How to create a common function in Sqlserver to get Effective working hours of employee

Question

Hi
The following is the logic applied in the application , But I want to create an server function , Pls help
adc_opening  is starting time and   is an argument 1
adc_break is finishing time and   is an argument 2
adc_break is breake time and   is an argument 3
My  Existing logic is  given below, I want to create sqlserver function , to replace the given logic. Please help
long ll_opening_in_minutes, ll_closing_in_minutes, ll_break_in_minutes, ll_effective_in_minutes
decimal {2} ldc_result
ll_opening_in_minutes = truncate(adc_opening, 0) * 60 + (adc_opening - truncate(adc_opening, 0)) * 100
ll_closing_in_minutes = truncate(adc_closing, 0) * 60 + (adc_closing - truncate(adc_closing, 0)) * 100
// If the closing time is on the next day, add 24 hours to the value
if ll_closing_in_minutes < ll_opening_in_minutes then ll_closing_in_minutes += 24 * 60
ll_break_in_minutes = truncate(adc_break, 0) * 60 + (adc_break - truncate(adc_break, 0)) * 100
// Use max function to disallow negative results
ll_effective_in_minutes = Max(ll_closing_in_minutes - ll_opening_in_minutes - ll_break_in_minutes, 0)
ldc_result = truncate(ll_effective_in_minutes / 60, 0) + mod(ll_effective_in_minutes, 60) / 100
return ldc_result
polachan

Answer 1

That is not datetime information, the argument of the function 
adc_opening = 8.30
adc_break = 1.00
 adc_closing = 17.30
I want to get net hours  ( 8.30 - 17.30 ) - 1.00 . The result minutes  part
 should be shown like 
if .75  should be shown as .45.  if .50 should be shown as .30  , if  .25  as
.15. 
I cannot give datediff function because the argument will not be  the date , its like decimal  
as I given above.
Any idea
polachan
isnt it enough to multiply by 0.6?
0.75 * 0.6 = 0.45
0.5 * 0.6 = 0.3 etc
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