How to implement session listener in RM

Hi,
In my repository manager, a connection to another system is established when a user tries to access the repository. Is there any way to implement a session listener, thereby terminating the sessions to another system when the EP user logs off?
In our words, in Repository Manager, how can I know when an EP user clicks Log off?
Thanks,
Ray

Or, how can I know when a user logs off EP in my repository manager?

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How to implement session varibles and how to use it

how to implement session varibles and how to use it.ple help me

Please see the below blog, Hope it helps!!!
http://obieetraining11.blogspot.com/2012/06/create-initialization-block-for-session.html

BC4J/UIX: How to implement session timeout and logout?

Hi,
I need to implement logout function in my UIX application. We use JAZN basic authentication. So several things need to be done when user clicks 'logout'
1. Any pending transaction is rolled-back.
2. App Module - what to do with it?
3. Browser closes or redirects to other page. Any attempts to go BACK will show either 'session expired' or will redirect to login page.
Also I need a mechanism where if user is idle for say, 10 minutes, that he/she will be automatically logout (maybe after some warning message). How to do this?
Thanks
Rade

Well if you search long enough, you will find your own answers. After months of not having this solved, I found the solution, in a piece of sample code from oracle that is distro with the OC4J stuff.
if (request.getRemoteUser() != null) {
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     HttpSession session = request.getSession();
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     String url=null;
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This is the piece I was looking for, a way to kill off the SSO session. Now when I click logoff, the user is actually logged off the application and their HTTP session is killed off as well.
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How to implement a Session Object.

Hi,
If anybody show me any example of how to implement
session object so that I can store any parameters such as user id and use it later on. And also if there is any good web site for reference about using session object.
thanks

You can use the the session.setAttribute and session.getAttribute methods.
For example let's say you would want to store a username in the session after a user has logged on:
String usrname = request.getParameter("username");
session.setAttribute("myStoredUsername", usrname);
you can then retrieve it using the get method. Remember that the entities stored inside a session object are generic objects and need to be cast to be used:
String usrname2 = (String)session.getAttribute("username");
Hope this helps
Chelman

How to implement the Session ManageMent in OracleADF .

Hi I am New to ADF, In my application i have requirement like, I Have a JSPX login page,which contain 4 taskflows as a regions(like AddEmp,DeleteEmp,Create New Dept,Delete Emp), based on the type of user login,i want give different responsibilities(ADF Security, for example a normal employe cant Edit the Other Employe information only HR can do the Edit ), for those who logged in i want to use Session.
Every Time When the user Request the resource it has to check for the session validation.
i know in JEE How to implement Sessions but i don't know in ADF .
Thanks in Advance...

Hi,
have a look here http://download.oracle.com/otn_hosted_doc/jdeveloper/11gdemos/AdfSecurity/AdfSecurity.html
Its a video about ADF Security that explains how you can use custom Resource Permissions for any kind of user authorization, plus the on-board page and task flow permission. Note that the session has nothing to do with authorization. All a session can be is authenticated after which users are associated with enterprise roles, which then are mapped to permissions (through application roles in ADF Security). So session management is not what you are looking for in this case.
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instead of writing isNew() in every jsp page i wanted to write in my central controller ,where each request is passing through controller. can any body give me the solution

i tried it it is failed because first time the request is coming to the controller.it checks for new since of it is a first request it is forwarded to the login page.how to avoid or skip the condition checking when the request is first time.

How can a session scope bean access an application scope bean - help

Hello,
I have a JSP page that has references to an Application Scope and a Session Scope bean...
<jsp:useBean id="myWebApp" scope="application" class="com.my.web.WebApplication" />
<jsp:useBean id="myWebSession" scope="session" class="com.my.web.WebSession" />
I would like the WebSession access methods in the WebApplication ... Can/ How does the WebSession object lookup the reference to WebApplication object?

