How do I set up an indicator to display for only 1 second?

Question

How do I set up an indicator to display for only 1 second?
I am reading keys from a serial device and I turn on an indicator that corresponds to the key pressed
on the serial device but how do I set this up so that it only stays lit (enabled) for a second or two?
The indicator is inside of a case statement and turns on OK but I do not want it to stay on for more than
a second or two. How do I modify this to display for only a second or two?
 (P.S. I am running an old version 8.2 and can only see vis that are 8.2 or older.)
thanks

Answer 1

Simplest way to turn the indicator off (false value) after a set time is to use a Sequence structure (flat or stacked).
Frame 1, set to true,
Frame 2, Wait ms (wire millisecond value to wait)
Frame 3, set to false.
This method, however, prevents the code outside the case structure from running during that wait time.  
Something more elaborate will allow the external code to run.  What comes to mind is a shift register that holds the indicator name and the time stamp (in milliseconds) when it was turned on, in an array of clusters.  Each iteration of your loop will check this register to see if a certain time has passed (current time stamp minus turn on time).  If so, use a case structure to turn the indicator off and remove the elements from the shift register array (so you don't keep setting the indicator to false).  The array will let you control multiple indicators independently.
A problem with this option could arise from multiple readings.  Lets say you want to turn it off after 2 seconds, but you read the value again after 1 second (this means the indicator should be on for a total of 3).  The code would still turn it off after the 2 second mark.  Of course this really depends on the time intervals involved with your code.