How to list the employees working under one manager in the same row.

Hi,
my emp table has the following data.
EMPNO ENAME JOB MGR HIREDATE SAL COMM DEPTNO
7369 SMITH CLERK 7902 17-DEC-80 800 20
7499 ALLEN SALESMAN 7698 20-FEB-81 1600 300 30
7521 WARD SALESMAN 7698 22-FEB-81 1250 500 30
7566 JONES MANAGER 7839 02-APR-81 2975 20
7654 MARTIN SALESMAN 7698 28-SEP-81 1250 1400 30
7698 BLAKE MANAGER 7839 01-MAY-81 2850 30
7782 CLARK MANAGER 7839 09-JUN-81 2450 10
7788 SCOTT ANALYST 7566 19-APR-87 3000 20
7839 KING PRESIDENT 17-NOV-81 5000 10
7844 TURNER SALESMAN 7698 08-SEP-81 1500 0 30
7876 ADAMS CLERK 7788 23-MAY-87 1100 20
7900 JAMES CLERK 7698 03-DEC-81 950 30
7902 FORD ANALYST 7566 03-DEC-81 3000 20
7934 MILLER CLERK 7782 23-JAN-82 1300 10
I want to group all the employees under one manager and list their names in the same row. IS that possible. When i tried the query below,
select mgr, count(*) employees from emp where mgr is not null group by mgr, ename;
I got the result as
MGR EMPLOYEES
7566 2
7698 6
7782 1
7788 1
7839 3
7902 1
Additionally, would I be able to display the names of the employees under one manager in a row? or atleast in some other way? Pls share your ideas.

A summary of different string aggregation techniques can be found here
http://www.oracle-base.com/articles/10g/StringAggregationTechniques.php

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