How to Achieve this in SQL Query?

Question

How to Achieve this ?
I have a table with numeric value populated like this
create table random_numeral (numerals Number(10));
insert into random_numeral values (1);
insert into random_numeral values (2);
insert into random_numeral values (3);
insert into random_numeral values (4);
insert into random_numeral values (5);
insert into random_numeral values (6);
insert into random_numeral values (56);
insert into random_numeral values (85);
insert into random_numeral values (24);
insert into random_numeral values (11);
insert into random_numeral values (120);
insert into random_numeral values (114);
Numerals
1
2
3
4
5
6
56
85
24
11
120
114
I want to display the data as follows
col1 / col2 / col3
1 / 2 / 3
4 / 5 / 6
11 / 24 / 56
85 / 114 / 120
Can anyone Help me?

Answer 1

I hope there might be some simple way to do this and waiting for experts to reply.
Try the below query.
SQL> select * from random_numeral;
  NUMERALS
         1
         2
         3
         4
         5
         6
        56
        85
        24
        11
       120
  NUMERALS
       114
       100
       140
14 rows selected.
SQL> select a.numerals ||' / '||b.numerals||' / '||c.numerals from
  2          (select numerals,rownum rn1 from
  3          (
  4              select numerals,mod(row_number() over(partition by 1 order by numerals),3)
  5              from random_numeral
  6          )
  7          where rn=1) a,
  8          (select numerals,rownum rn1 from
  9          (
10              select numerals,mod(row_number() over(partition by 1 order by numerals),3)
11              from random_numeral
12          )
13          where rn=2) b,
14          (select numerals,rownum rn1 from
15          (
16              select numerals,mod(row_number() over(partition by 1 order by numerals),3)
17              from random_numeral
18          )
19          where rn=0) c
20  where   a.rn1=b.rn1(+)
21  and b.rn1=c.rn1(+)
22  /
A.NUMERALS||'/'||B.NUMERALS||'/'||C.NUMERALS
1 / 2 / 3
4 / 5 / 6
11 / 24 / 56
85 / 100 / 114
120 / 140 /
SQL>Cheers,
Mohana