How to determine the Java version in Windows XP

In Windows 2000, I can determine the version of Java that's running by typing 'java -version' in a command prompt. However, when I type this in a command prompt in Windows XP, a message says 'java is not recognized as an internal or external command ...'.
Is there some other means of determining the version of Java that's running on Windows XP?
Thank you.

I found the directory with java.exe on my XP client. After updating my Path and then typing 'java -versions' I still see a 'java not found message'. No problem though - a README.TXT says that I have JRE 1.1.7B.
One final question - a co-worker who also has XP just starting seeing a pop-up window saying 'Runtime' error when running a Java applet. His java.exe is in a path that includes the sub-directory 'JRE' On my XP client, java.exe is in a path which includes a 'JRE11' sub-directory. We therefore seem to have different versions of the JRE. Since I don't see the Runtime error when running the same applet, should my co-worker try upgrading his JRE?
Thank you.

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One final question - a co-worker who also has XP just starting seeing a pop-up window saying 'Runtime' error when running a Java applet. His java.exe is in a path that includes the sub-directory 'JRE' On my XP client, java.exe is in a path which includes a 'JRE11' sub-directory. We therefore seem to have different versions of the JRE. Since I don't see the Runtime error when running the same applet, should my co-worker try upgrading his JRE?
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