How to create oracle scheduled job

Question

DECLARE
jobno NUMBER;
BEGIN
SYS.DBMS_JOB.SUBMIT
( job => jobno
,what => 'DEL_HIST_TABLE;'
,next_date => to_date('09/04/2009 18:23:00','dd/mm/yyyy hh24:mi:ss')
,interval => 'null'
,no_parse => TRUE
SYS.DBMS_OUTPUT.PUT_LINE('Job Number is: ' || to_char(jobno));
END;
commit;
i wrote the above job to run on specific time and date
but i want to convert the same to run on
every day @ 1:00 am using oracle 10g
Edited by: [email protected] on May 17, 2009 11:39 PM

Answer 1

Hi,
You need to set the interval then:
MHO%xe> select trunc(sysdate) + 1/24 + 1 from dual;
TRUNC(SYSDATE)+1/24
19-05-2009 01:00:00
1 rij is geselecteerd.
MHO%xe> DECLARE
  2  jobno NUMBER;
  3  BEGIN
  4  SYS.DBMS_JOB.SUBMIT
  5  ( job => jobno
  6  ,what => 'begin null; end;'
  7  ,next_date => to_date('09/04/2009 18:23:00','dd/mm/yyyy hh24:mi:ss')
  8  ,interval => 'trunc(sysdate) + 1/24 + 1'
  9  ,no_parse => TRUE
10  );
11  SYS.DBMS_OUTPUT.PUT_LINE('Job Number is: ' || to_char(jobno));
12  END;
13  /
Job Number is: 21
PL/SQL-procedure is geslaagd.
Verstreken: 00:00:11.39
MHO%xe> commit;
Commit is voltooid.
MHO%xe> select interval from user_jobs where job = 21;
INTERVAL
trunc(sysdate) + 1/24 + 1
1 rij is geselecteerd.Edited by: hoek on May 18, 2009 8:49 AM added to example