How to rename column name of table?

Hello...
How to rename column name of table?
The column have data.
Thanks.
Martonio.

The following should work in 9i release 2 and above.
SQL> create table mytable(col1 varchar2(2),
  2  col2 date);
Table created.
SQL> insert into mytable values('t1',sysdate);
1 row created.
SQL> select * from mytable;
CO COL2
t1 30-NOV-04
1 row selected.
SQL> desc mytable
Name                                      Null?    Type
COL1                                               VARCHAR2(2)
COL2                                               DATE
SQL> alter table mytable rename column col2 to mydate;
Table altered.
SQL> desc mytable
Name                                      Null?    Type
COL1                                               VARCHAR2(2)
MYDATE                                             DATE
SQL> select * from mytable;
CO MYDATE
t1 30-NOV-04
1 row selected.
SQL> disconnect
Disconnected from Oracle9i Enterprise Edition Release 9.2.0.3.0 - 64bit Production
With the Partitioning option
JServer Release 9.2.0.3.0 - Productionhttp://download-west.oracle.com/docs/cd/B10501_01/server.920/a96540/wnsql.htm#972698

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    /

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    To annotate the schema and control the naming, modify the content to :
    <?xml version="1.0" encoding="UTF-8" ?>
    <xs:schema xmlns:xs="http://www.w3.org/2001/XMLSchema" xmlns:xdb="http://xmlns.oracle.com/xdb">
      <xs:element name="employee" xdb:defaultTable="EMPLOYEE_XML">
        <xs:complexType>
    Next step : create a resource, or just directly insert an XML document into the table.
    Example of creating a resource :
    declare
      res  boolean;
      doc  xmltype := xmltype(
    '<employee>
      <details>
        <emp_id>1</emp_id>
        <emp_name>SMITH</emp_name>
        <emp_age>40</emp_age>
        <emp_dept>10</emp_dept>
      </details>
    </employee>'
    begin
      res := dbms_xdb.CreateResource(
               abspath   => '/public/test.xml'
             , data      => doc
             , schemaurl => 'my_schema.xsd'
             , elem      => 'employee'
    end;
    The resource has to be schema-based so that the default storage mechanism is triggered.
    It could also be achieved if the document possesses an xsi:noNamespaceSchemaLocation attribute :
    SQL> declare
      2 
      3    res  boolean;
      4    doc  xmltype := xmltype(
      5  '<employee xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
      6             xsi:noNamespaceSchemaLocation="my_schema.xsd">
      7    <details>
      8      <emp_id>1</emp_id>
      9      <emp_name>SMITH</emp_name>
    10      <emp_age>40</emp_age>
    11      <emp_dept>10</emp_dept>
    12    </details>
    13   </employee>'
    14   );
    15 
    16  begin
    17    res := dbms_xdb.CreateResource(
    18             abspath   => '/public/test.xml'
    19           , data      => doc
    20           );
    21  end;
    22  /
    PL/SQL procedure successfully completed
    SQL> set long 5000
    SQL> select * from "employee1121_TAB";
    SYS_NC_ROWINFO$
    <employee xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:noNamespaceS
      <details>
        <emp_id>1</emp_id>
        <emp_name>SMITH</emp_name>
        <emp_age>40</emp_age>
        <emp_dept>10</emp_dept>
      </details>
    </employee>
    Then use XMLTABLE to shred the XML into relational format :
    SQL> select x.*
      2  from "employee1121_TAB" t
      3     , xmltable('/employee/details'
      4         passing t.object_value
      5         columns emp_id   integer      path 'emp_id'
      6               , emp_name varchar2(30) path 'emp_name'
      7       ) x
      8  ;
                                     EMP_ID EMP_NAME
                                          1 SMITH

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