How to return from Child Page to Immediate Parent Page

Hi All,
I have created a custom OAF page and linked the same with 3 standard OAF pages(Lets say Standard-Page1, Standard-Page2, Standard-Page3) in such a way that whenever I click the GO button in any of those standard pages it navigates to my custom page.
As of now when I click the BACK button in the custom page it navigates back to Standard-page1(Because i have given the page1 Path in the pageContext.ForwardImmediately) only even though if I would have opened my custom page from standard-Page2 or 3.
I need to understand what should I do to navigate back to the exact standard page from which the custom page has been opened.
Any help on this would be greatly appreciated.
Many thanks in advance!
Kind Regards,
Myvizhi

Hi Sumit,
Thanks for your kind reply. I tried another way because we will not have that Standard AM in the Custom Page. The other way is like, getting the standard page URL into a variable and passing it as a session value and getting that session value into a variable in the Custom Page. Then passing that variable in the place of URL in the following way:
In the Standard Page passing URL variable into a session value:
String s4 = pageContext.getCurrentUrlForRedirect();
pageContext.putSessionValue("*previousPageUrlForList*", s4);
In the Custom Page getting session value into a variable and using :
String valuefromsession =(String)pageContext.getSessionValue("*previousPageUrlForList*");
pageContext.forwardImmediately(
valuefromsession,
null,OAWebBeanConstants.KEEP_MENU_CONTEXT,
null,
null,
true, // retain AM
OAWebBeanConstants.ADD_BREAD_CRUMB_NO);
Kind Regards,
Myvizhi

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Hello,
I tried to implement the solution as follow:
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-> )
-> );
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mysql>
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