How to determine line # from printstack() with cc compiler on Solaris 10

Question

Hi,
printstack() when called produces a stack trace per the following:
/lib/libc.so.1:0xc5364
/lib/libc.so.1:0xb9e64
/platform/sun4u-us3/lib/libc_psr.so.1:memcpy+0x660 [ Signal 11 (SEGV)]
/opt_outside_local_disk/opt/zim/bin/program_name:function_name+0x160
How does one determine what the line # is in the C program for the above offset 0x160?
Thanks in advance.
Joe

Answer 1

Hi Joe,
I don't know what is the best way, but here is a 3-steps procedure to find the line.
I inserted a printstack(2) line in my program, and got this output:
/export/home/nikm/SunStudioProjects/4Queens/NQueens'main+0x711 [0x4023f9]I use Sun Studio 12 update 1 to compile my program.
It includes Performance Analyzer tools, and one of its utilities, "er_src", can help to find the line.
First of all, let's run it with "-disasm" option to find the line number, that corresponds to the address 4023f9:
nikm@OS-Dec2008:~$  er_src -disasm main  /export/home/nikm/SunStudioProjects/4Queens/NQueens | grep 4023f9
                [137]   4023ed:  jle     .+0xc [ 0x4023f9 ]
                [141]   4023f9:  movq    0x11280(%rip),%rsiBasically, that's it, we have the line number - it is 141.
Let's verify that this is correct:
nikm@OS-Dec2008:~$  er_src -src main  /export/home/nikm/SunStudioProjects/4Queens/NQueens | grep -n '141\.'
214:           141.     return total_pos;Well, it points to the line after the printstack(2) statement. Let's verify this:
nikm@OS-Dec2008:~$  er_src -src main  /export/home/nikm/SunStudioProjects/4Queens/NQueens | head -214 | tail -5
           137.     if (debug > 0) {
           138.         printstack(2);
           139.     }
           140.
           141.     return total_pos;
nikm@OS-Dec2008:~$ That's it. The line is 138, and printstack(2) actually points to the next line.
Thanks.
Nik
Edited by: NikMolchanov on Aug 29, 2009 10:10 PM
Edited by: NikMolchanov on Aug 29, 2009 10:11 PM