How to get path

Hello
How do I get the current path an object is executing from? This is for a simple test. I have a file I want to open up within my object. That file is being copied to the .class directory where my object is. I just want to figure out how to use some static method of the Class to find where it is so I can use it. I am sure this is the wrong way to do it, if even possible. I just need this as a "throwaway" technique. tia.

See http://www.rgagnon.com/javadetails/java-0076.html

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How to get path of a specified file

how to get path of a specified folder
my code is as follows: Iam using struts 1.2
my directory structure in tomcat/webapp is as afollows:
sfq
|
| _ _xml
| |
| |_ _ sqx_read.xml
|
|__jsp
|
|__WEB-INF
     |
     |_ _classes
          |
          |_ _ReadXml.class
Now i have to get the path of a sql_read.xml file which is in xml folder from ReadXml.java file. pls it's urgent

Urgent or not, you can obtain the document root directory as
ServletContext.getRealPath("/")

How to get path of downloaded file?

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I use JDeveloper 11g with ADF.
I have to download file with original date. If i want to save date i have to zip file. After that to unzip. My queation is: when clien download file how to get path of downloaded file????
Because, i want to save unziped file on location where client want to download.

Hi,
you cannot download a file directly to a client. If this is a requirement then you need a signed Java Applet to handle the download. Otherwise a download dialog is opened for the user to define where to store the file.
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I am using a class which is present in a jar file.
There are lot of versions of this jar file are present on machine.
I am accessing one class from this jar.
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URL jarURL = this.getClass().getResource("/whatever.class");will return you a jar:// URL. Experiment with that. (Remember that "whatever.class" needs to be prefixed by the full name of the package the class is in.)

How-to get path to a node in SPRO

Hello guys,
I'm working on a tool which creates automatic dcumentation tool of changes in SPRO. All goes fine except one thing:
I need to generate a PATH to IMG ACTIVITY. I know the code of activity, I know it's HIER_GUID. What I need to get is all "parents" HIER_GUID of bottom node.
So far I got only one FM - STREE_GET_PATH_TO_NODE. It's fine but it returns only the path to 03 level in SPRO. (01 - is top, 02 - are components).
What I desperatly need is how to get a connection from 03 to 02 level.
You can simulate the FM with following values:
SEARCH_FOR_NODE-NODE_ID = 1C1B49FEC279D411AB74009027B70B8E
SEARCH_FOR_NODE-TREE_ID = 367A8DF9ACEE16E7E10000009B38F976
The result contain the highest node id 367A8DAFACEE16E7E10000009B38F976, which stands for "SAP Business Parnter" (according the table TNODEIMGT-NODE_ID).
But the fact, that "SAP Business Partner" is in "Cross-Application Components" is unreachable for me.
Do you know, how to get relevant node on level 02 ?
All hints will be rewarded.
Thank you
Regards
Tomas

Hello guys,
I'm working on a tool which creates automatic dcumentation tool of changes in SPRO. All goes fine except one thing:
I need to generate a PATH to IMG ACTIVITY. I know the code of activity, I know it's HIER_GUID. What I need to get is all "parents" HIER_GUID of bottom node.
So far I got only one FM - STREE_GET_PATH_TO_NODE. It's fine but it returns only the path to 03 level in SPRO. (01 - is top, 02 - are components).
What I desperatly need is how to get a connection from 03 to 02 level.
You can simulate the FM with following values:
SEARCH_FOR_NODE-NODE_ID = 1C1B49FEC279D411AB74009027B70B8E
SEARCH_FOR_NODE-TREE_ID = 367A8DF9ACEE16E7E10000009B38F976
The result contain the highest node id 367A8DAFACEE16E7E10000009B38F976, which stands for "SAP Business Parnter" (according the table TNODEIMGT-NODE_ID).
But the fact, that "SAP Business Partner" is in "Cross-Application Components" is unreachable for me.
Do you know, how to get relevant node on level 02 ?
All hints will be rewarded.
Thank you
Regards
Tomas

How to get path to file variable with applescript

I've tried:
`set file_path to path of myfile`
but it's giving me error:
`error "Finder got an error: Can’t get path of document file ..."`

Code is:
set theFolder to (choose folder with prompt "Select the start folder")
set file_list to every file of theFolder
repeat with myfile in file_list
    set file_name to name of myfile
    set file_path to path of myfile
    log (file_path & "/" & file_name as string)
end repeat

