How to write SQL query and apply aggregate functions on it

Hello experts,
Iu2019ve a task to write SQL query on tree tables and do inner join on them. Iu2019ve accomplish this task by using T-CODE SQVI. However now I need to write a query and apply SQL functions on it i.e. Add, Count, Max and Min etc. Please can someone tell me how I can write SQL query with aggregate functions in SAP?
Thanks a lot in advance

HI Mr. Cool
you can see the below code for using aggregate functions.
where ARTIST and SEATSOCCU are the field names for which you want to perform these functions.
DATA: TOTAL_ENTRIES TYPE I,
      TOTAL_ATT TYPE I,
      MAX_ATT TYPE I,
      AVG_ATT TYPE I.
SELECT COUNT( DISTINCT ARTIST )
       SUM( SEATSOCCU )
       MAX( SEATSOCCU )
       AVG( SEATSOCCU ) FROM YCONCERT INTO (TOTAL_ENTRIES, TOTAL_ATT,
MAX_ATT, AVG_ATT).
Thanks
Lalit Gupta

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How to write sql query for counting pairs from below table??

Below is my SQL table structure.
user_id | Name | join_side | left_leg | right_leg | Parent_id
100001 Tinku Left 100002 100003 0
100002 Harish Left 100004 100005 100001
100003 Gorav Right 100006 100007 100001
100004 Prince Left 100008 NULL 100002
100005 Ajay Right NULL NULL 100002
100006 Simran Left NULL NULL 100003
100007 Raman Right NULL NULL 100003
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It is a binary table structure.. Every user has to add two per id under him, one is left_leg and second is right_leg... Parent_id is under which user current user is added.. Hope you will be understand..
I have to write sql query for counting pairs under id "100001". i know there will be important role of parent_id for counting pairs. * what is pair( suppose if any user contains both left_leg and right_leg id, then it is called pair.)
I know there are three pairs under id "100001" :-
1. 100002 and 100003
2. 100004 and 100005
3. 100006 and 100007
100008 will not be counted as pair because it does not have right leg..
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Suppose i have to count pair for id '100002'. Then there is only one pair under id '100002'. i.e 100004 and 100005

Sounds like this to me
DECLARE @ID int
SET @ID = 100001--your passed value
SELECT left_leg,right_leg
FROM table
WHERE (user_id = @ID
OR parent_id = @ID)
AND left_leg IS NOT NULL
AND right_leg IS NOT NULL
Please Mark This As Answer if it helps to solve the issue Visakh ---------------------------- http://visakhm.blogspot.com/ https://www.facebook.com/VmBlogs

How to write sql query for below mentioned eaxmple.

Hi,
I have requirement.
There are number of rows and I need the result through query as follows.Please help me to proved sql query for below mentioned requirement.
example: table TEST.
COLA COLB COLC COLD COLE COLF MANAGER 5 NULL NULL 3 NULL
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Duplicate thread. please view the answer posted in your first thread.
how to write sql query.
And, please don't post any duplicate thread.
Regards.
Satyaki De.

How to write sql query with many parameter in ireport

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How will write SQL query to fetch data from each Sub-partition..

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SELECT * FROM emp SUBPARTITION(sp1);

How to write sql query?

create table test (
company varchar2(2),
order_number number(4),
item_id number(4),
quantity number(8),
item_desc varchar2(16)
insert into test values ('A',1001,1,10,'apple');
insert into test values ('A',1001,2,20,'banana');
insert into test values ('B',1002,2,50,'banana');
insert into test values ('B',1002,1,30,'orange');
commit;
Table Test DATA
company order_number item_id quantity item_desc
1001 1 10 apple
A 10
1002 2 50 banana
1002 1 30 orange
B 80
90
how to make above result in using sql query ?
thanks !

