How to remove first line of outgoing messages: ?xml version="1.0"........

On outgoing messages, when I look in MONI, I see properly formatted XML message.
The first line of all my outgoing files has this line:
<?xml version="1.0" encoding="UTF-8" ?>
Is there a way to suppress this?
If so, is there a way to suppress for only certain partners within one interface?
Thanks,
Jeff

Hi Jeff,
As others pointed without this line the document will not be a valid document. Can you tell your complete requirment. One of these kind of requirement is discussed in this thread, you can see whether its the same in your case or not. If not then tell your complete req. so that somebody can help you out here.
Remove first line in the XML Document
Regards,
---Satish

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<pre>
Hi
<b>i have xml document, which is shown below
after removing some nodes from the document ,i am getting empty lines in place of removed nodes,how to resolve this and get the proper xml document without any errors</b>
<?xml version="1.0" encoding="UTF-8" standalone="no"?>
<!DOCTYPE Message SYSTEM "TRD01.dtd">
<Message>
<Header>
<CounterPartyType>CLIENT</CounterPartyType>
<CreationTime>20134455</CreationTime>
<ErrorCode>363 </ErrorCode>
<ErrorEnterPriseId>N</ErrorEnterPriseId>
<ErrorStatus>1</ErrorStatus>
<ErrorSystemId>STL</ErrorSystemId>
<ErrorTimes>31</ErrorTimes>
<MessageType>T</MessageType>
<RecipientEnterpriseId>N</RecipientEnterpriseId>
<RecipentSystemId>EXM</RecipentSystemId>
<Remarks>REMARSK</Remarks>
<SenderEnterpriseId>N</SenderEnterpriseId>
<SenderSystemId>TR</SenderSystemId>
</Header>
</Message>
<ErrorCode>363 </ErrorCode>
<ErrorEnterPriseId>NIHK</ErrorEnterPriseId>
<ErrorStatus>1</ErrorStatus>
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Object result5 = expression5.evaluate(doc, XPathConstants.NODE);
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node5.getParentNode().removeChild(node5);
XPathExpression expression6 = xpath.compile(xmlpath6);
Object result6 = expression6.evaluate(doc, XPathConstants.NODE);
Node node6=(Node) result6;
node6.getParentNode().removeChild(node6);
XPathExpression expression7 = xpath.compile(xmlpath7);
Object result7 = expression7.evaluate(doc, XPathConstants.NODE);
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the xml output i am getting is
<?xml version="1.0" encoding="UTF-8" standalone="no"?>
<Message>
<Header>
<CounterPartyType>CLIENT</CounterPartyType>
<CreationTime>20134455</CreationTime>
<MessageType>TRD01</MessageType>
<RecipientEnterpriseId>N</RecipientEnterpriseId>
<RecipentSystemId>STL</RecipentSystemId>
<Remarks>REMARSK</Remarks>
<SenderEnterpriseId>N</SenderEnterpriseId>
<SenderSystemId>T</SenderSystemId>
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</Message>
<b>could you please let me know how to avoid empty lines in the xml doucment output</b>
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public void ValidateRecord(String xml){
try{
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/*DOMParser parser = new DOMParser();
parser.setErrorStream(System.err);
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parser.showWarnings(true);*/
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XPathExpression expression1 = xpath.compile(xmlpath2);
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System.out.println("the values of the string is " +node1.getNodeValue());
// for (int i = 0; i < nodes.getLength(); i++) {
//System.out.println(nodes.item(i).getNodeValue());
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XPathExpression expression2 = xpath.compile(xmlpath1);
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Node node2 = (Node) result2;
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node2.setNodeValue(node1.getNodeValue());
System.out.println(node2);
//removing the nodes from document
String xmlpath3="/Message/Header/ErrorCode";
String xmlpath4="/Message/Header/ErrorEnterPriseId";
String xmlpath5="/Message/Header/ErrorStatus";
String xmlpath6="/Message/Header/ErrorSystemId";
String xmlpath7="/Message/Header/ErrorTimes";
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t.setOutputProperty(OutputKeys.METHOD,"xml");
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t.transform(new DOMSource(doc), new StreamResult(System.out));
catch (Exception e) {
e.printStackTrace();
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</pre>
Edited by: user12185243 on Apr 6, 2013 6:38 AM
Edited by: user12185243 on Apr 6, 2013 6:41 AM
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