How to read specific line in a file through UNIX shell script..

Dear Friends,
I have generated .ldt file under admin/import/US folder through FND_LOAD script for Download the responsibility.
I registred Shell script (Host concurrent program) in Oracle apps. Now i want to read the file in speciific line which i was generated in admin/import/US folder through unix shell script. Please help me how to read specific line and the i want to replace that which i am going to read the specific line.
Thanks in advance..
Regards,
Velu.

Hi,
Thanks for reply,
My requirement i have to find the specific line in a file and find and replace needed word over there it's should happen programatically. i want to read specific line in a file Once complete find and replace the condition should exists. The loop will go to next file and read the same line in next file also do the same process upto how many files over there.i am doing through UNIX shell script. Please help me out to find the
Your suggestion is highly appriciated.
Thanks,
Velu.

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HOW to read CLOB and create XML file on UNIX/LINUX

Hi,
Could you please let me know, how to read CLOB using ADODB. I have column CLOB type on Oracle 9.2, with content of whole XML type. I am unable to retreive more than 4k. I use adLongVarChar. So I have written Oracle stored procedure to read the clob and create XML file using DBMS_LOB package and UTL_FILE package, still no joy.
Please help.
example of my XML file is:
<EXAMPLE><HEADER><VERSION>1.0</VERSION><TEMPLATE>XXXX</TEMPLATE><TAG1>CON</TAG1></HEADER><BODY><TAG2>X1</TAG2><OFFICE>assad</OFFICE><CREATE_DATE>27/02/2006 10:55</CREATE_DATE><SOURCE></SOURCE></BODY><FIXEDTABLE1><TABLEROW1COL1>asdadddddddddddddddddddddddddddddddddddddddddddddddddd asdadddddddddddddddddddddddddddddddddddddddddddddddddd asdadddddddddddddddddddddddddddddddddddddddddddddddddd asdadddddddddddddddddddddddddddddddddddddddddddddddddd asdadddddddddddddddddddddddddddddddddddddddddddddddddd asdadddddddddddddddddddddddddddddddddddddddddddddddddd asdadddddddddddddddddddddddddddddddddddddddddddddddddd asdadddddddddddddddddddddddddddddddddddddddddddddddddd asdadddddddddddddddddddddddddddddddddddddddddddddddddd asdadddddddddddddddddddddddddddddddddddddddddddddddddd asdadddddddddddddddddddddddddddddddddddddddddddddddddd asdadddddddddddddddddddddddddddddddddddddddddddddddddd asdadddddddddddddddddddddddddddddddddddddddddddddddddd asdadddddddddddddddddddddddddddddddddddddddddddddddddd 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asdadddddddddddddddddddddddddddddddddddddddddddddddddd</TABLEROW4COL1><TABLEROW4COL2></TABLEROW4COL2><TABLEROW5COL1></TABLEROW5COL1><TABLEROW5COL2></TABLEROW5COL2></FIXEDTABLE1><CHECKBOX><CHECKBOX1>False</CHECKBOX1><CHECKBOX2>False</CHECKBOX2><CHECKBOX3>False</CHECKBOX3><CHECKBOX4>False</CHECKBOX4><CHECKBOX5>False</CHECKBOX5><CHECKBOX6>False</CHECKBOX6><CHECKBOX7>False</CHECKBOX7><CHECKBOX8>False</CHECKBOX8><CHECKBOX9>False</CHECKBOX9></CHECKBOX></EXAMPLE>
My STored Procedure:
ftypFileHandle := UTL_FILE.fopen ('XML_DIR_FILE', vFileName, 'w', 32000);
lMarker := 'Selecting XML row';
println(lMarker, 2);
SELECT XML_FILE
INTO clobBuffer
FROM XML_TABLE
WHERE x=1;
lMarker := 'Get length of the clob';
iClobLength := nvl(DBMS_LOB.getlength(clobBuffer), 0);
WHILE (l_offset <= iClobLength) LOOP
DBMS_LOB.READ (
lob_loc=> clobBuffer,
amount=> l_amt,
offset=> l_offset,
buffer=> vOutputBuffer
UTL_FILE.put (ftypFileHandle, vOutputBuffer);
UTL_FILE.fflush (ftypFileHandle);
UTL_FILE.new_line (ftypFileHandle);
l_offset := l_offset + l_amt;
END LOOP;
lMarker := 'Close file';
println(lMarker, 2);
UTL_FILE.fclose (ftypFileHandle);
Thanks