And just so you can see....
We can also get the totals and even break down the cursors to show individual orders within each of the companys...
SQL> select * from test;
CO ORDER_NUMBER    ITEM_ID   QUANTITY ITEM_DESC
A          1001          1         10 apple
B          1002          2         50 banana
B          1002          1         30 orange
B          1003          2         40 pear
B          1003          1         70 grapefruit
SQL>
SQL> select cursor(
2 select cursor(select cursor(select item_id, quantity, item_desc
3                              from   test t4
4                              where t4.order_number = t2.order_number
5                              and    t4.company = t2.company
6                              order by item_id) order_details,
7                       order_number,
8                       (select sum(quantity)
9                        from   test t5
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11                        and    t5.order_number = t2.order_number) order_quantity_total
12                from   (select distinct company, order_number from test) t2
13                where t2.company = t.company
14                order by order_number) company_orders
15        ,RPAD(company,10,' ') company
16        ,(select sum(quantity)
17          from   test t3
18          where t3.company = t.company) company_quantity
19 from (select distinct company from test) t
20 ) company_orders,
21 (select sum(quantity) from test) as total_quantity
22 from dual;
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CURSOR STATEMENT : 1            200
CURSOR STATEMENT : 1
COMPANY_ORDERS       COMPANY    COMPANY_QUANTITY
CURSOR STATEMENT : 1 A                        10
CURSOR STATEMENT : 1
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CURSOR STATEMENT : 1         1001                   10
CURSOR STATEMENT : 1
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         1         10 apple
CURSOR STATEMENT : 1 B                       190
CURSOR STATEMENT : 1
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How to write sql query that display comma suppurated result using Group by

Hi,
I am having data like bellow ,
Above result got from joining two tables VMTAGroupClient,VMTAipNames .
Query i have written to display above result is,
select vgc.VMTAGroupId,vn.VMTAName from VMTAGroupClient vgc inner join VMTAipNames vn
on vgc.VMTAID=vn.VMTANameID group by vgc.VMTAGroupId,vn.VMTAName
using the VMTAGroupId column how to write query to display result result like,
VMTAGroupID VMTAs
1 VMTA1,VMTA3
2 VMTA2,VMTA4,VMTA5
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Satheesh,
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How to write sql query for below example.

Hi,
I have requirement.
There are number of rows and I need the result through query as follows.Please help me to proved sql query for below mentioned requirement.
example: table TEST.
COLA COLB COLC COLD
MANAGER 5 NULL null
SR.MANAGE 6 3 NULL
VP 5 5 4
I have to write the sql query if COLA IS MANAGER THEN CONSIDER MANGER RECORD,AND IF ANY COLUMN FILED IS NULL FOR MANGER THEN CONSIDER COLA IS SR.MANGER, AND IF ANY COLUMN FILED IS NULL FOR SR,MANGER THEN CONSIDER VP records.
I need output as below.
COLB COLC COLD
5(MANGER) 3(sr.manger) 5(vp)
Please provide the for above mentioned output.
Thanks

<<if COLA IS MANAGER THEN CONSIDER MANGER RECORD>>
What does this sentence means? COLA does not cnatin a single record but the number of records with diffrent values.
Regards
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How to write SQL query to flatten the hierarchy

Hi,
I have person table which has recursive hierarchy and I wish to flatten it upto 5 levels.
I am using Oracle10g and I have written following query to flatten the hierarchy
SELECT
ID,
level lvl,
REGEXP_SUBSTR (SYS_CONNECT_BY_PATH (fname||' '||lname, '/'), '[^/]+', 1, 1) AS level_1,
REGEXP_SUBSTR (SYS_CONNECT_BY_PATH (fname||' '||lname, '/'), '[^/]+', 1, 2) AS level_2,
REGEXP_SUBSTR (SYS_CONNECT_BY_PATH (fname||' '||lname, '/'), '[^/]+', 1, 3) AS level_3,
REGEXP_SUBSTR (SYS_CONNECT_BY_PATH (fname||' '||lname, '/'), '[^/]+', 1, 4) AS level_4,
REGEXP_SUBSTR (SYS_CONNECT_BY_PATH (fname||' '||lname, '/'), '[^/]+', 1, 5) AS level_5
FROM cmt_person
CONNECT BY manager_id = PRIOR id
and level<=5
The person table have more than a million records.
Here I am getting the correct output but this query is taking a lot of time to run.
I am looking at a SQL query without use of connect by to get the required output.
To recreate the issue, you can use this query in HR schema of Oracle and use Employees table.
Any help would be greatly appreciated.
Thanks,
Raghvendra

