How to pop up a new browser window to point to an external site

Question

Please help. we want to popup an new browser window when click on a button and the new window is pointing to an external web site.
I can make it work to point to an external site in the same window. But that is not we want to.
I do see some old posting about this but it does not work for us.
Please anyone knows the detail of the steps and code, probably including any environment setting/configuration if required, response to this thread.
thanks a lot in advance!
ggu

Answer 1

ggu,
This is a gimmicky solution but it works and is reusable. Copy your button template and rename it POP_UP_BUTTON. Get rid of the #LINK# substitution string and replace it with:
window.open('#BUTTON_ATTRIBUTES#')Put the URL you want to go to in the attributes section of the button. Put something like "TO_<DOMAIN>" in the button request so it is not totally gibberish and irrelevant. This would be much nicer if the apex engine did not include the "apex.submit()" code inside of the #LINK# substitution string. Or if they provided a second substitution string just for the URL specified.
Here is the old code:
<button value="#LABEL#" onclick="#LINK#" class="button-default" type="button">
  <span>#LABEL#</span>
</button>here is the new code:
<button value="#LABEL#" onclick="window.open('#BUTTON_ATTRIBUTES#')" class="button-default" type="button">
  <span>#LABEL#</span>
</button>Cheers,
Tyson Jouglet
Edited by: Tyson Jouglet on Jun 17, 2011 8:50 AM