Hello myself,
nobody has answered my question, so now I answer myself!!
The wrong part is to read the file with "open dataset" and to create the inputstream with
p_istream = p_streamfactory->create_istream_itable(
table = g_xml_table
size = g_xml_size ).
Better ist to create the inputstream with
p_istream = p_streamfactory->create_istream_uri(
.......................PUBLIC_ID = ''
.......................SYSTEM_ID = '
applserver\I$\TEMP\Datei.XML' ).
In this way no space is needed for the file.
Best regards,
Thomas
Message was edited by:
Thomas13 Scheuermann

How to write dbms_out traces into a file (in a shell script)?

I'm afraid this is a shell scripting question:
I have the following lines in a script:
ls $salida/EXAR* | while read FILE
do
sqlplus -s user@isntance/password << EOF
set serveroutput on size 1000000
set feedback off
--set trimspool on
var p_out_result_nv number
var p_out_DescError_SV varchar2(4000)
var p_out_Traza_SV varchar2(4000)
var p_Fich_Entrada varchar2(4000)
--spool $mi_fich_log
begin
:p_Fich_Entrada := replace(('$FILE'),('$salida/'),'');
dbms_output.put_line('Tratando archivo: '||:p_Fich_Entrada);
:p_out_result_nv := 0;
SJPAMIOB.SJPRPRIN('01',:p_Fich_Entrada,:p_Fich_Entrada,'EXSJ_ENTRADA','EXSJ_SALIDA',
:p_out_result_nv,:p_out_DescError_SV,:p_out_Traza_SV);
end;
--spool off
exit :p_out_result_nv
EOF
How can I write all dbms_output.put_line in a file?
Thanks in advance.

you can use the package utl_file.
for this you either
- need a directory object in the database which points to the folder where your file is located you want to write to:
CREATE DIRECTORY lutz_dir AS ´/home/oracle/UTL_FILE_DIR´;
You will need create any directory privilege for this.
or
- you must have the init.ora parameter UTL_FILE_DIR set to the location.
Regards,
Lutz

How to read specific lines from a text file using external table or any other method?

Hi,
I have a text file with delimited data, I have to pick only odd number rows and load into a table...
Ex:
row1: 1,2,2,3,3,34,4,4,4,5,5,5,,,5 ( have to load only this row)
row2:   8,9,878,78,657,575,7,5,,,7,7
Hope this is enough..
I am using Oracle 11.2.0 version...
Thanks

There are various ways to do this. I would be inclined to use SQL*Loader. That way you can load it from the client or the server and you can use a SQL*Loader sequence to preserve the row order in the text file. I would load the whole row as a varray into a staging table, then use the TABLE and MOD functions to load the individual numbers from only the odd rows. Please see the demonstration below.
SCOTT@orcl12c> HOST TYPE text_file.csv
1,2,2,3,3,34,4,4,4,5,5,5,,,5
8,9,878,78,657,575,7,5,,,7,7
101,201
102,202
SCOTT@orcl12c> HOST TYPE test.ctl
LOAD DATA
INFILE text_file.csv
INTO TABLE staging
FIELDS TERMINATED BY ','
TRAILING NULLCOLS
(whole_row VARRAY TERMINATED BY '/n' (x INTEGER EXTERNAL),
rn SEQUENCE)
SCOTT@orcl12c> CREATE TABLE staging
2    (rn         NUMBER,
3     whole_row SYS.OdciNumberList)
4 /
Table created.
SCOTT@orcl12c> HOST SQLLDR scott/tiger CONTROL=test.ctl LOG=test.log
SQL*Loader: Release 12.1.0.1.0 - Production on Tue Aug 27 13:48:37 2013
Copyright (c) 1982, 2013, Oracle and/or its affiliates. All rights reserved.
Path used:      Conventional
Commit point reached - logical record count 4
Table STAGING:
4 Rows successfully loaded.
Check the log file:
test.log
for more information about the load.
SCOTT@orcl12c> CREATE TABLE a_table
2    (rn       NUMBER,
3     data NUMBER)
4 /
Table created.
SCOTT@orcl12c> INSERT INTO a_table (rn, data)
2 SELECT s.rn,
3         t.COLUMN_VALUE data
4 FROM   staging s,
5         TABLE (s.whole_row) t
6 WHERE MOD (rn, 2) != 0
7 /
17 rows created.
SCOTT@orcl12c> SELECT * FROM a_table
2 /
        RN       DATA
         1          1
         1          2
         1          2
         1          3
         1          3
         1         34
         1          4
         1          4
         1          4
         1          5
         1          5
         1          5
         1
         1
         1          5
         3        101
         3        201
17 rows selected.