I tried to rewrite the query without using regular expression and connect by. Here is the code:
SELECT
cmt_person.id ,
cmt_person.fname as mgr1,
case when cmt_person2.manager_id=cmt_person.id then (cmt_person2.fname ) end as mgr2,
case when cmt_person3.manager_id=cmt_person2.id then (cmt_person3.fname ) end as mgr3,
case when cmt_person4.manager_id=cmt_person3.id then cmt_person4.fname end as mgr4,
case when cmt_person5.manager_id=cmt_person4.id then cmt_person5.fname end as mgr5
FROM
cmt_person,
cmt_person cmt_person2,
cmt_person cmt_person3,
cmt_person cmt_person4,
cmt_person cmt_person5
WHERE
cmt_person2.manager_id(+)=cmt_person.id and
cmt_person3.manager_id(+)=cmt_person2.id and
cmt_person4.manager_id(+)=cmt_person3.id and
cmt_person5.manager_id(+)=cmt_person4.id
order by 2,3,4
I got following output:
emplo000000000200100     Bobby     Khasha     Rahul     Rajesh
emplo000000000200099     Bobby     Khasha     Rahul     Ajay
emplo000000000200101     Bobby     Khasha     Rahul     Swati
emplo000000000200320     Bobby     Khasha     Rahul     Jinesh
emplo000000000201231     Bobby     Khasha     Test123
emplo000000000201230     Bobby     Khasha     User1_Domain
emplo000000000201227     Bobby     Khasha     User1_World
emplo000000000200104     Bobby     Khasha     Yitzik     Natalia
emplo000000000200103     Bobby     Khasha     Yitzik     Andrew
total 9 rows
But this is partially correct output. I want output like this:
emplo000000000200097          Bobby
emplo000000000200087          Bobby     Khasha
emplo000000000200102          Bobby     Khasha     Yitzik
emplo000000000200103          Bobby     Khasha     Yitzik     Andrew
emplo000000000200104          Bobby     Khasha     Yitzik      Natalia
emplo000000000201227          Bobby     Khasha     User1_World
emplo000000000201231          Bobby     Khasha     Test123
emplo000000000201230          Bobby     Khasha     User1_Domain
emplo000000000200098          Bobby     Khasha     Rahul
emplo000000000200099          Bobby     Khasha     Rahul     Ajay
emplo000000000200100          Bobby     Khasha     Rahul     Rajesh
emplo000000000200320          Bobby     Khasha     Rahul     Jinesh
emplo000000000200101          Bobby     Khasha     Rahul     Swati
total 13 rows
Do you know what I should do to get this output.
Thanks,
Raghvendra

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<?xml version="1.0" encoding="UTF-8"?>
<MaterialUpdates>
<Materials>
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</Materials>
</MaterialUpdates>
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Please find sample xml below:
<?xml version="1.0" encoding="UTF-8"?>
<MaterialUpdates>
<Materials>
     <SalesOrg>
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</Materials>
</MaterialUpdates>
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How to write a Query a table and the return result is the column name

Hi All
Pls advise how to write a query whereas the return result is the
column name.
I know there is describe <table_name>;
Is there any other ways?
Pls advise
Tj
Edited by: user600866 on Oct 14, 2008 12:13 AM

Data Dictionary table user_tab_columns has all the column names. You can query that and get what ever you want.
To get the column list of a table just query
select *
from user_tab_columns
where table_name = <your_table>Edited by: Karthick_Arp on Oct 14, 2008 12:18 AM

How to write this query ?

how to write this query ?
list the emp name who is working for the highest avg sal department.
I can use row_number over to get correct result. If we don't use this row_number function, just plain sql, how to do it ?
the row_number version is like this
select emp.* from emp ,
select deptno, row_number() over (order by avg(sal) desc) r from emp
group by deptno
)e
where e.r = 1
and emp.deptno = e.deptno

Hi,
806540 wrote:
how to write this query ?
list the emp name who is working for the highest avg sal department.
I can use row_number over to get correct result. If we don't use this row_number function, just plain sql, how to do it ?ROW_NUMBER is just plain SQL, and has been since Oracle 8.1.
ROW_NUMBER (or its close relative, RANK) is the simplest and most efficient way to solve this problem. Why not do this the right way?
the row_number version is like this
select emp.* from emp ,
select deptno, row_number() over (order by avg(sal) desc) r from emp
group by deptno
)e
where e.r = 1
and emp.deptno = e.deptno
If there happens to be a tie (that is, two or more departments have the same average sal, and it is the highest), then the query above will only arbitrarily treat one of them (no telling which one) as the highest. Change ROW_NUMBER to RANK to get all departments with a claim to having the highest average sal.
You could use the ROWNUM pseudo-column instead of ROW_NUMBER, if all you want to do is avoid ROW_NUMBER.
Without using ROW_NUMBER or RANK, there are lots of ways involving other analytic functions, such as AVG and MAX.
If you really, really don't want to use analytic functions at all, you can do this:
SELECT     *
FROM     scott.emp
WHERE     deptno     IN (
                  SELECT       deptno
                  FROM       scott.emp
                  GROUP BY deptno
                  HAVING       AVG (sal) = (
                                                   SELECT    MAX (AVG (sal))
                                           FROM          scott.emp
                                           GROUP BY deptno
;

Hi in my sql query i applied like condition (like '%TEST') but it is taking long time

Hi in my sql query i applied like condition (like '%TEST') but it is taking long time. I applied indexes also,but still i'm facing the same problem. In my databse nearly 2,00,000 records their.

