HOW DO I UNZIP AND ZIP FILES

This Mac uses 10.5.8 and apparently will not open .zip files that come to it nor can my bookkeeper zip excel sheets to email to me.
Anybody? Please?
Bill

Hi Bill,
What happens when you double click on a zip file? It should decompress.
If not... The Unarchiver 2.6 will do...
http://wakaba.c3.cx/s/apps/unarchiver
To zip a file, right click or control+click on a file, choose compress.

Similar Messages

How to unzip and zip files

I have a very large number of Karaoke music that plays on my windows pc but some will not play on my Mac. I think i need to unzip & re-zip them to play on my mac but i'm not sure exactly how to do this. any suggestions? Do I need a special program? running os x 10.9.3

Zip files can be opened with the built in 'Archive Utility' application. Double click any zip file & it will try to unzip it.
This application is tucked away inside /System/Library/CoreServices/Archive Utility. If you want to set preferences for it you need to open the location in Finder by using the 'Go Menu > Go to Folder…', enter /System/Library/CoreServices/ for the path & then open the Archive Utility application and look in it's preferences.
I expect that zipping & rezipping will not do anything useful for you. I suspect that the file format is the issue.
Unzip some files & post what the Finders 'File > Get info' panel shows, take a screenshot of it with 'cmd+shift+4', then drag the crosshairs to select the area. it will appear on the Desktop for uploading here.
You may need to find a compatible player or find a way to convert them if the Mac cannot play them.
P.S. to zip a file(s) select the items & right click, select 'Compress x items' & you will get a zip archive - I don't think it will help you though

Unzip a zipped file?

How can I unzip a zipped file with java ?

I presume you've read the API of [url http://java.sun.com/j2se/1.4.1/docs/api/java/util/zip/ZipFile.html]ZipFile?

How do you unzip a Word File on an older MAC mini?

How do you unzip a Word File on an older MAC mini?

On older Macs .docx files can look like a zip file. This is because they contain a proprietary form of XML compressed using ZIP.
If you have an older version of Office for Mac, i.e. Office 2004 which predates .docx format files, then you can install a free addon to allow it to import and export .docx files.
See http://www.microsoft.com/en-us/download/details.aspx?id=27334

Problem in unzipping the zip files

Hi,
I have created a program to unzip the zip files. But when i try to zip it is creating the zipped files outside the folder where it is to be zipped.
what is wrong with my code.
if the zip file is migration.zip
if the path inside the zip file shows
and the path inside says this
/codebase/scripts/
it would create migration folder and create codebase folder outside the migration folder
what is wrong with my code
//Unzip the zip files to the folder with their name
import java.io.BufferedReader;
import java.io.File;
import java.io.FileOutputStream;
import java.io.FilenameFilter;
import java.io.IOException;
import java.io.InputStreamReader;
import java.util.Enumeration;
import java.util.zip.ZipEntry;
import java.util.zip.ZipFile;
// Getting the path to find the type of files
public class zipper implements FilenameFilter{
          String ext;
          public zipper(String ext)
               this.ext="." + ext;
          public boolean accept(File dir,String name)
               return name.endsWith(ext);
public static void main(String args[]) throws IOException
          try
                    String dir = "D:/a/";
                    File f2 = new File(dir);
                    FilenameFilter fn= new zipper("zip");
                    String ss[]=f2.list(fn);
               for ( int j = 0; j < ss.length; j++)
                    System.out.println(" Extracting ...." + ss[j]) ;
                    String zipFile = dir + ss[j];
                    ZipFile zf = new ZipFile(zipFile);
                    Enumeration entries = zf.entries();
                    String directoryName = zf.getName();
                    directoryName = directoryName.substring(0, (directoryName.indexOf(":" + File.separator) + 2));
                         String folderName = zf.getName();
                         folderName = folderName.substring(0, folderName.lastIndexOf("."));
                         File file1 = new File(folderName);
                         //File file1 = new File(entries.getName());
                         file1.mkdir();
               while (entries.hasMoreElements())
                         ZipEntry ze = (ZipEntry) entries.nextElement();
                         String path = directoryName + ze.getName() ;
                         String path1 = folderName + ze.getName();
                         //System.out.println(" : " + path);
                         if (ze.getName().endsWith("/"))
                                   File file = new File(path);
                                   file.mkdir();
                                   continue;
                                   //break;
                    BufferedReader bReader = new BufferedReader(new InputStreamReader(zf.getInputStream(ze)));
     StringBuffer fileBuffer = new StringBuffer(" ");
     String line ;
                    while ((line = bReader.readLine()) != null)
                              fileBuffer.append(line);
                              fileBuffer.append("\r\n");
                              //line = line + "\r\n";
                              //byte[] b = new byte[line.length()];
                              //b =line.getBytes();
                              //out.write();
                    String fileData = fileBuffer.toString();
     File f1 = new File(path);
                    f1.createNewFile();
                    //FileOutputStream out = new FileOutputStream(folderName + "/" + ze.getName());
                    FileOutputStream out = new FileOutputStream(path);
                    long size = ze.getSize();
                    byte[] data1 = new byte[fileData.length()];
                    for (int i = 0; i < fileData.length(); i++)
                              data1[i] = (byte) fileData.charAt(i);
     out.write(data1);
     out.close();
                    bReader.close();
               } catch (Exception e)
                         e.printStackTrace();
Thanks in Advance
Avinash

