How to compare index names and columns from different user?
I am using below query to compare two indexes from 2 different users but even though index name and columns are same... result shows me they are different.. what I am doing wrong? Thanks
WITH t AS
(SELECT COUNT (DISTINCT index_owner || index_name || indexed_cols)
cnt
FROM ( SELECT index_owner,
index_name,
listagg (column_name, ',')
WITHIN GROUP (ORDER BY column_position)
indexed_cols
FROM dba_ind_columns
WHERE index_name='XPKTBL_A'
GROUP BY index_owner, index_name))
SELECT CASE
WHEN cnt > 1 THEN 'Indexes are different'
WHEN cnt = 0 THEN 'Indexes dont exist'
WHEN cnt > 1 THEN 'Indexes are identical'
END
commnt
FROM t
Result:
Indexes are different
but Actually if you check below they are same After when I run this query:
SELECT index_owner,
index_name,
listagg (column_name, ',') WITHIN GROUP (ORDER BY column_position)
indexed_cols
FROM dba_ind_columns
WHERE index_name='XPKTBL_A'
GROUP BY index_owner, index_name;
Result:
Index_owner
Index_name
Index_cols
USER1
XPKTBL_A
FIELD_A1
USER2
XPKTBL_A
FIELD_A1
Hi,
Erhan_toronto wrote:
I am using below query to compare two indexes from 2 different users but even though index name and columns are same... result shows me they are different.. what I am doing wrong? Thanks
WITH t AS
(SELECT COUNT (DISTINCT index_owner || index_name || indexed_cols)
So index_owner is 'USER1' in one case, and 'USER2' in the other; right?
A string that starts with 'USER1' will be distinct from a string that starts with 'USER2', no matter what the rest of the string contains. Maybe you don't want to compare the owners, or maybe you meant to use some other column (such as table_name) instead of index_owner).
I hope this answers your question.
If not, post a little sample data (CREATE TABLE, CREATE INDEX and CONNECT statements), and also post the results you want from that data.
Explain, using specific examples, how you get those results from that data.
Always say which version of Oracle you're using (e.g., 11.2.0.2.0).
See the forum FAQ: https://forums.oracle.com/message/9362002
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