How to update the R/3 tables with the target message??

Hi All:
I have one scenerio, that I am getting the data from Flat File and Mapping
it to the target structure. Now from that target message I need to update
few tables in R/3.Could any one give me a hint how I can achive it.
It is possible with proxy??
Thanks in advance.
regards,
Farooq.

Also when ever I send the e-mail you peoples are able to read it..but
I am unable to recieve the others mail in my mail box(Regarding the new blogs, forums etc). Can any one help
me on this

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How to encrypt column of some table with the single method on oracle7/814?

How to encrypt column of some table with the single method on oracle7/814?

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How to encrypt column of some table with the single method ?

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How to encrypt column of some table with the single
method ?How to encrypt column of some table with the single
method ?
using dbms_crypto package
Assumption: TE is a user in oracle 10g
we have a table need encrypt a column, this column SYSDBA can not look at, it's credit card number.
tha table is
SQL> desc TE.temp_sales
Name Null? Type
CUST_CREDIT_ID NOT NULL NUMBER
CARD_TYPE VARCHAR2(10)
CARD_NUMBER NUMBER
EXPIRY_DATE DATE
CUST_ID NUMBER
1. grant execute on dbms_crypto to te;
2. Create a table with a encrypted columns
SQL> CREATE TABLE te.customer_credit_info(
2 cust_credit_id number
3      CONSTRAINT pk_te_cust_cred PRIMARY KEY
4      USING INDEX TABLESPACE indx
5      enable validate,
6 card_type varchar2(10)
7      constraint te_cust_cred_type_chk check ( upper(card_type) in ('DINERS','AMEX','VISA','MC') ),
8 card_number blob,
9 expiry_date date,
10 cust_id number
11      constraint fk_te_cust_credit_to_cust references te.customer(cust_id) deferrable
12 )
13 storage (initial 50k next 50k pctincrease 0 minextents 1 maxextents 50)
14 tablespace userdata_Lm;
Table created.
SQL> CREATE SEQUENCE te.customers_cred_info_id
2 START WITH 1
3 INCREMENT BY 1
4 NOCACHE
5 NOCYCLE;
Sequence created.
Note: Credit card number is blob data type. It will be encrypted.
3. Loading data encrypt the credit card number
truncate table TE.customer_credit_info;
DECLARE
input_string VARCHAR2(16) := '';
raw_input RAW(128) := UTL_RAW.CAST_TO_RAW(CONVERT(input_string,'AL32UTF8','US7ASCII'));
key_string VARCHAR2(8) := 'AsDf!2#4';
raw_key RAW(128) := UTL_RAW.CAST_TO_RAW(CONVERT(key_string,'AL32UTF8','US7ASCII'));
encrypted_raw RAW(2048);
encrypted_string VARCHAR2(2048);
BEGIN
for cred_record in (select upper(CREDIT_CARD) as CREDIT_CARD,
CREDIT_CARD_EXP_DATE,
to_char(CREDIT_CARD_NUMBER) as CREDIT_CARD_NUMBER,
CUST_ID
from TE.temp_sales) loop
dbms_output.put_line('type:' || cred_record.credit_card || 'exp_date:' || cred_record.CREDIT_CARD_EXP_DATE);
dbms_output.put_line('number:' || cred_record.CREDIT_CARD_NUMBER);
input_string := cred_record.CREDIT_CARD_NUMBER;
raw_input := UTL_RAW.CAST_TO_RAW(CONVERT(input_string,'AL32UTF8','US7ASCII'));
dbms_output.put_line('> Input String: ' || CONVERT(UTL_RAW.CAST_TO_VARCHAR2(raw_input),'US7ASCII','AL32UTF8'));
encrypted_raw := dbms_crypto.Encrypt(
src => raw_input,
typ => DBMS_CRYPTO.DES_CBC_PKCS5,
key => raw_key);
encrypted_string := rawtohex(UTL_RAW.CAST_TO_RAW(encrypted_raw)) ;
dbms_output.put_line('> Encrypted hex value : ' || encrypted_string );
insert into TE.customer_credit_info values
(TE.customers_cred_info_id.nextval,
cred_record.credit_card,
encrypted_raw,
cred_record.CREDIT_CARD_EXP_DATE,
cred_record.CUST_ID);
end loop;
commit;
end;
4. Check credit card number script
DECLARE
input_string VARCHAR2(16) := '';
raw_input RAW(128) := UTL_RAW.CAST_TO_RAW(CONVERT(input_string,'AL32UTF8','US7ASCII'));
key_string VARCHAR2(8) := 'AsDf!2#4';
raw_key RAW(128) := UTL_RAW.CAST_TO_RAW(CONVERT(key_string,'AL32UTF8','US7ASCII'));
encrypted_raw RAW(2048);
encrypted_string VARCHAR2(2048);
decrypted_raw RAW(2048);
decrypted_string VARCHAR2(2048);
cursor cursor_cust_cred is select CUST_CREDIT_ID, CARD_TYPE, CARD_NUMBER, EXPIRY_DATE, CUST_ID
from TE.customer_credit_info order by CUST_CREDIT_ID;
v_id customer_credit_info.CUST_CREDIT_ID%type;
v_type customer_credit_info.CARD_TYPE%type;
v_EXPIRY_DATE customer_credit_info.EXPIRY_DATE%type;
v_CUST_ID customer_credit_info.CUST_ID%type;
BEGIN
dbms_output.put_line('ID Type Number Expiry_date cust_id');
dbms_output.put_line('-----------------------------------------------------');
open cursor_cust_cred;
loop
     fetch cursor_cust_cred into v_id, v_type, encrypted_raw, v_expiry_date, v_cust_id;
exit when cursor_cust_cred%notfound;
decrypted_raw := dbms_crypto.Decrypt(
src => encrypted_raw,
typ => DBMS_CRYPTO.DES_CBC_PKCS5,
key => raw_key);
decrypted_string := CONVERT(UTL_RAW.CAST_TO_VARCHAR2(decrypted_raw),'US7ASCII','AL32UTF8');
dbms_output.put_line(V_ID ||' ' ||
V_TYPE ||' ' ||
decrypted_string || ' ' ||
v_EXPIRY_DATE || ' ' ||
v_CUST_ID);
end loop;
close cursor_cust_cred;
commit;
end;
/

