpperCase();
Thanks
Lucky Pianwi

Answer 1

You need to check the values to see if they are null before you concatenate them:
>FIELD.rawValue != null
Some example code which should do what you are trying to do above:
    var lName = EMPLNAME.rawValue;
    var fName = EMPFNAME.rawValue;
    var initialName = EMPMI.rawValue;
    var result = "";
    if(fName != null && fName.length > 0) {
        result = fName + " ";
    if(initialName != null && initialName.length > 0) {
        result += initialName + ". ";
    if(lName != null && lName.length > 0) {
        result += lName
    EMPNAME.rawValue = result;
(There are shorter ways of doing this, but this way, it's pretty clear what is going on)
You should probably also check out some Javascript tutorials. I use http://www.w3schools.com/js/ as a reference all the time but there are many others around.
Regards
Anthony Jereley
Indigo Pacific
www.indigopacific.com