How to Configure my url in Apache server?

i have an Apache webserver.i want to give url as desired say.http://intranet.com. Now iam giving my machine ip address as "127.0.101:9000 "to get my html page displayed from a remote terminal in a intranet network.
How to configure the apache so that i can replace the ip address with my desired name url type. Please help me.

How to configure the apache so that i can replace the
ip address with my desired name url type. Please help
me.Apache cannot do anything about this . It is your network DNS and DHCP that does this for you .If u edit the hosts file in a pc on ur lan ,then u can invoke from this m/c with the string as long as ur m/c isnt re-booted .This is assuming that u do not have a static IP adress .

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i my use case i have created simple adf application using ADF BC and want to deploy on Apache server 6.x.
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<Resource name="jdbc/TestDB" auth="Container"
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check link-
https://forums.oracle.com/thread/2564233
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<GlobalNamingResources>
    
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              driverClassName="oracle.jdbc.driver.OracleDriver"
              factory="oracle.jdbc.pool.OracleDataSourceFactory"
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</GlobalNamingResources>
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<ResourceLink global="jdbc/TestDB" name="jdbc/TestDB" type="oracle.jdbc.pool.OracleDataSource"/>
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log-
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at org.apache.taglibs.standard.tag.common.sql.QueryTagSupport.doStartTag(QueryTagSupport.java:181)
at org.apache.jsp.test_jsp._jspx_meth_sql_005fquery_005f0(test_jsp.java:110)
at org.apache.jsp.test_jsp._jspService(test_jsp.java:63)
at org.apache.jasper.runtime.HttpJspBase.service(HttpJspBase.java:70)
at javax.servlet.http.HttpServlet.service(HttpServlet.java:820)
at org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:374)
at org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:342)
at org.apache.jasper.servlet.JspServlet.service(JspServlet.java:267)
at javax.servlet.http.HttpServlet.service(HttpServlet.java:820)
at org.apache.catalina.core.ApplicationFilterChain.internalDoFilter(ApplicationFilterChain.java:290)
at org.apache.catalina.core.ApplicationFilterChain.doFilter(ApplicationFilterChain.java:206)
at org.apache.catalina.core.StandardWrapperValve.invoke(StandardWrapperValve.java:233)
at org.apache.catalina.core.StandardContextValve.invoke(StandardContextValve.java:191)
at org.apache.catalina.core.StandardHostValve.invoke(StandardHostValve.java:128)
at org.apache.catalina.valves.ErrorReportValve.invoke(ErrorReportValve.java:102)
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at org.apache.tomcat.util.net.AprEndpoint$Worker.run(AprEndpoint.java:1509)
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at org.apache.taglibs.standard.tag.common.sql.QueryTagSupport.getConnection(QueryTagSupport.java:298)
at org.apache.taglibs.standard.tag.common.sql.QueryTagSupport.doStartTag(QueryTagSupport.java:181)
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at org.apache.jasper.runtime.HttpJspBase.service(HttpJspBase.java:70)
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at org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:342)
at org.apache.jasper.servlet.JspServlet.service(JspServlet.java:267)
at javax.servlet.http.HttpServlet.service(HttpServlet.java:820)
at org.apache.catalina.core.ApplicationFilterChain.internalDoFilter(ApplicationFilterChain.java:290)
at org.apache.catalina.core.ApplicationFilterChain.doFilter(ApplicationFilterChain.java:206)
at org.apache.catalina.core.StandardWrapperValve.invoke(StandardWrapperValve.java:233)
at org.apache.catalina.core.StandardContextValve.invoke(StandardContextValve.java:191)
at org.apache.catalina.core.StandardHostValve.invoke(StandardHostValve.java:128)
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at org.apache.tomcat.util.net.AprEndpoint$Worker.run(AprEndpoint.java:1509)
at java.lang.Thread.run(Thread.java:662)
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<%@ taglib uri="http://java.sun.com/jsp/jstl/sql" prefix="sql" %>
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select empname from pay_emphdr where empcd='JK1306'
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<html>
<head>
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<body>
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<c:forEach var="row" items="${rs.rows}">
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</c:forEach>
</body>
</html>
please help me. it is very urgent.
thanks in Advance
Manish

Hi Lindalnci
i have already tried this tutorial and in my post i have defined first way to do using this procedure.
in that case i have got following exception as i have mentioned above
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