How to put OR clause in SELECT statement

Question

Hi
How to put OR clause in SELECT statement to return number_first/number_last to match records from another table's column.
<pre>
SELECT
a.id ,
flat_number ||' '|| a.number_first||' '||a.street_name||' '||a.suburb address1,
apt_no ||' '|| street_no||' '||b.street_name||' '||b.suburb address2
from
a ,
b
where b.street_name = a.street_name
AND b.SUBURB = a.SUBURB
AND b.STATE = a.STATE
</pre>
Thsi will return this as exact match.
ADDRESS 1
12 TAMAN TENANG A ORCHARD 3142     
10 RAMA YISHUN 2095
ADDRESS2
12 TAMAN TENANG A ORCHARD 3142     
10 RAMA YISHUN 2095
However this only matches number_first.
How can I get the query work that it will match both number_first and number_last (table b)in address 1 to match street_no in address2 ( table b).My oracle version is 10GR/2.

Answer 1

Hi, I have a hard time understanding your request, and below is what I thought you want:
SELECT
    a.id ,
       flat_number ||' '|| (decode(b.street_no, a.number_first, a.number_first, a.number_last, a.number_last)||' '||a.street_name||' '||a.suburb  address1,
         apt_no ||' '|| street_no||' '||b.street_name||' '||b.suburb address2
      from
             a ,
             b
            where          b.street_name = a.street_name
             AND            b.SUBURB      = a.SUBURB
            AND            b.STATE       = a.STATE
            AND  (B.street_no=a.number_first OR b.street_no=a.number_last);Not tested.
Also, since your B.street_no will be either a.number_first OR a.number_last, you could replace
(decode(b.street_no, a.number_first, a.number_first, a.number_last, a.number_last) with just b.street_no.
Edited by: PhoenixBai on Aug 26, 2010 11:33 AM