I don't think you should make the WebSession implement the session listener.
The session listener will be created once, at the start of the servlet context and would be listening to all sessions. So you would have one instance of the WebSession belonging to the context (though not as an attribute), and others belonging to each session. This will be confusing in your code, I think.
I would suggest having a different class act as the HttpSessionListener. Perhaps do something like this:
public class WebSessionInjector implements HttpSessionListener {
public void sessionCreated(HttpSessionEvent e) {
    WebApplication webApp = (WebApplication)(e.getSession().getServletContext().getAttribute("webapp"));
    WebSession mySession = new WebSession();
    mySession.setWebApplication(webApp);
    e.getSession().setAttribute("mySession", mySession);
public void sessionDestroyed(HttpSessionEvent e) { ... }
}You may be able to use the WebApplication object itself as the listener ...
Or, you could make the WebSession implement the HttpSessionBindingListener and use the valueBound event much like the sessionCreated event above, but from inside the WebSession object:
public class WebSession implements HttpSessionBindingListener {
public void valueBound(HttpSessionBindingEvent e) {
    WebApplication webApp = (WebApplication)(e.getSession().getServletContext().getAttribute("webapp"));
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public void valueUnbound(HttpSessionBindingEvent e) { ... }
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How to implement row level security using external tables

Hi All Gurus/ Masters,
I want to implement row level security using external tables, as I'm not sure how to implement that. and I'm aware of using it by RPD level authentication.
I can use a filter condition in my user level so that he can access his data only.
But when i have 4 tables in external tables
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usergroups
webgrups
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Pl let me know this ...

You pull the Group into a repository variable using a session variable init block, then reference that variable in the data filters either in the LTS directly or in the security management as Filters. You reference it with the syntax VALUEOF("NQ_SESSION.Variable Name")
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Webinar: How to implement secure scenarios with SAP NW PI 7.1

SAP Intelligence Platform & NetWeaver RIG APJ Expert Call
Dear valued SAP Experts,
Next SAP Intelligence Platform & NetWeaver RIG Expert Call Session will take place on Tuesday, August 18.
The SAP Intelligence Platform & NetWeaver RIG Expert Call Sessions are designed to support consultants, partners and customers during their implementation projects. The sessions cover all different aspects of SAP NetWeaver and are aimed at
thus provide knowledge which is not available via standard training courses. The session duration is typically 60min and includes questions and answers.
Tuesday, August 18, 2009:
How to implement secure scenarios with SAP NetWeaver Process Integration 7.1
Time: 2.00 - 3.00 p.m. Singapore Time (UTC +8)
This event will feature Makoto Sugishita with the SAP Intelligence Platform & NetWeaver Regional Implementation Group.
Makoto provides the following abstract:
In this session you will learn more about the core security concepts that are provided with the service-oriented architecture (SOA)
management capabilities in SAP NetWeaver Process Integration (SAP NetWeaver PI). This session will cover main use cases and
supported scenarios of secure SAP NetWeaver PI deployments.
SAP Connect Link: https://sap.emea.pgiconnect.com/I016095
(no passcode needed)
Dial in:
For dial in details please register here http://www.surveymonkey.com/s.aspx?sm=EFeuZl9PxrwKOW5i5W556g_3d_3d
Kind regards,
Sarma Sishta
SAP Intelligence Platform & NetWeaver RIG APJ

hi,
I'm making this a sticky thread till August 18 so it will have better visibility
Regards,
Michal Krawczyk