How to read a line from a file which contains 45000 characters?

Hi all,
     Iam a receiving a .CSV file which contains n number of rows ,each row has a data seperated with delimiter.
These values based on delimiter it is seperated and certain validations are handled.
Iam using UTL_FILE.GET_LINE operator to read the value and store it in a variable which is declared as l_text VARCHAR2(30000).
when we receive a line which contains huge characters say 45000 then it throws an error(Unable to read the file).
Only on rare cases we used to receive these kind of files with huge size.
Kindly help to solve this issues.
Database details.
Oracle Database 11g Enterprise Edition Release 11.2.0.2.0 - 64bit Production
PL/SQL Release 11.2.0.2.0 - Production
CORE 11.2.0.2.0 Production
TNS for Linux: Version 11.2.0.2.0 - Production
NLSRTL Version 11.2.0.2.0 - Production
Hereby i have tried with long Raw data type but still same error unable to read the file.pls find the sample code below,
declare
l_text             LONG RAW;
l_importTypeFile   UTL_FILE.FILE_TYPE ;
begin
     PKG_COMMON.PROC_FOPEN(g_Directory, P_FILENAME,    'RB',l_importTypeFile,    p_error_cd, p_error_msg) ;
UTL_FILE.GET_RAW(l_ImportTypeFile,l_Text);
End;
Thanks in Advance
Siva

Hi Siva,
Are you trying to use data from this .csv file into your realtion tables. If yes and If you are using 11g Oracle database. I would suggest you create External Tables using the below query,
http://www.oracle.com/technetwork/issue-archive/2011/11-mar/o21nanda-312277.html
STEP1: You need a Directory where your SCHEMA has read/write access. Store the csv file in that directory.
STEP2: Create an EXTERNAL Table script. Please refer the above URL. Examples are for coma delimiter (,); replace it with your pipe (|) in the code
STEP: Once your external table is created you can simply create a relational table as below:
CREATE TABLE relation_table
AS
SELECT * FROM external_table;
Regards,
RaviR

Reading specific lines in a file

hI
i need to write a program which has a file name a.txt the contents in the file is
SELECT DISTINCT D.MENUNAME, D.MENULABEL, D.MENUSEP, D.MENUORDER FROM PSMENUDEFN D, PSAUTHITEM A, PSOPRCLS C WHERE D.INSTALLED = 1 AND D.MENUGROUP = :1** AND D.MENUNAME = A.MENUNAME AND A.AUTHORIZEDACTIONS > 0 AND A.CLASSID = C.OPRCLASS AND C.OPRID = :2** ORDER BY D.MENUORDER, D.MENUNAME
Bind-1 length=21 value=&Administer Workforce
Bind-2 length=6 value=NLWAJP
I need to read the file in such a way that in the SQL statement in the place of ":1" I need to get Bind-1 value i.e., &Administer Workforce and same with :2 I need to get Bind 2 value NLWAJP
Output must be like this
SELECT DISTINCT D.MENUNAME, D.MENULABEL, D.MENUSEP, D.MENUORDER FROM PSMENUDEFN D, PSAUTHITEM A, PSOPRCLS C WHERE D.INSTALLED = 1 AND D.MENUGROUP = &Adminster Workforce AND D.MENUNAME = A.MENUNAME AND A.AUTHORIZEDACTIONS > 0 AND A.CLASSID = C.OPRCLASS AND C.OPRID = NLWAJP ORDER BY D.MENUORDER, D.MENUNAME