Hi Manikandan
Is there a difference in performance between running the query in BEx and WebI?
have you aggregates in place on the BEx side of things?
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Gill

How to create sql query for item master with operator LIKE with variables?

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How to create sql query for item master with
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Jeyakanthan

Hi Jeyakanthan,
here is an example (put the like statement into the where field)
SELECT T0.CardCode, T0.CardName FROM OITM T0 WHERE T0.CardName Like '%%test%%'
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How does a SQL query work

Hi all...
How does a SQL query basically work? Is there any pseudocode for it?
How ro calculate the cost of query?
Can we find out what would be the execution time for a query before it is executed?
Thanks in advance.
Ameya

Hi Avinash,
Look closely mate!!!
You have done set autotrace on... meaning you are executing the statement while i am doing set autotrace traceonly explain meaning the statement would never get executed actually.. oracle optimizer will just select the desired plan and will show the output..
You can even ESTIMATE how many rows the qeury will return before even executing the statement using the same above tech.. i will show you how:
The explain plan gives this -- as long as you are using the CBO (cost based
optimizer). Doesn't matter if you have 1 or 50 tables. The last part of the
plan is the estimate output.
consider:
SQL> set autotrace traceonly explain
SQL> select e1.*, e2.* from emp e1, emp e2;
Execution Plan
0 SELECT STATEMENT Optimizer=CHOOSE (Cost=15 Card=196 Bytes=12544)
1 0 MERGE JOIN (CARTESIAN) (Cost=15 Card=196 Bytes=12544)
2 1 TABLE ACCESS (FULL) OF 'EMP' (Cost=1 Card=14 Bytes=448)
3 1 SORT (JOIN) (Cost=14 Card=14 Bytes=448)
4 3 TABLE ACCESS (FULL) OF 'EMP' (Cost=1 Card=14 Bytes=448)
196 = 14 * 14 -- thats right....
SQL> select emp.ename, mgr.ename from
2 emp, emp mgr
3 where emp.mgr = mgr.empno;
Execution Plan
0 SELECT STATEMENT Optimizer=CHOOSE (Cost=5 Card=13 Bytes=208)
1 0 MERGE JOIN (Cost=5 Card=13 Bytes=208)
2 1 SORT (JOIN) (Cost=3 Card=14 Bytes=112)
3 2 TABLE ACCESS (FULL) OF 'EMP' (Cost=1 Card=14 Bytes=112)
4 1 SORT (JOIN) (Cost=3 Card=14 Bytes=112)
5 4 TABLE ACCESS (FULL) OF 'EMP' (Cost=1 Card=14 Bytes=112)
Here is estimated that about 13 rows would be returned...
SQL> select count(*) from emp;
Execution Plan
0 SELECT STATEMENT Optimizer=CHOOSE (Cost=1 Card=1)
1 0 SORT (AGGREGATE)
2 1 INDEX (FULL SCAN) OF 'EMP_PK' (UNIQUE) (Cost=1 Card=14)
one row...
SQL> select ename, dname
2 from emp, dept where emp.deptno = dept.deptno;
Execution Plan
0 SELECT STATEMENT Optimizer=CHOOSE (Cost=5 Card=14 Bytes=252)
1 0 NESTED LOOPS (Cost=5 Card=14 Bytes=252)
2 1 TABLE ACCESS (FULL) OF 'DEPT' (Cost=1 Card=4 Bytes=44)
3 1 TABLE ACCESS (FULL) OF 'EMP' (Cost=1 Card=14 Bytes=98)
14 rows...
1 select ename, dname
2* from emp, dept where emp.deptno = dept.deptno and emp.ename like '%A%'
SQL> /
Execution Plan
0 SELECT STATEMENT Optimizer=CHOOSE (Cost=2 Card=1 Bytes=18)
1 0 NESTED LOOPS (Cost=2 Card=1 Bytes=18)
2 1 TABLE ACCESS (FULL) OF 'EMP' (Cost=1 Card=1 Bytes=7)
3 1 TABLE ACCESS (BY INDEX ROWID) OF 'DEPT' (Cost=1 Card=4 Bytes=44)
4 3 INDEX (RANGE SCAN) OF 'DEPT_IDX' (NON-UNIQUE)
1 rows.....
and this was all done without executing the query. See EXPLAIN plan and the
PLAN_TABLE.

How to write SQL query and apply aggregate functions on it

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