How to get the day as numeric value without formatting the date?

Hello,
to reduce the costs of a sql-statement I need to get the day of a date-value as number (to compare it to a numeric value) without any formatting. Every formatting results in a full table scan of the table with the date field. Is there any function to solve this problem?
Oracle version is 11g.
Thanks Carsten

CarstenDD wrote:
select T1.SYSID from T2,T1
where T2.SysT1 = T1.SYSID
and T2.Date1 < '01.03.2011' --German date format
and to_number(to_char(T2.Date2,'DD')) = 1
and T2.Inactive = 0
The explain plan shows a full table scan on T2. With EXTRACT(DAY FROM T2.Date2) there is no difference.It probably would and should in any case.
Look at your predicates, which of them would reduce the resultset to a fair size compared to the total number of records in the table?.
- You may have a huge number of records when you say date less than
- Of these perhaps one seventh have day = 1
- My guess is that most have Inactive = 0
Besides, you should not rely on implictit char to date conversion, always use TO_DATE
How many records are in the table? - How many will that query return?
Regards
Peter

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How to get the day as numeric value without formatting the date?

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