thomas.behr wrote:
Read in your text file line by line, then replace \*XXX\*:Y** with the appropriate value using regular expressions.
Phani532 wrote:The above answers doesnot answer my question....
I am putting my question in refined format...Wrong. import java.io.BufferedReader;
import java.io.IOException;
import java.io.StringReader;
import java.util.List;
import java.util.ArrayList;
import java.util.Collections;
import java.util.Comparator;
import java.util.Map;
import java.util.HashMap;
import java.util.regex.Pattern;
import java.util.regex.Matcher;
public class Test {
private static final String DEFAULT_TEXT =
"SELECT DISTINCT D.MENUNAME, D.MENULABEL, D.MENUSEP, D.MENUORDER FROM PSMENUDEFN D, PSAUTHITEM A, PSOPRCLS C WHERE D.INSTALLED = 1 AND *D.MENUGROUP = *:1** AND D.MENUNAME = A.MENUNAME AND A.AUTHORIZEDACTIONS > 0 AND A.CLASSID = C.OPRCLASS AND *C.OPRID = *:2** ORDER BY D.MENUORDER, D.MENUNAME\n" +
"Bind-1 length=21 value=&Administer Workforce\n" +
"Bind-2 length=6 value=NLWAJP";
public static void main( String[] args ) {
 final List<String> lines = new ArrayList<String>();
 try {
 BufferedReader br = null;
 try {
 br = new BufferedReader(new StringReader(DEFAULT_TEXT));
 String line;
 while ((line = br.readLine()) != null) {
 lines.add(line);
 } finally {
 if (br != null) {
 br.close();
 } catch (IOException ioe) {
 lines.clear();
 ioe.printStackTrace();
 if (!lines.isEmpty()) {
 Collections.sort(lines, new Comparator<String>() {
 public int compare( final String s1, final String s2 ) {
 if (s1.startsWith("Bind-")) {
 if (s2.startsWith("Bind-")) {
 return s1.compareTo(s2);
 } else {
 return -1;
 } else {
 if (s2.startsWith("Bind-")) {
 return 1;
 } else {
 return s1.compareTo(s2);
 final Map<String, String> parameters = new HashMap<String, String>();
 for (String line : lines) {
 if (line.startsWith("Bind-")) {
 parameters.put(line.substring(5, line.indexOf(' ')), line.substring(line.indexOf("value=") + 6));
 } else if (line.startsWith("SELECT ")) {
 final Matcher matcher = Pattern.compile("\\*(.*?)\\*:([\\d]*?)\\*\\*").matcher(line);
 final StringBuilder sb = new StringBuilder();
 int last = 0;
 while (matcher.find()) {
 final int idx = matcher.start();
 if (idx > last) {
 sb.append(line.substring(last, idx));
 sb.append(matcher.group(1));
 sb.append(parameters.get(matcher.group(2)));
 last = matcher.end();
 if (last < line.length()) {
 sb.append(line.substring(last));
 System.out.println(sb.toString());
}(Lucky you, I'm feeling generous - and eager to code.)

How to read long line from text file

Hi,
I just faced problem when reading a big text file.
BufferedReader br = new BufferedReader(new FileReader("D:\\afile.txt"));
String str;
int i;
while ((str = br.readLine())!=null)
i++;
//do some work here...
...This code throws exception:
Exception in thread "main" java.lang.OutOfMemoryError: Java heap spaceSo I thought file line is very long. When I opened it in FAR it only displays no more than 4096 characters as a line.
Help me to read a text file that's line is very long?

try,
$ java -X
-Xmixed mixed mode execution (default)
-Xint interpreted mode execution only
-Xbootclasspath:<directories and zip/jar files separated by ;>
set search path for bootstrap classes and resources
-Xbootclasspath/a:<directories and zip/jar files separated by ;>
append to end of bootstrap class path
-Xbootclasspath/p:<directories and zip/jar files separated by ;>
prepend in front of bootstrap class path
-Xnoclassgc disable class garbage collection
-Xincgc enable incremental garbage collection
-Xloggc:<file> log GC status to a file with time stamps
-Xbatch disable background compilation
-Xms<size> set initial Java heap size
-Xmx<size> set maximum Java heap size
-Xss<size> set java thread stack size
-Xprof output cpu profiling data
-Xrunhprof[:help]|[:<option>=<value>, ...]
perform JVMPI heap, cpu, or monitor profiling
-Xdebug enable remote debugging
-Xfuture enable strictest checks, anticipating future default
-Xrs reduce use of OS signals by Java/VM (see documentation)
-Xcheck:jni perform additional checks for JNI functions
The -X options are non-standard and subject to change without notice.

How to Read the Timestamp of a File on Unix from Form?

If you have a file located on UNIX operating, what is the best way to read the time stamp (the date that file has been created) of that file from Oracle SQL, SQL*plus, or Developer Forms 6i/9i/10g?

