How to find xml attributes valus

var xml:XML=
<root>
<country id="0">
<states id="0_0">
<city id="0_0_0">
<village id="0_0_0_0"></village>
<village id="0_0_0_1"></village>
<village id="0_0_0_2"></village>
</city>
</states>
<states id="0_1">
</states>
</country>
<country id="1"></country>
</root>;

duplicate post.

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Whoa, easier than I'd thought...
When the page first shows up, there's the About This Page link, at the bottom, clicking it you get to the About Page.
I noted two sections, Page Definition and Business Component References Details.
I expanded Business Component References Details and found View Objects. There's a list of views used. I was dismayed that the views don't appear to be in the database. Of course, they're camelCased Java names of Java objects, not database names (although sometimes some of the camelCased tokens might correspond to parts of view names). They are, however, clickable and when clicked the definition shows up, and I was thinking that it would take a long while to find what I was seeking.
But... Hit the Expand All link in Page Definition, do a find on page for the desired label, and there it is... a row with the label, view object name and attribute! Pay dirt!
Then go to the Business Component References Details, find the View Object, click it, and there's the view :-) Find the attribute, then the table... easy peasy!
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LOOP
loops through tables for a case.
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v_sql:='select * from '||j.table_name||' where case_id='||i.case_id;
Here I need to get the output of the above query in xml format. There will have to be xmlattributes.
End loop;
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<Case repeating index="1">
<CASE_ID>970200</CASE_ID>
<STATUS>CLO
SED</STATUS>
<RESOLUTION>Charge Off Booked</RESOLUTION>
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<Case repeating index="2">
<CA
SE_ID>970670</CASE_ID>
<STATUS>CLOSED</STATUS>
<RESOLUTION>Immediate Denial<
/RESOLUTION>
</Case>
<Case repeating index="3">
<CASE_ID>980030</CASE_ID>
<STATUS>CLOSED</STAT
US>
<RESOLUTION>Total Avoidance</RESOLUTION>
</Case>
</ROWSET>

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How to write XML with attributes to a table in Oracle?

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In all these cases, the solution considers XML structure with only nodes and child nodes but not attributes. In fact, one of the solutions suggests transforming the XML into a canonical form with only nodes w/o attributes.
This is a sample of xml structure I am working with:
Sample XML
<rep type="P" title="P List"> <as> <a id="3" /> <a id="4" /> </as> </rep>
I am working with oracle client 11.2 and SQL developer
My question is: how to write XML data into a table with attributes also as column values, beside the nodes?

My question is: how to write XML data into a table with attributes also as column values, beside the nodes
The question you should be asking is : "how do I access attributes in the XPath language?"
and the answer to that is easily found in any XPath tutorial you may find over the Internet, it is not related to Oracle in particular.
Short answer : you use an "attribute::" axis before the attribute name, or more commonly a "@", e.g. @type, @id etc.
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SELECT x.*
FROM XMLTable(
 '/rep'
 passing <xmltype variable/column goes here>
 columns type varchar2(1) path '@type'
 , title varchar2(30) path '@title'
) x ;
For deeper levels, use additional XMLTable calls as described in the mentioned post.

How to read an attribute of an xml tag in jsp.

hi guys,
This is murali krishna. i have a small problem,
i have one xml file (books.xml)
<?xml version="1.0" encoding="iso-8859-1"?>
<library>
<book id="1">
<name>Head First Java, 2nd Edition</name>
<author>Kathy Sierra and Bert Bates</author>
<publication-date>09-Feb-2005</publication-date>
</book>
<book id="2">
<name>Effective Java</name>
<author>Joshua Bloch</author>
<publication-date>28-May-2008</publication-date>
</book>
<book id="3">
<name>Java How to Program, 7th Edition</name>
<author>Harvey M. Deitel and Paul J. Deitel</author>
<publication-date>6-Jan-2007</publication-date>
</book>
</library>
I tried to read this xml file in jsp as shown below
<%@ page language="java" %>
<%@ page import="org.w3c.dom.*" %>
<%@ page import="javax.xml.parsers.DocumentBuilder" %>
<%@ page import="javax.xml.parsers.DocumentBuilderFactory" %>
<%
DocumentBuilderFactory dbf=DocumentBuilderFactory.newInstance();
DocumentBuilder db =dbf.newDocumentBuilder();
Document doc=db.parse("c:\\books.xml");
NodeList nl = doc.getElementsByTagName("book");
%>
<html>
<head>
<title>How to read XML file in JAVA</title>
</head>
<body>
<%
for(int i=0;i<nl.getLength();i++)
NodeList nameNlc= doc.getElementsByTagName("name");
Element nameElements=(Element)nameNlc.item(i);
String nameTagValue=nameElements.getChildNodes().item(0).getNodeValue();
NodeList authorNlc= doc.getElementsByTagName("author");
Element authorElements=(Element)authorNlc.item(i);
String authorTagValue=authorElements.getChildNodes().item(0).getNodeValue();
NodeList dateNlc= doc.getElementsByTagName("publication-date");
Element dateElements=(Element)dateNlc.item(i);
String dateTagValue=dateElements.getChildNodes().item(0).getNodeValue();
out.println("name :"+nameTagValue+" ");
out.println("author :"+authorTagValue+" ");
out.println("publication-date :"+dateTagValue+" ");
%>
</body>
</html>
so, my problem is I was unable to read the attribute of the tag book , that is "id".
can any one tell me how to read this "id" attribute.
Murali Krishna
[email protected]

hi,
U r retriving the elements by tag name.So it just chks the tag name ie.<book> & gives u array of elements.But u need retrive d attribute of <book> tag itself.
=Solution =====
Add one more statement ----> var[]= doc.getElementsByName("book");
Now u hav book elements as an array & can retrive id in for loop
for(var; var.length;var++)
doc.element[var].id.value

How to find xml attributes valus

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