How to get path or parent folder

Hello
I'm overriding method extendedPreAddRelationship on class S_Relationship.
My purpose is to check whether the document is being put in the correct path or not.
I can get folder name and document name using following code:
AttributeValue av;
av = def.getAttribute(Relationship.LEFTOBJECT_ATTRIBUTE);
S_PublicObject folder = (S_PublicObject) av.getPublicObject(this.getSession());
av = def.getAttribute(Relationship.RIGHTOBJECT_ATTRIBUTE);
S_PublicObject document = (S_PublicObject) av.getPublicObject(this.getSession());
What I need is the whole path (or at least the parent folder). Can I get path somehow? Or should I try to search parent folders?
Jaska

My purpose is to check whether the document is being put in the correct path or not.Hi,
I had a similar problem - I needed to compare the path of current folder with path from parameters. Because I wasn't be able to get the path of folder, I did it in reverse way, comparing the folders. To get folder from path I needed getRootFolder method, which wasn't in server-side classes, so I extend S_TieFolder class:
* Analogy of LibrarySession.getRootFolder().
public static S_Folder getRootFolder(S_LibrarySession session)
throws IfsException
S_Folder folder = null;
try
Collection c = session.getValueDefaultCollection();
S_ValueDefault vd = (S_ValueDefault)c.getItems("RootFolder");
AttributeValue av = vd.getPropertyValue();
folder = (S_Folder)av.getPublicObject(session);
catch(Exception e)
throw new IfsException(21020, e, session);
return folder;
In extendedPreAddItem method of S_TieFolder:
S_Folder paramFolder = (S_Folder)getRootFolder(session).findPublicObjectByPath(folderPath);
if( this==paramFolder ) ...
Radek
[email protected]

How to get path of a VI used in LV project?

How can I get the path of a VI used in LabVIEW project?
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There are several ways to replace a VI, say "MyFirstVI", with another, say "MySecondVI". The method you use will depend on several factors, including
the version of LabVIEW you are running
whether the VIs are in a LabVIEW Project or not (if they are, I'm assuming they are in the same Project)
whether you want to replace all MyFirstVI instances with MySecondVI, or selected ones
the size (number of VIs) of the Project.
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Close the Project. You do not want to do this with Project open.
Rename MyFirstVI to MyOldFirstVI.
Rename MySecondVI to MyFirstVI. If MySecondVI already exists in the Project, you might want to Copy it instead of Rename.
Open the Project. Find and open an instance of MyFirstVI, verify it has the code of MySecondVI.
In Project Explorer, find MyFirstVI and rename it MySecondVI.
Exit Project. Rename MyOldFirstVI back to MyFirstVI.
At this point, all of your VIs have their "original" names, but in, say, Main.vi, wherever MyFirstVI was called, you should see MySecondVI.
For doing selective Replacement (or even total replacement where you want to actually see all of the instances where replacements are made), you can use QuickDrop to your advantage. You need to have in memory the VIs that use MyFirstVI, and also have MySecondVI in memory. With the Project open and the relevant VIs in memory:
Open any VI that shows MyFirstVI on the Block Diagram. Right-click it and choose "Find All Instances".
When the search is done, you need to "visit" each of the found VIs -- use Ctrl-G to do this.
When you find an instance of MyFirstVI, type Ctrl-Space to activate QuickDrop, start typing MySecondVI until it appears on the Selection line (if you are lucky, you will only need to type MySec and it will find the correct VI), then type Ctrl-P to replace MyFirstVI with MySecondVI.
Type another Ctrl-G to go to the next instance of MyFirstVI and replace as needed. When you've replaced all of them (or all that you want to replace), stop.
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[CS4] How to get path from SPPlatformFileSpecification on mac ?

Hi all,
sADMBasic->StandardGetDirectoryDialog() return the directory selected by user in SPPlatformFileSpecification type variable.
when I select the any directory i.e desktop SPPlatformFileSpecification structure contains the following values--
short vRefNum = -100
long parID = 371658
unsigned char name[64] = '\0'
is there any API or alternatives which give the path as char or string like - "/Users/User1/Desktop" from these values?
thanks
D.A

Try this:
SPPlatformFileSpecification spec;
// do sADMBasic->StandardGetDirectoryDialog()
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How to get path of image from server side in form of URL

Hello,
I want to access images stored on server side local folder. How do I create a URL for that. Images in the folder changes dynamically, so I should be able to display the new modified images. Please help me.
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Are you asking from client side to access server (local folder) images...
if yes
where the security goes....
please be in detail...