Thanks Robin for the reply! Your suggestion seems to be good!
However, We found a solution now! I would like to share with you the way we did, in case anyone out there need the solution:
In SQL*Plus, we created a Java Source below:
CREATE OR REPLACE AND COMPILE JAVA SOURCE NAMED "FileDate"
AS
import java.io.File;
import java.text.SimpleDateFormat;
import java.util.Date;
public class FileDate {
public static String GetDate(String strFilePath) {
String ReturnValue = null;
if (strFilePath == null || strFilePath.length()==0)
// do nothing
else
File aFile = new File(strFilePath);
if (aFile.exists())
long lngTime = aFile.lastModified();
Date aDate = new Date(lngTime);
SimpleDateFormat fmtDate =
new SimpleDateFormat("dd-MM-yyyy HH:mm:ss");
ReturnValue = fmtDate.format(aDate);
fmtDate = null;
aDate = null;
aFile = null;
return ReturnValue;
-- Then we created a wrapper to call the Compiled Java above:
CREATE or REPLACE FUNCTION FileDate_GetDate(FilePath IN STRING)
RETURN VARCHAR2 IS
LANGUAGE JAVA
NAME 'FileDate.GetDate(java.lang.String) return int';
-- Then we created a database package:
-- Package Spec:
PACKAGE sap_dnld AS
FUNCTION get_file_date2 (s1 varchar2) RETURN VARCHAR2;
END sap_dnld;
-- Package Body:
PACKAGE BODY sap_dnld AS
FUNCTION get_file_date2( s1 VARCHAR2 )
RETURN VARCHAR2 AS LANGUAGE JAVA
NAME 'FileDate.GetDate(java.lang.String) return int';
END sap_dnld;
-- Then we tested the whole thing in SQL*Plus:
set serveroutput on;
declare
x varchar2(2000);
begin
x := sap_dnld.get_file_date2;
dbms_output.put_line(x);
end;
-- Then we called the function from the package using a procedure from the form:
PROCEDURE Find_date IS
BEGIN
:control.file_date := sap_dnld.get_file_date2('directory1/subdirectory/filename.txt');
END;

How can i call a Stored Procedure procedure from Unix shell script

Hi All,
I want to call a Strored PL-SQL Procedure through Unix shell script.
Can any body help me with this.
Regards,
Saurabh

I prefer a seperate script like the other poster mentioned. However, most shells can use a 'here' document as well ...
sqlplus uid/pwd <<END
exec myproc
exit
ENDRichard

Read specific line

Dear All,
I have a one input file following way:
PATH: Top/Science/Earth Sciences/Atmospheric Chemistry
RAW: Atmospheric Chemistry
WSDA: Atmospheric() chemistry(70995,WordNet_2.1:n#06005460)
PATH: Top/Science/Earth Sciences/Atmospheric Chemistry/Publication
RAW: publication
WSDA: publication(41740,WordNet_2.1:n#01087739)
PATH: Top/Science/Earth Sciences/Atmospheric Chemistry/Modeling
RAW: Modeling
WSDA: Modeling(42261,WordNet_2.1:n#00885978)
I want to read a specific line RAW and store each line in the array list. Could you please give me some suggestions. How to read specific line . I know how to read file and line but I do not know the specific line. .
Thanks a lots .
morshed

what I wrote you before , It was my file structure of text file.
My problem is how can I store the token from perticular line .
suppose my perticular line is RAW
i want to store the token following:
ArrayList ar =new ArrayList()
ar.add(Atmospheric Chemistry)
ar.add(publication)
ar.add(modelling)
But I am facing problem to read a specific line like RAW: Atomospheric Chemistry .
I want to ignore line PATH and WASD etc. if you know it please let me know.
thanks ..
morshed

Reading Multiple lines in a file Using File Adapter

Hi All,
Iam new to this technology.How to read multiple lines in a file using file adapter.Brief me with the methodology.

