How to create several colums if many rows

Hi,
I have a problem with finding a technical solution. If I have more than 30 records, I want to put them in the next column. How do I do this in xsl (HTML output):
|PCS|REV|DATE | |PCS|REV|DATE |
| 1 | 1 |xx.xx.xx| | 5 | 1 |xx.xx.xx|
| 2 | 1 |xx.xx.xx| | 6 | 1 |xx.xx.xx|
| 3 | 1 |xx.xx.xx| | 7 | 1 |xx.xx.xx|
| 4 | 1 |xx.xx.xx|
Is this something you can help me with?
Where can I learn more about xsl, xpath, xml, xslt etc?

My book Building Oracle XML Applications has a technical introduction to XML, XML Namespaces, XPath, XSLT, and contains 17 chapters of examples of using these technologies together with the Oracle XML platform in Java, PL/SQL, and with XSQL Pages. You can checkout reviews at: http://www.amazon.com/exec/obidos/ASIN/1565926919
Here's a solution to your XSLT problem.
Given an XML source like:
<terje>
<rec rev="a" date="xx.xx.xxxx"/>
<rec rev="b" date="xx.xx.xxxx"/>
<rec rev="c" date="xx.xx.xxxx"/>
<rec rev="d" date="xx.xx.xxxx"/>
<rec rev="e" date="xx.xx.xxxx"/>
<rec rev="f" date="xx.xx.xxxx"/>
<rec rev="g" date="xx.xx.xxxx"/>
<rec rev="h" date="xx.xx.xxxx"/>
<rec rev="i" date="xx.xx.xxxx"/>
<rec rev="j" date="xx.xx.xxxx"/>
<rec rev="k" date="xx.xx.xxxx"/>
<rec rev="l" date="xx.xx.xxxx"/>
<rec rev="m" date="xx.xx.xxxx"/>
<rec rev="n" date="xx.xx.xxxx"/>
<rec rev="o" date="xx.xx.xxxx"/>
<rec rev="p" date="xx.xx.xxxx"/>
<rec rev="q" date="xx.xx.xxxx"/>
<rec rev="r" date="xx.xx.xxxx"/>
<rec rev="s" date="xx.xx.xxxx"/>
<rec rev="t" date="xx.xx.xxxx"/>
<rec rev="u" date="xx.xx.xxxx"/>
<rec rev="v" date="xx.xx.xxxx"/>
<rec rev="w" date="xx.xx.xxxx"/>
<rec rev="x" date="xx.xx.xxxx"/>
<rec rev="y" date="xx.xx.xxxx"/>
<rec rev="z" date="xx.xx.xxxx"/>
<rec rev="aa" date="xx.xx.xxxx"/>
<rec rev="ab" date="xx.xx.xxxx"/>
<rec rev="ac" date="xx.xx.xxxx"/>
<rec rev="ad" date="xx.xx.xxxx"/>
<rec rev="ae" date="xx.xx.xxxx"/>
<rec rev="af" date="xx.xx.xxxx"/>
<rec rev="ag" date="xx.xx.xxxx"/>
<rec rev="ah" date="xx.xx.xxxx"/>
<rec rev="ai" date="xx.xx.xxxx"/>
</terje>the following stylesheet renders the columnized output as you want, with a parameterizable number of records per column.
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">

<xsl:param name="per-col" select="30"/>

<xsl:variable name="num-col" select="ceiling(count(terje/rec) div $per-col)"/>
<xsl:template match="/">
<html>
<body>
<table border="1" cellspacing="0">
<tr>

<xsl:apply-templates mode="header"
select="terje/rec[position() mod $per-col = 1]"/>
</tr>

<xsl:apply-templates mode="row"
select="terje/rec[$per-col >= position()]"/>
</table>
</body>
</html>
</xsl:template>

<xsl:template match="rec" mode="row">
<tr>
<xsl:variable name="rowrecs"
select=".|following-sibling::rec[position() mod $per-col = 0]"/>
<xsl:variable name="num-rowrecs" select="count($rowrecs)"/>
<xsl:apply-templates select="$rowrecs"/>

<xsl:if test="$num-col > $num-rowrecs">
<xsl:call-template name="empty-row"/>
</xsl:if>
</tr>
</xsl:template>
<xsl:template match="rec">
<td><xsl:value-of select="count(preceding-sibling::rec)+1"/></td>
<td><xsl:value-of select="@rev"/></td>
<td><xsl:value-of select="@date"/>&lt ;/td>
</xsl:template>
<xsl:template match="rec" mode="header">
<th>PCS</th><th>Rev</th><th>Date</th>
</xsl:template>
<xsl:template name="empty-row">
<td> </td>
<td> </td>
<td> </td>
</xsl:template>
</xsl:stylesheet>Hope this helps.
Steve Muench
Lead Product Manager for BC4J and Lead XML Evangelist, Oracle Corp
Author, Building Oracle XML Applications
null

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