Trigger to update field on a table with the sum of fields on another table

My experience creating triggers and pl/sql in general can best be described in oracle terms as null. I've been practicing by creating tables and applications on my personal home server to help me with some of my work related tasks. Right now I'm trying to create a trigger that will, after insert, update, delete on the assignment_time_track table update the time_spent field on the assignments table with the sum of the time_spent fields on the assignment_time_track table. Hopefully that run on sentence there is clear to people other than myself. I've attempted to script this on my own using the trigger creation tool for Oracle Database Express Edition but I get the following error:
Trigger create was not successful for the following reason:
ORA-06552: PL/SQL: Compilation unit analysis terminated ORA-06553: PLS-320: the declaration of the type of this expression is incomplete or malformed
Here is my attempt at creating the trigger on my own.
create or replace trigger "ASSIGNMENT_TIME_TRACK_T1"
AFTER
insert or update or delete on "ASSIGNMENT_TIME_TRACK"
for each row
begin
update assignments
set time_spent = (select sum(time_spent)
from assignment_time_track
where assignment_time_track.name = assignments.name);
end;
If what I've posted isn't clear or more detail is needed, let me know and I'll respond with a complete description of both tables and my goals for each table. Thanks in advance for any help. I will also gladly accept links to tutorials or lessons that explain how to do this sort of thing.
Edited by: bobonthenet on Mar 9, 2009 2:01 PM