I didn't look at anything else but if you want to write more than one line ever to your file you should change this
out = new FileOutputStream("Calculation.log");to this...
out = new FileOutputStream("Calculation.log",true);A quick look at the API reveals the follow constructor FileOutputStream(File file, boolean append) append means should I add on the end of the file or over-write what is there.
By default you over-write. So in our case we say true instead which says add on to what is there.
At the end of that little snippet you shoudl be closing that stream as well.
So where you have
p.close();You should have
p.close();
out.close();

Having trouble reading specific lines from a text file and displaying them in a listbox

I am trying to read specific lines from all of the text files in a folder that are reports. When I run the application I get the information from the first text file and then it returns this error: "A first chance exception of type 'System.ArgumentOutOfRangeException'
occurred in mscorlib.dll"
Below is the code from that form.
Option Strict On
Option Infer Off
Option Explicit On
Public Class frmInventoryReport
Public Function ReadLine(ByVal lineNumber As Integer, ByVal lines As List(Of String)) As String
Dim intTemp As Integer
intTemp = lineNumber
Return lines(lineNumber - 1)
lineNumber = intTemp
End Function
Public Function FileMatches(ByVal folderPath As String, ByVal filePattern As String, ByVal phrase As String) As Boolean
For Each fileName As String In IO.Directory.GetFiles(folderPath, filePattern)
If fileName.ToLower().Contains(phrase.ToLower()) Then
Return True
End If
Next
Return False
End Function
Private Sub frmInventoryReport_Load(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles MyBase.Load
Dim intcase As Integer = 1
Dim strTemp, strlist, strFile As String
Dim blnCheck As Boolean = True
strFile = "Report Q" & intcase.ToString & ".txt"
Do While blnCheck = True
strFile = "Report Q" & intcase.ToString & ".txt"
Dim objReader As New System.IO.StreamReader("E:\Furry Friends Animal Shelter Solution\Furry Friends Animal Shelter\" & strFile)
Dim allLines As List(Of String) = New List(Of String)
Do While objReader.Peek <> -1
allLines.Add(objReader.ReadLine())
Loop
objReader.Close()
strlist = ReadLine(1, allLines) & "" & ReadLine(23, allLines)
lstInventory.Items.Add(strlist)
intcase += 1
strTemp = intcase.ToString
strFile = "Report Q" & intcase.ToString & ".txt"
blnCheck = FileMatches("E:\Furry Friends Animal Shelter Solution\Furry Friends Animal Shelter\", "*.txt", intcase.ToString)
Loop
End Sub
Private Sub Button1_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Button1.Click
Dim intcase As Integer = 1
Dim strTemp, strlist, strFile As String
Dim blnCheck As Boolean = True
strFile = "Report Q" & intcase.ToString & ".txt"
Do While blnCheck = True
strFile = "Report Q" & intcase.ToString & ".txt"
Dim objReader As New System.IO.StreamReader("E:\Furry Friends Animal Shelter Solution\Furry Friends Animal Shelter\" & strFile)
Dim allLines As List(Of String) = New List(Of String)
Do While objReader.Peek <> -1
allLines.Add(objReader.ReadLine())
Loop
objReader.Close()
strlist = ReadLine(1, allLines) & "" & ReadLine(23, allLines)
lstInventory.Items.Add(strlist)
intcase += 1
strTemp = intcase.ToString
strFile = "Report Q" & intcase.ToString & ".txt"
blnCheck = FileMatches("E:\Furry Friends Animal Shelter Solution\Furry Friends Animal Shelter\", "*.txt", intcase.ToString)
Loop
End Sub
End Class
Sorry I'm just beginning coding and I'm still a noob. Any help is appreciated. Thank you!

Ok, so if I'm following this correctly you should be able to just loop through all of the files in that folder whose file name matches the pattern and then read the first 22 lines, recording only the first and the last.
Exactly how you store the animal data probably depends on how you are going to display it and what else you are going to do with it. Is there anything other than name and cage number that should be associated with each animal?
You might want to make a dataset with a datatable to describe the animal, or you might write a class, or you might just use something generic like a Tuple. Here's a simple class example:
Public Class Animal
Public Property Name As String
Public Property Cage As String
Public Overrides Function ToString() As String
Return String.Format("{0} - {1}", Name, Cage)
End Function
End Class
With that you can use a routine like the following to loop through all of the files and read each one:
Dim animals As New List(Of Animal)
Dim folderPath As String = "E:\Furry Friends Animal Shelter Solution\Furry Friends Animal Shelter\"
For Each filePath As String In System.IO.Directory.GetFiles(folderPath, "Report Q?.txt")
Using reader As New System.IO.StreamReader(filePath)
Dim lineIndex As Integer = 0
Dim currentAnimal As New Animal
While Not reader.EndOfStream
Dim line As String = reader.ReadLine
If lineIndex = 0 Then
currentAnimal.Name = line
ElseIf lineIndex = 22 Then
currentAnimal.Cage = line
Exit While
End If
lineIndex += 1
End While
animals.Add(currentAnimal)
End Using
Next
'do something to display the animals list
Then you might bind the animals list to a ListBox, or loop through the list and populate a ListView. If you decided to fill a datatable instead of making Animal instances, then you might bind the resulting table to a DataGridView.
There are lots of options depending on what you want and what all you need to do.
Reed Kimble - "When you do things right, people won't be sure you've done anything at all"