String path = directoryName + ze.getName();
String path1 = folderName + File.separator+ ze.getName();
File f1 = new File(path); // pass path1 instead of path
f1.createNewFile();
FileOutputStream out = new FileOutputStream(path); // pass path1 instead of path

Problem in Unzipping the zip file

Hi
I have created a program to unzip the zip files in the folder named after the zip file
it is working well well when u try to zip zip files put in a directory
i.e u create a folder name contents and put files into that and then zip it
but when u directly create a zip file , without putting in a folder
it creates the folder and zip the files outside the folder
Another problem is that with the path
for e.g. suppose the zip file name is contents and path should show
contents/filename.txt but there are some other files whose path shows
res/file.txt. In this case it creates a folder of res and put it outside the
folder with the name of zip file
I have pasted my code :
//Unzip the zip files to the folder with their name
import java.io.BufferedReader;
import java.io.File;
import java.io.FileOutputStream;
import java.io.FilenameFilter;
import java.io.IOException;
import java.io.InputStreamReader;
import java.util.Enumeration;
import java.util.zip.ZipEntry;
import java.util.zip.ZipFile;
// Getting the path to find the type of files
public class zipper implements FilenameFilter{
          String ext;
          public zipper(String ext)
               this.ext="." + ext;
          public boolean accept(File dir,String name)
               return name.endsWith(ext);
public static void main(String args[]) throws IOException
          try
                    String dir = "D:/";
                    File f2 = new File(dir);
                    FilenameFilter fn= new zipper("zip");
                    String ss[]=f2.list(fn);
               for ( int j = 0; j < ss.length; j++)
                    System.out.println(" Extracting ...." + ss[j]) ;
                    String zipFile = dir + ss[j];
                    ZipFile zf = new ZipFile(zipFile);
                    Enumeration entries = zf.entries();
                    String directoryName = zf.getName();
                    directoryName = directoryName.substring(0, (directoryName.indexOf(":" + File.separator) + 2));
                         String folderName = zf.getName();
                         folderName = folderName.substring(0, folderName.lastIndexOf("."));
                         File file1 = new File(folderName);
                         //File file1 = new File(entries.getName());
                         file1.mkdir();
               while (entries.hasMoreElements())
                         ZipEntry ze = (ZipEntry) entries.nextElement();
                         String path = directoryName + ze.getName() ;
                         String path1 = folderName + ze.getName();
                         //System.out.println(" : " + path);
                         if (ze.getName().endsWith("/"))
                                   File file = new File(path);
                                   file.mkdir();
                                   continue;
                                   //break;
                    BufferedReader bReader = new BufferedReader(new InputStreamReader(zf.getInputStream(ze)));
     StringBuffer fileBuffer = new StringBuffer(" ");
     String line ;
                    while ((line = bReader.readLine()) != null)
                              fileBuffer.append(line);
                              fileBuffer.append("\r\n");
                              //line = line + "\r\n";
                              //byte[] b = new byte[line.length()];
                              //b =line.getBytes();
                              //out.write();
                    String fileData = fileBuffer.toString();
     File f1 = new File(path);
                    f1.createNewFile();
                    //FileOutputStream out = new FileOutputStream(folderName + "/" + ze.getName());
                    FileOutputStream out = new FileOutputStream(path);
                    long size = ze.getSize();
                    byte[] data1 = new byte[fileData.length()];
                    for (int i = 0; i < fileData.length(); i++)
                              data1[i] = (byte) fileData.charAt(i);
     out.write(data1);
     out.close();
                    bReader.close();
               } catch (Exception e)
                         e.printStackTrace();
Thanks in Advance
Avinash