Hi,
If the assignments table has only one row per assignment, why is the primary key the combination of name and time_spent? If you have two two assignments called "Lab Report", isn't it possible that you would spend the same amount of time on each of them? I suggest using a sequence to assign an arbitrary id number to each assignment, and use that as the primary key.
What does each row in assuignment_time_track represent? It sounds like it is a chunk of time spent on one assignment (that is, you want to know that you spent 90 minutes on Tudesday morning working on some assignment, and that you spent another 30 minutes on Tuesday afternoon working on the same assignment). If so, then there should be a foreign key constraint in assignment_time_track referencing the primary key of assignemnt, and not the other way around.
Alex is right; you can get the total time spent on each project in a query or view; there is no need to replicate that data.
If you're new to Oracle and SQL, you should invest your time in getting more experience with the basics: everyday things like queries (using joins and GROUP BY) and views, and not spend much time on things that aren't used that much, like triggers.
If you really did have to copy the data, then you could have a trigger on assignemnt_time_track that kept the total in assignment up to date, like this:
UPDATE assignment
SET     total_time_spent = total_time_spent
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                         - NVL (:OLD.time_spent, 0);I suggest you name the column in assignment something different than the column in assignment_time_track, to reduce the risk of confusion. Also, since they represent different things, the same name can't be the most descripttive for each of them.
In case you're wondering about the use of NVL, above: It allows the same statement to take care of the situation when you INSERT, UPDATE or DELETE a row in assignment_time_track. That is, if you UPDATE a row in assignment_time_track, and change the time_spent from 60 to 90, then you want to add the new time (90) and subtract the old time (60) fro the total_time_spent in assignment: that is, total_time_spent would increase by 30. If you INSERT a new row into assignment_time_track with time_spent=30, you just need to add the new time_spent (30): there is nothing to subtract. But rather than write an IF statement and a second UPDATE for that situation, you can just rely on hte fact that all :OLD values are NULL iwhen INSERTing, and treat that NULL as a 0. Likewise, when DELETing, all :NEW values are NULL..

How to create an dynamic internal table with the structure of a ddic table

Hi all,
I want to fill ddic-tables (which I already created) in my abap dictionary with data out of CSV-files (which are located on the CRM-Server). The ddic tables have different amount of fields.
I started with creating a table which contains the name of the tables and the path to the matching CSV-file.
At the beginning I'm filling an internal table with part of this data (the name of the ddic-tables) - after that I am looping at this internal table.
LOOP AT lt_struc ASSIGNING <lfs_struc>.
     LOOP AT lv_itab1 INTO lv_wa1 WHERE ztab_name = <lfs_struc>.
     lv_feld = lv_wa1-zdat_name.
    ENDLOOP.
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This is not the whole code, but it's working until
SPLIT lv_rec AT ';' INTO TABLE lt_str_values.
I want to split all the data of lv_rec into an internal table which has the structure of the current ddic-table, but I didn't find out how to do give the internal table the structure of the ddic-table. In the code I used an internal tyble type string but I should be the structure of the matching tabel.
If I try to create an internal table by using a fiel symbol, I am told, that the data types are not matching.
Has anyone an idea?

Hi Mayari,
though you were successfull with
METHOD cl_alv_table_create=>create_dynamic_table
I must warn you not to use it. The reason is that the number of tables created is limited, the method uses GENERATE SUBROUTINE statement and this triggers an unwanted database commit.
If you know the DDIC structure, it is (starting with ECC6.0) much easier:
field-symbols:
<table> type standard table.
data:
lr_data type ref to data.
Create data lr_data type table of (<DDIC structure>).
assign lr_data->* to <table>.
The split code can be simplified gaining speed loosing complexity not loosing functionality.
field-symbols:<fs_s> type any.
field-symbols:<fs_t> type any.
SPLIT lv_rec AT ';' INTO table it_string.
loop at it_string assigning <fs_s>.
assign component sy-tabix of wa_string to <fs_t>.
if sy-subrc = 0.
<fs_t> = <fs_s>.
endif.
at last.
append <fs_itwa3> to <ft_itab3>.
endat.
endloop.
Though it may work as Keshav.T suggested, there is no need to do that way.
Regards,
Clemens

Just need the record from the right (many) table with the max value for the Record on the left (one) side table

SELECT
ADHOC.ATS_ESH.Entry_Num
,ADHOC.ATS_ESH.Importer
,ADHOC.ATS_ESH.Version AS [ATS_ESH Version]
,ADHOC.ATS_ESL.Version AS [ATS_ESL Version]
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ADHOC.ATS_ESH
INNER JOIN ADHOC.ATS_ESL
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I just need to see the MAXIMUM version number in the ESL table for each Entry_Num in the ESH table. ESH is the one side, ESL is the MANY side.

