How to update a string value located on the main VI

Hello
I would like, from a subVI, to update a string value located in the main VI (using References). I was trying to find examples on NI web page but it´s impossible to download them (for more than one month : Error, File Not Found), do everyone has got the same problem?
Thanks for your answer
Nicolas

Hi,
this is from LV help file:
Complete the following steps to create a subVI that includes a control reference directly from a Property Node.
1.On the block diagram, right-click the front panel object terminal for which you want a control reference and select Create»Property Node from the shortcut menu to create a Property Node implicitly linked to the object. You can have multiple Property Nodes for multiple front panel objects.
2.Use the Positioning tool to select the new Property Node and select Edit»Create SubVI from menu. LabVIEW automatically creates a control reference to the control on the block diagram of the main VI, creates a subVI that contains a control refnum wired to a Property Node, and wires the control reference on the main VI to the
control refnum input terminal of the new subVI.
Note: Select several Property Nodes at once to create a subVI with multiple control refnums and Property Nodes.
3.Double-click the subVI to open it. Modify the Property Node and other elements of the subVI as you do in any other VI.
4. If you want to change values of control then select "Value" property in Property node.
I've attached the examples.
Good luck.
Oleg Chutko.
Attachments:
Ref.zip ‏11 KB

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Please help me......
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Dear All,
I am new to powershell script, i was trying to store a Ad user password set date to a variable add, add a number of days to get the expire date.
but when i try to convert the variable to date value, I am getting the error as below.
Please help me......
PS C:\script> $passwordSetDate = (get-aduser user1 -properties * | select PasswordLastSet)
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7/15/2014 8:17:24 PM
PS C:\script> $a = [datetime]::ParseExact($passwordSetDate,"MM/dd/yyyy HH:MM:SS", $null)
Cannot find an overload for "ParseExact" and the argument count: "3".
At line:1 char:1
+ $a = [datetime]::ParseExact($passwordSetDate,"MM/dd/yyyy HH:MM:SS", $null)
+ ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
+ CategoryInfo : NotSpecified: (:) [], MethodException
+ FullyQualifiedErrorId : MethodCountCouldNotFindBest
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In your post you ask how to convert a string value to a date. The value returned from the Get-AdUser is already a date. It does not need to be converted.
Bill has sshown one way to convert a date to a string and there are other methods. You need to clarify your question.
If you are really trying ot convert strings to dates then you can start with this:
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Most date strings aer autodetected by the class.
¯\_(ツ)_/¯

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Hi,
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Regards
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student11 wrote: These "a" and "b" values will be automatically matched with the gas name from a list I put. For example the gas hydrogen has a value of 3 for "a" and 4 for "b".
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Update xml string values.

Hi,
I'm on 11.2.0.2 and got table with nclob column which stores long xml string .
{code}
"<?xml version="1.0" encoding="UTF-8"?>
<?fuego version="6.5.2" build="101272"?>
<set>
<configuration name="TEST Database" type="SQL" subtype="DDORACLE">
<property name="jdbc.pool.idle_timeout" value="5"/>
<property name="jdbc.pool.entry.max" value="10"/>
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<property name="user" value="user1"/>
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<property name="jdbc.pool.min" value="0"/>
<property name="jdbc.pool.maxopencursors" value="50"/>
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<property name="password" value="user101"/>
<property name="jdbc.xa" value="false"/>
<property name="jdbc.pool.max" value="10"/>
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<configuration name="TEST Database2" type="SQL" subtype="DDORACLE">
<property name="jdbc.pool.idle_timeout" value="5"/>
<property name="jdbc.pool.entry.max" value="10"/>
<property name="oracle.dateEqualsTimestamp" value="false"/>
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<property name="user" value="user2"/>
<property name="jdbc.port" value="1521"/>
<property name="jdbc.pool.min" value="0"/>
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{code}
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<property name="password" value="user201"/>   <-- that is my goal .
Regards
Greg

Hi,
You can find a few methods here : How To : Update XML nodes with values from the same document | Odie's Oracle Blog
They're not all applicable to your version and settings though.
Here's the first one applied to your case :
declare
v_xmldoc   xmltype;
begin
select xmlparse(document to_clob(t.xmldoc))
into v_xmldoc
from my_nclob_table t
where t.id = 1;
for r in (
    select idx, schema_name
    from my_nclob_table t
       , xmltable(
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           , r.schema_name || '01'
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    from dual ;
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set t.xmldoc = to_nclob(xmlserialize(document v_xmldoc indent))
where t.id = 1;
end;
Here's another one, using DOM :
declare
doc   clob;
p        dbms_xmlparser.Parser;
domdoc   dbms_xmldom.DOMDocument;
docnode dbms_xmldom.DOMNode;
conf_list      dbms_xmldom.DOMNodeList;
conf_node      dbms_xmldom.DOMNode;
password_node dbms_xmldom.DOMNode;
schema_name     varchar2(30);
password_value varchar2(256);
begin
select to_clob(xmldoc)
into doc
from my_nclob_table
where id = 1 ;
p := dbms_xmlparser.newParser;
dbms_xmlparser.parseClob(p, doc);
domdoc := dbms_xmlparser.getDocument(p);
dbms_xmlparser.freeParser(p);
docnode := dbms_xmldom.makeNode(domdoc);
conf_list := dbms_xslprocessor.selectNodes(docnode, '/set/configuration');
for i in 0 .. dbms_xmldom.getLength(conf_list) - 1 loop
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    dbms_xslprocessor.valueOf(conf_node, 'property[@name="jdbc.schema"]/@value', schema_name);
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    dbms_xmldom.setNodeValue(password_node, schema_name || '01');
end loop;
dbms_xmldom.writeToClob(domdoc, doc);
dbms_xmldom.freeDocument(domdoc);
update my_nclob_table t
set t.xmldoc = to_nclob(doc)
where t.id = 1;
end;
Message was edited by: odie_63 - added DOM example

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