How can I input read a line from a file and output it into the screen?

How can I input read a line from a file and output it into the screen?
If I have a file contains html code and I only want the URL, for example, www24.brinkster.com how can I read that into the buffer and write the output into the screen that using Java?
Any help will be appreciate!
======START FILE default.html ========
<html>
<body>
 
<center>

Welcome to a DerekTran's Website! 
Underconstructions.... 
 </center>
 
Hello, 
 
I've been using the PWS to run the website on NT workstation 4.0. It was working
fine. 
The URL should be as below: 
http://127.0.0.1/index.htm or http://localhost/index.htm
And suddently, it stops working, it can't find the connection. I tried to figure
out what's going on, but still NO CLUES. Does anyone
know what's going on? Please see the link for more.... I believe that I setup
everything correctly and the bugs still flying in the server.... 
Thank you for your help.

PeerWebServer.doc
 
CannotFindServer.doc
 
HOSTS file is not found
 
LMHOSTS file
 
How to Setup PWS on NT
 
Issdmin doc
Please be patient while the document is download....
 If you have any ideas please drop me a
few words at [email protected] 
 
 

 
</body>
</html>
========= END OF FILE ===============

Hi!
This is a possible solution to your problem.
import java.io.*;
class AddressExtractor {
 public static void main(String args[]) throws IOException{
 //retrieve the commandline parameters
 String fileName = "default.html";
 if (args.length != 0) fileName =args[0];
 else {
 System.out.println("Usage : java AddressExtractor <htmlfile>");
 System.exit(0);
 BufferedReader in = new BufferedReader(new FileReader(new File(fileName)));
 StreamTokenizer st = new StreamTokenizer(in);
 st.lowerCaseMode(true);
 st.wordChars('/','/'); //include '/' chars as part of token
 st.wordChars(':',':'); //include ':' chars as part of token
 st.quoteChar('\"'); //set the " quote char
 int i;
 while (st.ttype != StreamTokenizer.TT_EOF) {
 i = st.nextToken();
 if (st.ttype == StreamTokenizer.TT_WORD) {
 if (st.sval.equals("href")) {
 i = st.nextToken(); //the next token (assumed) is the '=' sign
 i = st.nextToken(); //then after it is the href value.
 getURL(st.sval); //retrieve address
 in.close();
 static void getURL(String s) {
 //Check string if it has http:// and truncate if it does
 if (s.indexOf("http://") > -1) {
 s = s.substring(s.indexOf("http://") + 7, s.length());
 //check if not mailto: do not print otherwise
 if (s.indexOf("mailto:") != -1) return;
 //printout anything after http:// and the next '/'
 //if no '/' then print all
 if (s.indexOf('/') > -1) {
 System.out.println(s.substring(0, s.indexOf('/')));
 } else System.out.println(s);
}Hope this helps. I used static methods instead of encapsulating everyting into a class.

How to read random lines?

Hi everyone,
I am trying to write a program that will take a random lines from a number text files and copy them to a new document.
Is there a way to read specific lines in a document?
For example if I set an int array to hold 20 random numbers, (23, 504, 498, etc...)
can i then jump to each of these lines in the document and output the data on each line??
I have tried the RandomAccessFile seek method but that only moves a certain number of bytes(not lines).
I have also tried:
String tempLine = null;
// where numLines is the total number of lines in the document
// where randInput is my RandomAccessFile
For (int i = 0; i < numLines; i++)
tempLine = (randInput.readLine())
for(int k = 0; k < 20; k++)
if(i == randNums[k])
out.println(tempLine);
but this method is too slow, as some of my input files are over 500,000 lines in length.
Can anyone please suggest a faster more efficient method??
Many Thanks

