How to read all the files in one directory?

can anyone tell me ?
3x

File.listFiles() is a good start
http://java.sun.com/j2se/1.4.2/docs/api/java/io/File.html
Gil

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How to read all the files in the directory

Hi,
I want to read all the files from a directory and perform some operations on them. How to read one file at a time from the directory. Is there any operation like the * sign in Dos and Matlab. Is there any such vi which does that.
Thanks,
Nitin

I'm glad I could help, Danny. Using the VI Server technique for recursion is very slow and memory-intensive. I have never seen a need for recursion in LabVIEW that couldn't be solved with a loop and shift registers.
-D
Darren Nattinger, CLA
LabVIEW Artisan and Nugget Penman

How to remove all the files in a directory

hi all ,
am new to unix.. i need to remove all the fine in the directory .
how can i remove it.. can any one tel me the command..
i have use rm -f logs(folder name).
but it is not removing any file ..
Thanks
sreedahr

Hi;
What is your OS?Which user you are using for delete process, you have w/r permission for your delete process on files
You can use man rm and can check manuel
Did you see:
http://en.wikipedia.org/wiki/Rm_(Unix)
http://www.cyberciti.biz/faq/howto-linux-unix-delete-remove-file/
http://www.cyberciti.biz/faq/delete-remove-a-directory-unix-command/
Pelase check links
Regard
Helios

Read all the files in a folder over and over again

I want to develop an application that reads all the files in a folder, and once its done reading those files it reads all the files again.
The purpose for this application is to read all the files in a folder that are continuously being stored in that folder, so that when a new file is created, that file is also read by the application. I then need to compare the date and time in which the file was created to the actual date and time of the system, so that way I can get the most recent file, and then I will do other operations with this file.
The thing is that I know how to read all the files in a directory, but I don't know how to cycle through those files again, in order to look for the most recent one, and I don't know how to make the comparison of the time stamps, because I need a precision of one second in the system time and the time the file was created.
Can someone please help me?
Thanks in advance!
Solved!
Go to Solution.

I think that I just went the wrong direction.
What I wanted to do in the first place, was to rename and overwrite every new file in a directory with the same name and file extension, so that every new file overwrites the old file. The thing is that the list folder only lists the files the first time and then keeps on telling me there are no files to be read even though there are new files.
What I need now is a way to overwrite the old files with the same name, and keep searching for every new file that is going to be stored in the directory.
I will leave the code that I have right now, so that you can tell me what do I need to modify in order to read every new file that's going to be created in that directory.
Thanks in advance for your help!
Attachments:
Overwrite Files.vi ‏12 KB

How can i open the directory/folder and read all the files inside it in order and then close it?

How can i open the directory/folder and read all the files inside it in order and then close it? any example would be nice.
thanks

In the File I/O>>Advanced File Functions Palette is a function named "List directory". This function will give you two arrays. One contains the names of all subdirectories the other the names of all files. If you want to sort them by name use the array sort function. If you want to sort them by another attribute use the File/Directory Info function to get more data. Use a cluster which contains the attribut to sort and the original index of the name. Then sort this array.
Waldemar
Waldemar
Using 7.1.1, 8.5.1, 8.6.1, 2009 on XP and RT
Don't forget to give Kudos to good answers and/or questions

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How to get all the values in one column of a JTable as a Collection of String.
I don;t want to write a for loop to say getValueAt(row, 1) eg for 2nd column.

I don;t want to write a for loop to say getValueAt(row, 1) eg for 2nd column. You could always write a custom TableModel that stores the data in the format you want it. It would probably be about 50 lines of code. Or you could write a loop in 3 lines of code. I'll let you decide which approach you want to take.

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I want to read all the files present in a folder on Application Server ( AL11 ). My problem is that I do not know the name of the file but I know the folder path where files are present.
I need to go to this folder and pick up all the files present in this folder and then process these files in my program.
Can any one help me in this!
Regards,
Lalit

You can use a call to
C_DIR_READ_START'
and
CALL 'C_DIR_READ_NEXT'
Regards,
John.

