How to get difference between two rows for a column field?

hi, all,
Could anyone show me what query statement is to get the difference betweem two rows for two column fields?
The tables and its records are like this:
id,      begin,      end
p1         21          30
p2          45          60
p3          120          150
I would like to have the query result like this
id,    diff
p1     15    --- which is 45 minus 30
p2     60    --- which is 120 minus 60
and so on...
thank you in advance.
Raffy

You can use the LAG function to access values from previous rows:
with q as (select 'p1' id, 21 v_start, 30 v_end from dual
union all
select 'p2', 45, 60 from dual
union all
select 'p3', 120, 150 from dual)
select id, v_start, v_end, v_start - lag (v_end, 1, 0)
over (order by id) v_diff from q
ID,V_START,V_END,V_DIFF
p1,21,30,21
p2,45,60,15
p3,120,150,60
See the SQL Language doc
http://docs.oracle.com/cd/B28359_01/server.111/b28286/functions075.htm

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I don't understand how most of the answers provided here not analytically solving the problem with many cases possible.
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SELECT
CASE
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