String path = directoryName + ze.getName();
String path1 = folderName + File.separator+ ze.getName();
File f1 = new File(path); // pass path1 instead of path
f1.createNewFile();
FileOutputStream out = new FileOutputStream(path); // pass path1 instead of path

Unzipping Mac .zip files on a Windows PC

Does anybody know of a Windows program that will decompress Mac .zip (gz) files reliably? I've Tried StuffIt Standard for Windows but it quits every time with a warning, "Engine Error:Internal Error." Sure, I can make .sit files on the Mac and use Stuffit to expand them in Windows, but that's not the solution I'm looking for. If I already have a Mac .zip file on my Windows PC is there any way to open it without using a Mac?
I've searched these forums but all my searches come up with answers to the opposite question: How do I open Windows .zip files on my Mac?

A .gz file is not a "Mac Zip file" but a GNU Zip file, which is commonly used on Unix and Linux computers (OS X is a form of Unix).
You can get a gzip application for Windows here, or Google for something like "gzip for Windows".
Archives made by the Finder on a Mac are regular zip files (.zip files), just like the ones you would see on Windows.

How to create a split zip file?

Hi,
Does anybody know how to create a split zip file using only Java?
Lets say I have a file that compressed has a size of 10MB and I need to split it into small files of 1MB each... and then be able to open and uncompress it using winzip or any other compressing tool.
I know how to create a zip file using java.util.zip but I cannot split it...
Thanks,
Ignacio

IgnacioKriche wrote:
Thanks for the philosophical advice...
Can anyone help me? Does anyone know if Java API java.util.zip can split a zip file?I'm 99.9 % sure that there is nothing in the Java ZIP APIs to do this but I'm 100% sure I can't be certain.

Unzip a zip file

Can someone help me for the following problem,
Iam downloading a zip file from the server to the client.i want to unzip and execute the .EXE file, which is inside the zip file through the java coding.can any one help me!
thanking you

I think you can do all of this using the Java runtime interface which allows you to execute command line commands via Java code (ie, launching an EXE).
See http://java.sun.com/j2se/1.4.2/docs/api/java/lang/Runtime.html
I don't believe there is a component of the Java API that allows you to unzip a zip file. But you could still accomplish this using the winzip command line support. See http://www.winzip.com/wzcline.htm in combination with the Java runtime.

How to convert FLV and F4V files to other media formats

How to convert FLV and F4V files to other media formats
Nowadays, every one can download their favorite videos from video sharing websites like YouTube, Hulu, MySpace, Google Video, metacafe, Yahoo! Video, Reuters.com and so on at will. However, these video files we got are usually in the format of FLV, or F4V, which are not workable by most portable devices, or some video players and video editors on our PC. With the intention of solving these problems, this guide will show you how to convert FLV and F4V files to other video and audio formats in detail.
1. Download, install and run Pavtube FLV Converter
As soon as you run this program, the following wine red interface will show up:
2. Add files, set output format and destination folder
Input FLV and F4V files to this program by clicking on “Add” button, and select a format as the output format in the drop-down list of “Format”, meanwhile, you can press the output folder to specify the destination folder or just use the path set by default. Moreover, “merge into one file” enables you to combine multiple FLV and F4V files to be as a single file, if you have this needs, just tick it.
3. Set advanced settings
Click “Settings” button, the following interface will pop up. You can change the parameters like screen size, bit rate, frame rate, sample rate, etc. on it to optimize the output quality or compress file size.
4. Convert
After all settings are done, you can press “Convert” button to start transferring, and then the following window will show you the conversion info in detail. According to the info you can manage your time and disk space properly.
Pavtube FLV Converter can definitely complete the conversion at a swift speed with excellent quality; also it adopts an advanced audio-video sync technology, so that audio and video match very well in the resulted files. Therefore you need not worry about these issues.
Useful tips:
Free online FLV downloader:
www.convertdirect.com
http://vixy.net/
http://www.videoconverterdownload.com/online-free-flv-converter.html
http://www.flv2mp3.com/
http://www.mediaconverter.org/
http://2conv.com/
http://online.movavi.com/
http://www.youconvertit.com/
http://www.playtube.com/
http://www.convert.net/