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Hi,
I have more than 1000 views in one shcema.
How to export all the views in one schema?
Amy

Hi,
It's not a very easy question, I have develop a script wich create a script to create view from old database to new database :
/* &1: Oracle SID Source
/* &2: Oracle Schema Source
SET HEAD OFF
SET VERIFY OFF
SET PAGESIZE 0
SET LONG 40000000
SET LONGCHUNKSIZE 2000
SET LINESIZE 2000
SET FEEDBACK OFF
CREATE TABLE RECREATE_VIEW(VIEW_NAME VARCHAR2(30), TEXT LONG);
/* Selection du texte de la vue */
DECLARE
w_text long;
w_text_debut long;
w_text_column long;
w_view varchar2 (30);
w_schema varchar2 (8):='&2';
CURSOR w_cursor IS
SELECT a.view_name, a.text
FROM dba_views a
WHERE a.owner = w_schema;
CURSOR w_column IS
SELECT DECODE (ROWNUM,
1, 'CREATE OR REPLACE FORCE VIEW ' || '&' || '1..'
|| a.table_name || chr(10)
|| '('
|| a.column_name
|| DECODE (ROWNUM, nbcolumns, ')' || chr(10) || 'AS' || chr(10), ',' || chr(10))
FROM (select column_name,table_name
FROM dba_tab_columns
WHERE owner = '&1'
AND table_name = w_view
order by column_id ) a,
(SELECT COUNT (1) nbcolumns
FROM dba_tab_columns
WHERE owner = '&1'
AND table_name = w_view
GROUP BY owner, table_name) b
order by rownum;
BEGIN
OPEN w_cursor;
LOOP
FETCH w_cursor INTO w_view, w_text;
EXIT WHEN w_cursor%NOTFOUND;
w_text_debut := NULL;
w_text_column := NULL;
OPEN w_column;
LOOP
FETCH w_column INTO w_text_column;
EXIT WHEN w_column%NOTFOUND;
w_text_debut := w_text_debut || w_text_column || ' ';
w_text_column := NULL;
END LOOP;
CLOSE w_column;
w_text := w_text_debut||w_text||';';
insert into RECREATE_VIEW(VIEW_NAME, TEXT) VALUES (w_view, w_text);
COMMIT;
w_text := NULL;
w_view := NULL;
END LOOP;
CLOSE w_cursor;
END;
SPOOL scripts_views_&1..sql
PROMPT SPOOL scripts_views_&1..log
PROMPT
SELECT TEXT
FROM RECREATE_VIEW;
PROMPT
PROMPT SPOOL OFF
PROMPT
SPOOL off
PROMPT /* Formattage du fichier SQL */
!sed 's/[ ]*$//' scripts_views_&1..sql > aprilia.tmp
!rm scripts_views_&1..sql
!mv aprilia.tmp scripts_views_&1..sql
DROP TABLE RECREATE_VIEW;
EXIT
I hope that help you.
Nicolas.

Function Module To read all the Files in a Given UNIX directory.

Can anyone provide me with a FUNCTION MODULE which reads all the files available in a UNIX directory?
I have the UNIX directory given. I need to find all the files available in that particular Directory so that I can choose and process accordingly. Probably I can store all files in an Internal Table.
Thanks in advance.
Sunil

Hi Nick,
Thankyou very much for the response.
The Function Module /SAPDMC/LSM_F4_SERVER_FILE is interactive wherein we can select only one file.
But my requirement is I need to collect (probably in an internal table) all the files exixting in the given UNIX directory.
Can you please find in that direction. I would be very grateful.
Thanks.
Sunil

MAC OSX 10.3.6 having Boot Problems(Gray Screen with Spinning wheel all the Time) ,How to restore all the files without Mac Startpup Disc,still is not possible i want to download full CD from Apple Site, Is It Possible to Download!

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MAC OSX 10.3.6 having Boot Problem(Gray Screen with Spinning wheel all the Time) ,How to restore all the files without Mac Startpup Disc,still is not possible i want to download full CD from Apple Site, Is It Possible to Download!, Windows 7 is working perfectly , can i restore any files in MAC OSX 10.3.6 through Windows 7, or i need the MAC OSX 10.3.6 Bootable Files i need to enter the MAC OSX....

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Is possible search all the files in one folder and get list all with the same extension.??

Hi,
I would like to get, if it is possible, do searching in one determinate folder and get all the files with the same extension, For example, Give the *.pou and get all the files on one list of the files in this folder and sub-folders...
If it is possible i would like to see any example.
Thanks a lot, Fonsi.