If that is really the requirement then I suggest you
pre-process the file into some other form so it is
easier to fulfil the requirement.
For example you could copy the lines into a database
table, then choose random records from the table. Or
you could copy the lines into a new file where all
the lines had the same length (pad with blanks or
nulls or whatever you need to get back the original
line), which would make it possible to seek to line N.How about cache first the file, by reading the each line in the file and store that line in an array?
ie.
package com.yahoo.ronilloang.idunoifthisright;
import java.io.BufferedReader;
import java.io.BufferedWriter;
import java.io.File;
import java.io.FileOutputStream;
import java.io.FileReader;
import java.io.IOException;
import java.io.OutputStreamWriter;
import java.text.SimpleDateFormat;
import java.util.Date;
import java.util.Locale;
import java.util.Vector;
* How about caching first then randomly read? This maybe slow or definitely slow in performance.
* @author Ronillo Ang
public class CacheFirstThenRandomlyPick{
 private String[] lines;
 private int lineCount;
 public CacheFirstThenRandomlyPick(String fileName) throws IOException{
 File file = new File(fileName);
 if(file.exists()){
 BufferedReader bufferedReader = new BufferedReader(new FileReader(file));
 String line = bufferedReader.readLine();
 while(line != null){
 addLine(line);
 line = bufferedReader.readLine();
 trim();
 randomlyPickAndWrite();
 bufferedReader.close();
 private void addLine(String line){
 if(lines == null)
 lines = new String[10];
 checkAndExpandCapacityAsNeeded(lineCount + 1);
 lines[lineCount++] = line;
 private void checkAndExpandCapacityAsNeeded(int minCapacity){
 int oldCapacity = lines.length;
 if(minCapacity > oldCapacity){
 int newCapacity = oldCapacity * 2;
 while(minCapacity >= newCapacity)
 newCapacity += 10;
 String[] oldLines = lines;
 lines = new String[newCapacity];
 System.arraycopy(oldLines, 0, lines, 0, lineCount);
 private void trim(){
 if(lineCount > 0 && lineCount < lines.length){
 String[] oldLines = lines;
 lines = new String[lineCount];
 System.arraycopy(oldLines, 0, lines, 0, lineCount);
 private void randomlyPickAndWrite() throws IOException{
 Vector drawnNumber = new Vector();
 BufferedWriter bufferedWriter = new BufferedWriter(new OutputStreamWriter(new FileOutputStream(new File("out.txt")), "8859_1"));
 for(int index = 0; index < lineCount; ++index){
 int whatLineToRead = (int)(Math.random() * lineCount);
 while(drawnNumber.contains(String.valueOf(whatLineToRead)))
 whatLineToRead = (int)(Math.random() * lineCount);
 drawnNumber.addElement(String.valueOf(whatLineToRead));
 bufferedWriter.write(lines[whatLineToRead]);
 bufferedWriter.newLine();
 bufferedWriter.flush();
 bufferedWriter.close();
 public static void main(String[] args) throws IOException{
 if(args.length == 1){
 SimpleDateFormat sdf = new SimpleDateFormat("hh:mm:ss", Locale.getDefault());
 System.out.println("Program start at " + sdf.format(new Date()));
 new CacheFirstThenRandomlyPick(args[0]);
 System.out.println("Program ended at " + sdf.format(new Date()));
 else
 System.out.println("Usage: java com.yahoo.ronilloang.idunoifthisright.CacheFirstThenRandomlyPick <text file>");
 System.out.println("\ndone.");
}What do you think? Definitely wrong? Okay. This just what I think. Never mind.
Thank you. -Ronillo

How to read MG1, MGU, SG1, SGU files?

I have copies of Band in a Box and Aebersold music software, from an older PC.
How to read MG1, MGU, SG1, SGU files on my MacBook Air?
Many thanks, Antoine

I believe in Linux/Unix, everything is treated as a file descriptor, be it a disk, socket, hardware device or an actual file. Since Java will simply call the appropriate method (length() for example) on the descriptor, I would imagine it would be up to the operating system to determine what to return. If I ask for the length() of a socket, I'm not sure what it would return. The bytes not flushed in the buffer? Total transmitted? Some random uid? I'm sure it is defined somewhere but the behavior may not be what you expect. See if you can use a 'vanilla' command-line method to get the file length from that device. If it too returns zero, you know it's not your program.
- Saish

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