Do you understand what this query is doing? Did you check the blogs I pointed you to?
The query I provided gets the latest ESL version for each custom number. So, if max ESL version is higher than ESH version, it's just a coincidence. If you only want to see rows where versions do not match, just add an extra where condition, e.g.
SELECT * FROM cte WHERE Rn = 1
AND  [ATS_ESH
Version] <>  [ATS_ESL
Version]
BTW, what is the type of these version
columns and what kind of data in them? If they are character columns, sorting them in DESC order will not necessary return the latest version. Can you show some samples of the data in these two columns?
For every expert, there is an equal and opposite expert. - Becker's Law
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0msec         1V
100msec     2V
200msec     3V
300msec     4V
etc.
If I use the Express VI for building a table, I always get the date and time, but I don't need the date and the time is in the following format: HH:MMS, which is nonsensical for me as I can't differentiate within msec. Can I change the format anywhere?
Can I also save the table to a file or even to an Excelsheet? How can I do that?
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Hi Craig:
thank you very much. To solve the mystery : ) :
I want to drive a stepper motor with a specific frequency. To get the current degree value of the motor I would like to measure the current time (from the beginning of the move on). (With a formula I get the degree value out of the time)
Concurrently I would like to get data from a torque sensor and from a pressure sensor. That's why I asked you about the time and the table. The measurement should start with the movement of the motor. How can I do that? Right now I have different block diagrams (different while loops) (see attachment) and I would like to put them in one.
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I also would like to set a mark in the table when the voltage value of an analog input gets under a specific threshold value. Is that possible?
I'm sorry, I'm a novice in LabVIEW. But maybe you can help me.
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Attachments:
motor.vi ‏238 KB
sensor.vi ‏59 KB

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Update the database table with the content of the internal table

Hello!
I have the next form:
FORM erase_data.
SELECT * FROM zadrress INTO CORRESPONDING FIELDS OF TABLE itab_adrress.
DELETE TABLE itab_adrress: FROM zadrress,
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WRITE 'The information after the DELETE operation'
COLOR 2.
LOOP AT itab_adrress INTO wa_adrress .
    WRITE:/
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           wa_adrress-name COLOR 7,
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   COMMIT WORK.
   IF sy-subrc = 0.
     WRITE 'OK !'.
     SKIP.
   ELSE.
     WRITE 'FAIL !'.
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ENDLOOP.
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UPDATE zadrress FROM TABLE itab_adrress.
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ENDFORM.                    "erase_data
I see that my record is deleted when I display the records from my internal table, but
now I want to delete the record from database table.
   For that I want to move the content of the modified internal table in the database table. You can see the methods I tried (some of them commented), but nothing seems to work.
Any advice ?
Thank you.

FORM erase_data.
SELECT * FROM zadrress INTO CORRESPONDING FIELDS OF TABLE itab_adrress.
DELETE TABLE itab_adrress: FROM zadrress,
WITH TABLE KEY adrid = '456'.
WRITE 'The information after the DELETE operation'
COLOR 2.
LOOP AT itab_adrress INTO wa_adrress .
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wa_adrress-adrid COLOR 5,
wa_adrress-name COLOR 7,
wa_adrress-email COLOR 5,
wa_adrress-depart COLOR 7,
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ENDLOOP.
SKIP.
LOOP AT itab_adrress INTO wa_adrress.
MODIFY zadrress FROM wa_adrress.
COMMIT WORK.
IF sy-subrc = 0.
WRITE 'OK !'.
SKIP.
ELSE.
WRITE 'FAIL !'.
SKIP.
ENDIF.
ENDLOOP.
<b>DELETE FROM zadrress.</b> "Make this change and try
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UPDATE zadrress FROM TABLE itab_adrress.
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Scott
Message was edited by: A A P L

HT1752 I recently purchased an old iMac G3 Macintosh. I was wondering, is there a way where I can update it without using an external disc? I've seen the newer Apple products with the dock, if I update my iMac G3, will it have that, and if so, how can I d

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with reference to
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How to know the the list of tables with no rows inside a schema?
I try this select table_name from user_tables where num_rows=0;
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Check this out...
SQL> drop table t
2 /
Table dropped.
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2 as
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4 /
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T
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How can i creat CRC 32 CHECK WITH THE lookup table as attached.

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result number C++ version:
FE 00 18 02 40 1E 65 43 00 03 E8        CRC32=>78 1F E9 06
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