How to implement this need help

I created a datacontrol for a named query which (using Ejb entity beans) which accepted a employee id and click on find show me the respected employee details in a table.
case 1: In one single page
when i added the form consisting of a single text box , button and the table to show the result of the find method in one single page it worked out perfectly,,,
case 2 : using 2 different pages
But then i tried adding only the form in one page named page1 and and the table to show the result in another page i.e page2 , Also in the command action of find button of page1 i asked it to redirect to page 2 and show result . But it never showed me any results..
Question :
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Hi Timo,
Thanks for response!
But as i read from the following url: http://docs.oracle.com/cd/E15051_01/apirefs.1111/e10653/oracle/jbo/ViewObject.html, the setQueryTimeOut(int timeOutMills), the timeOut is mentioned in milliseconds. Please correct me if I am wrong.
and i have overriden the executeQuery() method in the View Object Impl class as shown below:
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sessionScope.put("MyQuery", this);
try {
super.executeQuery();
} finally {
sessionScope.remove("MyQuery");
throw new JboException("Query Taking too long to respond");
and in the JAVA class i am calling the above method like this:
monitor.setQueryTimeOut(6);
monitor.executeQuery();
But the issue is:
1. The above exception message is getting carried forward to other pages as well. I mean somewhere in the session/ADFContext this message is being saved and error comes up/pops up when i click on other tabs of the page. How do i clear this?
2. The above exception message is coming for the first time but when i click the 'Submit' button second time, i am getting the results and also the message that 'Query is taking too long to respond'. This should not be the case, everytime it should show the same message as the timeout limit is less and the query should end without fetching the results.
Kindly let me know how to resolve the above issues, any pointers will be helpful.
Thanks in advance.
Edited by: user9223904 on Nov 3, 2012 4:42 AM

How to implement Self Registration in EP 7.0

Hello All,
I am working in Enterprise Portal 7.0.
I wanted to customize self registraion page in my portal in SAP Netweaver 7.0.
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Thankx.

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How to implement autocomplete?

Hello,
I have a String array with strings in non-alphabethical order.
I would like to implement autocomplete (just like in IE address line) on a JTextField.
I guess I'll need to put some listener on textfield, but which? And how to handle array - sort it before use? Any other possibilities?

Well, first you'd need something to compare the String being typed in to, so that you know what the user might be trying to type. Then, I guess you'd need a KeyListener on text field, so each time a key is pressed, you run a search and return all the possible Strings that could match it.
I'd be a little lost as to how to implement the drop-down list like IE (or Windows in general) has to handle auto-complete. The other way to handle it would be to have the word fill itself into the textbox as you type, leaving the guessed part highlighted so you can continue to type, and continue to get suggestions. This approach seems a bit easier, and could be handled fairly easily.

How to implement a

I have an application which uses the Comm API to communicate to a device
through the serial port. It is now necessary that I get acknowledgements
back from the device between messages. That is, I send a packet, and
cannot send another packet until that one is acknowledged. So, I need to
create a queue of packets to send, and after each is sent, I need to listen for
incoming packets to determine if I got an acknowledgement, after which I
can send the next one.
Other unrelated packets might come in, so I cannot "busy wait".
It seems like the best choice is to have a queue that is on its own thread, so
that whenever a packet comes in both the main thread and the queue
thread can decide how to react to it. I have some ideas about how to
implement this, but they are probably not "clean".
Is there a class that does something like this? I was going to create a class
which implements Runnable, and listens to the class which deals with the
serial port, and have the run method send a packet, and wait until a flag
was set that verifies that the acknowledgement packet was recieved, and
then it would send the next one. But I am a bit confused about what
happens when the queue gets empty and the run method stops.
So then I thought the queue would belong to a different class which would
create a new thread if the queue is empty, and keep adding to it as long as
it is empty. That is, if the queue is empty, create a new thread and start it.
If the queue is not empty, just add the new object to the currently running thread.
Does any of this make sense? Ideas?
Thanks,
Chuck.

I'm not at all sure what the "future result" pattern is, and a google search
didn't help much.
Wouldnt you check for a message before trying to send
something?
Vector queue;
if(queue.size() > 0 ) {
// transmit
I think you are missing something here--If the queue is empty, what happens? What is listening for new requests to send? What is waiting
for acknowledgments?
However, I think I can solve the problem without threads simply by having the queue listen for incoming packets, and if an acknowledgement is received, then the next packet is sent. Otherwise, it resends the original. The only downside I see to this is that if packets are never received, they are never sent. But if that is the case, there are bigger problems to deal with, so I think it may be acceptable.

How to implement session listener in RM

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