How to compare two fields in condition editor in receiver determination

Hello,
Is it possible to compare to fields frrom the source in the condition editor of Receiver Determination?
Because on the right hand operand we can specify only constants right and not the source field.
For eg: If field1 != field2 then Reciever = Receiver1
Thanks,
Loveena

In standard receiver determination while defining the condition, you can only specify an element from the message payload using expression editor to create an expression for the left operand and you must specify a fixed value in the right operand, against which the value of the element will be compared at runtime. You can use only these (=,, ,EX) operators. So the functionalities are limited.
so you have to use Enhanced Receiver Determination, In this Instead of creating the receivers in the receiver determination manually, you assign an Interface mapping to the receiver determination and this returns a list of receivers at runtime.
refer this wiki for more details
http://wiki.sdn.sap.com/wiki/pages/viewpage.action?pageId=133562771

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For example, this
data: cptotchek tyep i.
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Hi ,
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Hi,
I have a fixed length flat file coming in into which I have to look at the first line's 4th to 7th positions. Based on that if it is "1234" then I need to route it to the receiver else I will ignore in the receiver determination.
Example input file -
M 0123456789ABCDEFGHIJKL
PR0123456789JIDFJDIFJD0244
PA0123456789JFDJF9384384K
We have module configuration where we are converting this to a line value pair something like this -
<?xml version="1.0" encoding="utf-8"?>
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How to check for the XPATH value for null, My scenario is i have to assign the receiver depending upon the XPATH value and i need to assign a receiver if the node does not exist.
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Hi Shree,
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for more-
http://help.sap.com/saphelp_nw2004s/helpdata/en/67/49767669963545a071a190b77a9a23/frameset.htm
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PhoenixBai wrote:
Hi All,
How to compare two rows in PL/SQL? Is there any method that I can use instead of comparing them column by column?What "rows" are you referring to?
If you're talking of rows within a PL/SQL associative array there are techniques as described in the documentation... e.g.
SQL> ed
Wrote file afiedt.buf
1 declare
2    type v1 is table of number;
3    r1 v1 := v1(1,2,4);
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Different
PL/SQL procedure successfully completed.
SQL> ed
Wrote file afiedt.buf
1 declare
2    type v1 is table of number;
3    r1 v1 := v1(1,2,3);
4    r2 v1 := v1(1,2,3);
5 begin
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Same
PL/SQL procedure successfully completed.
SQL>If you're talking about rows on a table then you can use the MINUS set operator to find the rows that differ between two sets of data...
SQL> select * from emp;
     EMPNO ENAME      JOB              MGR HIREDATE                    SAL       COMM     DEPTNO
      7369 SMITH      CLERK           7902 17-DEC-1980 00:00:00        800                    20
      7499 ALLEN      SALESMAN        7698 20-FEB-1981 00:00:00       1600        300         30
      7521 WARD       SALESMAN        7698 22-FEB-1981 00:00:00       1250        500         30
      7566 JONES      MANAGER         7839 02-APR-1981 00:00:00       2975                    20
      7654 MARTIN     SALESMAN        7698 28-SEP-1981 00:00:00       1250       1400         30
      7698 BLAKE      MANAGER         7839 01-MAY-1981 00:00:00       2850                    30
      7782 CLARK      MANAGER         7839 09-JUN-1981 00:00:00       2450                    10
      7788 SCOTT      ANALYST         7566 19-APR-1987 00:00:00       3000                    20
      7839 KING       PRESIDENT            17-NOV-1981 00:00:00       5000                    10
      7844 TURNER     SALESMAN        7698 08-SEP-1981 00:00:00       1500          0         30
      7876 ADAMS      CLERK           7788 23-MAY-1987 00:00:00       1100                    20
      7900 JAMES      CLERK           7698 03-DEC-1981 00:00:00        950                    30
      7902 FORD       ANALYST         7566 03-DEC-1981 00:00:00       3000                    20
      7934 MILLER     CLERK           7782 23-JAN-1982 00:00:00       1300                    10
14 rows selected.
SQL> select * from emp2;
     EMPNO ENAME      JOB              MGR HIREDATE                    SAL       COMM     DEPTNO
      7521 WARD       SALESMAN        7698 22-FEB-1981 00:00:00       1250        500         30
      7566 JONES      MANAGER         7839 02-APR-1981 00:00:00       2975                    20
      7782 CLARK      MANAGER         7839 09-JUN-1981 00:00:00       2450                    10
      7788 SCOTT      ANALYST         7566 19-APR-1987 00:00:00       3000                    20
      7839 KING       PRESIDENT            17-NOV-1981 00:00:00       5000                    10
      7900 JAMES      CLERK           7698 03-DEC-1981 00:00:00        950                    30
      7934 MILLER     CLERK           7782 23-JAN-1982 00:00:00       1300                    10
7 rows selected.
SQL> select * from emp
2 minus
3 select * from emp2;
     EMPNO ENAME      JOB              MGR HIREDATE                    SAL       COMM     DEPTNO
      7369 SMITH      CLERK           7902 17-DEC-1980 00:00:00        800                    20
      7499 ALLEN      SALESMAN        7698 20-FEB-1981 00:00:00       1600        300         30
      7654 MARTIN     SALESMAN        7698 28-SEP-1981 00:00:00       1250       1400         30
      7698 BLAKE      MANAGER         7839 01-MAY-1981 00:00:00       2850                    30
      7844 TURNER     SALESMAN        7698 08-SEP-1981 00:00:00       1500          0         30
      7876 ADAMS      CLERK           7788 23-MAY-1987 00:00:00       1100                    20
      7902 FORD       ANALYST         7566 03-DEC-1981 00:00:00       3000                    20
7 rows selected.If you actually need to know what columns data is different on "non-matching" rows (based on your primary key) then you'll have to compare column by column.

How to compare two fields in condition editor in receiver determination

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