Hi Dennis,
I got your advise, I download the openG (i had problems, and downloading directly and install one to one).
Ok, i got but i have one problem, which i can't solve. I entry the promt to search and put the directory to save, later i push 'Do it' and it search the files, show the paths and number, then save in the folder and finally show the window , all ok!.
The problem is with the target path, when i want use the browse, it doesnt run properly. I want select one carpet, and it demands one file, i dont understand why??, i changed the options browse but it didnt work. Also i would like when i put one path if folder doesnt exist, directly create it and save the files, if exist copy it.
Thanks for all!. I attached the file in lv 7.1
Attachments:
buscar3.vi ‏50 KB
capture.GIF ‏48 KB

Moving the files from one directory to another.

It seems that this would be simple but I am not able to do it easily. I just want to move files from one directory to another directory. I tried the file class renameTo as in the following...
File fFrom = new File("C:\\uhin\\batch\\outgoing");
File fTo = new File("C:\\uhin\\batch\\outgoing\\back");
fFrom.renameTo(fTo);
but this doesn't seem to work. I have tried deleting the directory and then recreating it but this doesn't seem to work as in.
fTo.delete();
fTo.mkdir();
any ideas ?
thanks
kris.

That code you have there tries to rename the directory from C:\uhin\batch\outgoing to C:\uhin\batch\outgoing\back. I'm not sure if you can rename directories in general, but even if you can that particular renaming wouldn't work.
However you didn't want to rename the directory in any case. You need to use a File method called listFiles (if I recall correctly... check the API documentation) which returns an array of File objects, representing all the files in that directory. Then loop through that array, and for each File in it, (1) create a new File object with the new name, and (2) call renameTo() to rename the file.

Upload all the files in a directory

Hi,
I have searched in forum for a solution to my problem (Upload all the files contained in a certain directory) but all I've found is solutions to upload a single file using the bean JspSmartUpload. I had myself used this bean to uploads files to an server, but files choosed by the user with the <input type="file">. What I'm wanting know is different and I can't find a solution to it. I've tried to change the jspsmartupload to do this but I'm having no success..
Anyone can help?
Thanks in advance,
Nuno.

I don't believe there's any support in pure html forms to accomplish this.
The File class has a listFiles() method, that will return an array of all the files in a directory. As this code must run on the client machine, you will need to write an applet to accomplish this. You will also have to worry about the security sandbox, and sign your applet.
To get each file to the server you will need to create a URL object, openConnection on it, set up a multipart form POST to it, and transfer the files, one by one.

Selecting all the files in a directory

How would i select all the files in a directory, write the info of the files into a new file, and after the end of each file, make a New Line?

hi zymus,
check this code u will get the solution for ur problem..
import java.io.*;
public class files {
public static void main(String[] args) {
File f = new File("c://");// specify ur directory name here
String[] n = f.list();
System.out.println("ALL FILES.....");
               if (n != null)
                         System.out.println("length = " + n.length);
for (int i = 0; i < n.length; i++) { System.out.println("i = " + n[i]); }
                              String[] n2 = f.list(new myJavaFileFilter());
                              System.out.println("ALL JAVA FILES.....");
                              if (n2 != null)
                                   System.out.println("length = " + n2.length);
for (int i = 0; i < n2.length; i++)
     System.out.println("the files are::::::::: " + n2);
class myJavaFileFilter implements FilenameFilter
public boolean accept(File dir, String name)
     if (name.indexOf(".pdf") > 0)// give the file extension what u want
     return true;
return false;

How to read in a file as one whole String

Hi..im trying to read in a file, that has white spaces, indenting and all..an i wana read in all that as one string. i cant use realine has it reads in line by line...someone told me i should use fileinputstream but i dont knw how that's done. thanks

yea but i dont want to do that coz i have the reading in file in my main class. and a separte function that looks for two specific words in that whole string and spits out the content between them. with readline its only line by line.. my main looks like this:
public static void main(String args[])
try
FileInputStream fstream = new FileInputStream("c:/Program Files/searchResult.xml");
String line;
line = fstream.toString();
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catch (Exception e)
                    System.err.println("error");
So right now all this does is reads in the file..but the output it gives me is :
java.io.FileInputStream@108786b
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How to read all the files in one directory?

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