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Hi!
Lion seems fine for me ... but I can't see the drive capacity / free space which was previously at the bottom of each finder window.
Any ideas where it is? I can't see an option to turn it on, anywhere!
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Ummm...
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How to get path to windows

Hi, I need to locate the path to windows. I've found somewhere this instruction but it always returns null. This is what I have:
System.getProperty("com.ms.windir");
Any help please.
Roel

Just 'cos its deprecated doesn't mean you can't use it, and it certainly doesn't throw an exception - it just displays a warning when you compile it.
I've just done a quick check on System properties, and there isn't one for Windows directory. Abnormal's suggested method is cheating a bit - you're telling it what the directory is, rather than looking it up.
So I'm afraid it's either using getenv, or third party tools (the latter is preferred, as long as they're free!)
Robin

How to get object-path at runtime

Hi, In my application paths of particular controls(radio buttons and links) get changed at runtime. Therefore I cant access those objects. It would be helpful if somebody guide me how to get paths of objects(controls) at runtime. To be more specific following are the paths procured on different time ie. on different runs.
"window(name='incident173747')[1].window(name='ifrmTabWindow')[1].input(name='generateQuote')[1]"
"window(name='incident173750')[1].window(name='ifrmTabWindow')[1].input(name='generateQuote')[1]"
One can see only first window name is changed here.In first case it is :
name='incident173747'
while in the second one it's:
name='incident173750'

Hi Vivek555,
How do you know which radio button or link you want to click on? If each one is called generateQuote, what is in on the page that says "This is the one I want to click on".
Please give a snippet of the html for the page so that we can help you out.
Thanks,
Kevin Gehrke
Empirix, Inc.

Get path to nodes by value

Can enybody please help me. I don't know really how to get path from xml
for example, this is xml:
<?xml version="1.0"?>
<purchase_order>
<po_items>
<item>
<name>#Name#</name>
<quantity>#number#</quantity>
</item>
</po_items>
</purchase_order>
and get out path by variebles #Name# and #number#.
In this case i need to get result:
purchase_order/po_items/item/name
and
purchase_order/po_items/item/quantity

Pitty you did not mention your db version.
putting together some functions from FunctX one can write
SQL> with t as (
select xmltype('<?xml version="1.0"?>
<purchase_order>
<po_items>
<item>
<name>#Name#</name>
<quantity>#number#</quantity>
</item>
</po_items>
</purchase_order>') xml from dual
select x.*
from t t,
xmltable('declare function local:index-of-node ( $nodes as node()* , $nodeToFind as node() ) as xs:integer*
                   for $seq in (1 to count($nodes)) return $seq[$nodes[$seq] is $nodeToFind]
               declare function local:path-to-node-with-pos ( $node as node()? ) as xs:string
                   fn:string-join( for $ancestor in $node/ancestor-or-self::*
                                          let $sibsOfSameName := $ancestor/../*[fn:name() = fn:name($ancestor)]
                                       return fn:concat(fn:name($ancestor),
                                                               if (fn:count($sibsOfSameName) <= 1)
                                                               then "" else fn:concat( "[", local:index-of-node($sibsOfSameName,$ancestor),"]"))
           element e {local:path-to-node-with-pos(//item/name[. = "#Name#"]), element name {//name}},
           element e {local:path-to-node-with-pos(//item/quantity[. = "#number#"]), element name {//quantity}}'
           passing t.xml
           columns value varchar2(50) path 'name',
                        path varchar2(50) path 'text()'
           ) x
VALUE      PATH
#Name#     purchase_order/po_items/item/name
#number#   purchase_order/po_items/item/quantity
2 rows selected.

How to get the current path of my application in java ?

how to get the current path of my application in java ?
thanks

To get the path where your application has been installed you have to do the following:
have a class called "what_ever" in the folder.
then you do a litte:
String path=
what_ever.class.getRessource("what_ever.class").toString()
That get you a string like:
file:/C:/Program Files/Cool_program/what_ever.class
Then you process the result a little to remove anything you don't want:
path=path.substring(path.indexOf('/')+1),path.lastIndexOf('/'))
//Might be a little error here but you should find out //quickly if it's the case
And here you go, you have a nice
C:/Program Files/Cool_program
which is the path to your application.
Hooray

How to get path

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