How to specify the directory in which we want to store the uploaded files

Question

Hello !!
I am using apache commonfile upload for uploading my files.I followed the user guide and tried to run a program,but my problem is I am not able to understand as to how to mention the directory in which the uploaded file will be saved..My code is given below :
package r;
import javax.servlet.*;
import javax.servlet.http.*;
import java.io.*;
import java.sql.*;
import java.util.*;
import org.apache.commons.fileupload.*;
import org.apache.commons.fileupload.servlet.*;
import org.apache.commons.fileupload.disk.*;
import org.apache.commons.io.*;
import java.lang.Exception;
public class fileupload extends HttpServlet
     public void doGet(HttpServletRequest request,HttpServletResponse response)throws IOException,ServletException
               // Check that we have a file upload request
              boolean isMultipart = ServletFileUpload.isMultipartContent(request);
             System.out.println(isMultipart);
             if (ServletFileUpload.isMultipartContent(request))
             // Create a factory for disk-based file items
               FileItemFactory factory = new DiskFileItemFactory();
               // Create a new file upload handler
               ServletFileUpload upload = new ServletFileUpload(factory);
               // Parse the request
               try {
                           List items= upload.parseRequest(request);               
                         Iterator iter = items.iterator();
                         while (iter.hasNext())
                               FileItem item = (FileItem) iter.next();                    
                             if (item.isFormField()) //NORMAL FORM FIELD
                             String name = item.getFieldName();
                              String value = item.getString();
                              System.out.println(value);                                                             
                              else
                             String fileName = item.getName();
                             System.out.println(fileName);
                                String contentType = item.getContentType();
                              File saveTo = new File("/info/upload_files/myFile.jpeg");
                         try
                                   item.write(saveTo);
                                   System.out.println("File written" );                    
                         catch(Exception e)
                                     System.out.println("File not written");
                               // InputStream fs= item.getInputStream();                    
                               fileName = FilenameUtils.getName(fileName);
                                System.out.println(fileName);
                    }//end of try
          catch (Exception e) { }
     public void doPost(HttpServletRequest request,HttpServletResponse response)throws ServletException,IOException
             doGet(request,response);
The problem is that the control doesn't reach the try statement and I get " File not written" on the console because it enters catch everytime..Please tell me how the path to the directory should be given...Rest of the code is working fine

Answer 1

No, the problem is that when an Exception is thrown, you ignore it completely and throw away all the information associated with it. That leaves you to guess at what the problem is. So instead of answering your guess at a good question, I'm going to suggest that in all of your catch blocks you put this code:e.printStackTrace();Then you can look at the output in the log file and see what the problem is. Start from there.