Flip4Mac

How do I copy and paste files from a windows remote server to my mac?

How can i copy and paste files from a remote server (windows) to my mac? i have installed cord to connect to the server but now i can´t cpy the files to my mac!

Hi Sara. Tanks for responding. If I cannot figure this out (I was up
until 2am last night), I want to cancel my subscription.
Here are two files you can check on/help me with. When I try again, it
comes up 'an error has occurred when trying to access the service.'
Please advise.
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In a message dated 11/1/2014 12:55:23 A.M. Eastern Daylight Time,
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How do I copy and paste text from a converted Word document?
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Problem in tutorial and zip file. can anyone file it or correct it..

hi jdev experts,
am using jdev11.1.1.5.0.
when am new to these webservice. i followed this tutorial
http://docs.oracle.com/cd/E18941_01/tutorials/jdtut_11r2_14/jdtut_11r2_14.html
url wsdl link when use that wsdl.
throws some error.
what is the reason john says. ok at second post of the thread.
Consuming a Web Service from a Web Page
so if i change the wsdl means and somethings has to be changed in tutorial steps.
if any newbie crossing this tutorials feels very difficult to work. so can change the wsdl url link and those steps.
and another thing I installed 11.1.2.0 and download that zip file in that tutorial and i run throws the same error.
so. problem in tutorial and zip file. can anyone file or correct..
i think think this is the right place to tell this. or else re-direct me.

this is to arun.
As the exception stack clearly mentions that the endpoint is moved, it is up to the users to make use of any other webservice.trace says link is moved i know.
thing am here is:
please make note on that tutorials.
* note :- just like this consume some other external webservices. dont use this webservice this webservices link is broken.
this what saying.
this to john.
thanks. thanks again.

How do I store and delete files on the iphone

how do I store and delete files on the iphone

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Website image and zip file download links not working in Dreamweaver Air application

Hi
I have successfully created and AIR app for an existing business website using the Dreamweaver AIR Extension. The site works very well in all respects except for the part where we have high resolution images and zip files available for download. The download links refuse to do anything, and right-click (PC) / ctl-click (Mac) does nto work either.
I suspect this may be an AIR sandbox/security issue but am I correct and what can I do to fix it?
Thanks in advance for any assistance you may be able to give.
Martin

I am now facing the same problem. I wrote a servlet .
code like this
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        if (null != agent && agent.indexOf("MSIE")!=-1) {
            isIE=true;
        if (isIE) {
            fileName = URLEncoder.encode(fileName, "UTF-8");
        } else {
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and i open a new window refer to above jsp ,also i set a breakPoint at os.close(),the program has passed through,but nothing happened in the window.
If i use IE or FF ,the browser will open a small window to allow me select whether open or save the file.So can anybody give me some advice.Is it because air using webkit engine and the engine does not do this kind of job?
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How to transfer video and audio files from windows PC to new ipad?

How to transfer video and audio files from windows PC to new ipad?

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Sync with iTunes.
Connect the iPad to the PC and launch iTunes.
Click on the iPad name on the left side under devices.
Click on the Music Tab on the right.
Click on all of the albums, artists, playlists that you want to sync
Click on the Sync Music Heading.
Click on Apply in the lower right corner of iTunes
Follow the same procedure for Movies.

HOW DO I UNZIP AND ZIP FILES

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